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Approxuitely 9 kilogtamy of theTchisCetyl eslcrs WX 1125 & WVhutc WVZX 105 Mnctal ol UuIbs Solitun bomte 45 0 Puilied wntet 87+T6De IQUIL MCC Ayabol Uup Avply [...

Question

Approxuitely 9 kilogtamy of theTchisCetyl eslcrs WX 1125 & WVhutc WVZX 105 Mnctal ol UuIbs Solitun bomte 45 0 Puilied wntet 87+T6De IQUIL MCC Ayabol Uup Avply [ tor eqiollicut cticetaHotv mnny M of putibied Wilter nrc Ikcekd JIkeLI cunt

Approxuitely 9 kilogtamy of the Tchis Cetyl eslcrs WX 1125 & WVhutc WVZX 105 Mnctal ol UuIbs Solitun bomte 45 0 Puilied wntet 87+T6De IQUIL MCC Ayabol Uup Avply [ tor eqiollicut cticeta Hotv mnny M of putibied Wilter nrc Ikcekd JIke LI cunt



Answers

The orcs of $A g$ and Cu arc concentrarct using rhcir solubiliry in (a) $\mathbf{K C N}$ (b) $11 \mathrm{NO}_{3}$ (c) $11_{2} \mathrm{SO}_{1}$ (d) $11 C l$

So here, the question is which molecule have is have english tendency to form hydrogen born. So at I as at least, and nancy to form hydrogen born, it's born has won. It is because electronic city, because of low electronic nativity is because of low electronic nativity of I only in I and its side is also large, and I eyes off. Oh, option D is correct. And option he is correct, actually has less tendency to form hydrogen more.

As we all know that dissociation constant, the association constant of water Is equal to one, multiplication 10 to the power -14. And dissociation constant of have you worked? There Is equal to 0.3, multiplication 10 to the power -14. Therefore, according to the option in this problem, option C. Age, correct them. Said of some seed, correct answer for this problem. I hope you understand the solution of this problem.

In this problem, just look at it carefully. BB I too, will react in pageants of BSE here, too. ECU was to give compound Are we change which aid 80 cl here, which it A d c L. Here? So this is white PPT. They said white PPT. Therefore, according to the option option, age, correct and said for this problem, A d c l a will be the white PPT in this problem.

In this problem, we were asked to find the center of mass of the two dimensional system with masses 2 34 to 1 in six in the positions. Negative too negative. Three 55755100 and negative 30 In order to do this, we'll need to calculate both this center of mass in the extraction, which is given by the moment of why, over the total mass and then the center of mass in the UAE direction, which is given by the moment of action over to the trouble of mass First calculating X bar, the moment of wise given by each of the masses. Times there X coordinates allotted together so we can find that by three times negative too, plus four times five plus to turn someone plus 1 10 1 zero plus six times negative three all over the total mass is going to be three plus for someone close to his nine plus one is 10. Post six gives you 16. So doing some arithmetic we get three times a year to is negative. Six plus 20 is 14 plus 14 is 28 poses zero post negative 18 is going to give you 10 over 16 or 1.6 now to find the center mass in the wind direction, we're going to find Calculate the moment of X, which is given by the masses times there y components. So we have three times negative. One negative, three plus four times fine, but two times one plus one time zero was six times zero all over the total mess, which is still 16 now doing our athletic three times three makes nines with negative nine plus 20 which is this 11 plus two gives his 13 and both of these terms to goto zeros. We get 13 over 16. So are finally answer is export y bar it wa ce 10 over 16 comma 13 over 16.


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