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Answers

Choosc rhe corrccr srarcments. 1. Gcometry of rhe coondinarion chriry can be predicred if its magnctic behaviour is known. 3. For analogous entiries within a group, $\Delta_{b}$ value follows $3 \mathrm{~d}>4 \mathrm{~d}>5 \mathrm{~d}$ 1. $\left[\mathrm{Pt}(\mathrm{CN})_{4}\right]^{2}$ ion is square planar and diamagnetic. (a) 1,2 and 3 (b) 1,2 and 4 (c) 2,3 and 4 (d) 1,3 and 4

Hello and welcome to this video solution of numerous. Here we are given a link comprehension. So here in statement one were given that and iron or a on roasting with sodium carbonate and lying in the presence of air gives to compound PNC. And you're from option the second part the solution be in concentrated. It's alan reaction with production furrows and it gives a blue color on precipitated of compound their cost solution of C. On treatment with considerate statistical gives a yellow colored compound E. And the compound even treat it with a seal gives an orange red compound F. Which is used as an ox raise anything. So you have to make certain predictions to come into the solution. So let me show you how it's made. So first of all we take for if he oh she had to poetry thus eight and a two freedom global neck And with air that is given seven or 2 good line gives you to a free two or three that's eight the name so Seattle four. That's it. It's a frustration. Next we have if we two or three reacting with concentrate sales that is given gives you who official three Last three H 2. Right now this official tree reacts with who before if he 10 6 that is protection fellow sign a great this gives you the blue solution pushing blue solution of if the four if he CN six whole trade plus 12 cases. Mm Next From three we have two any he wanted to see our well for That's 8/10 of food gives you we need to the odd 47 is the yellow color solution. Greatness in A. Two so four. That's it too. No you have in A to see our two or seven. Okay, last case here is the orange color substance of people pr two or seven that's 2010. So this is the so let us state what is A what is B. The first we have me is If you see a 23, this is a Next we have every two or 3 SCB or Yes. So this suits also be ready And in in 204 this is C. Right BNC. That is mentioned. Yes. Now this pushing blue books. Mhm. Yeah. Yeah. Whoa it is. Mhm. Okay. To see again this election with the this one your local er this is E and we have orange. What are some common? It does if Yeah. Right. I hope this is clear to you and have a very good rest of the day. Thank you.

Hi friends here it is given four identical charges are placed on the circumference of a circle after emitted to the as soon the figure we have to find the potential at center potential at the center of a week. Okay, Cuban by our one. Get you to buy art. Okay. You three by archery. Okay. Q four by our food. Uh huh. Kick you wiggy. Mhm. So it is to be four times of for cuba. Haiti hands. Answer is D. That? So thanks for much.

Yeah. Okay for this question you're looking for the coordinates of the point where the terminal side of angle theta hits the unit circle. So I put a unit circle on the page for you to look at. But we're supposed to pretty much know the the unit circle values without it. P at pi means look at the angle from zero around a pie and write down the coordinates of the point where the angle hits the unit circle. The coordinates here are negative one and 0 negative pi over two isn't labeled on the unit circle because its a negative ankle and It's measured from zero Clockwise down to the same position as three pi over two negative pirate too Hits the unit circle at 0 -1 Pi over three. Is this one up here? You get 1/2 And Route 3/2. If you don't have a unit circle already drawn I draw an X. Y. Axis, measure up from the X axis pi over three. That's the tall angle rather than the long skinny. When the tall angle is 60°. So co sign is the little value and sign is the big value. So I get one half and wrote 3/2 Negative Pi over six is right there. Route three over to a negative 1/2 three pi over four is in the second quadrant, It's a 45° reference angle. So signing co signer both route to over two and then I have to pay attention to the quadrant to decide I have excess and wise positive and negative X. Is negative here and why? Positive? So it's negative route to over two. Into over to route to over two -7 Power four. Is this way all the way around To the same one at pot as you get at Pi over four. If you're not sure where it land, take negative seven pi over four and add to pie that comes out to pi over four. So negative 75 or four pi over four code terminal. And they hit the at the unit circle at the same point that square to over two square 2/2. He at four pi is the same as two pi, which is the same as zero five pi over two minus two Pi. Is pi over two. So you get 01 5, 5 or six is right here negative 3/2 and one half. A negative four pi over three is the same as to pi over three. That's negative one half en route 3/2. Thanks for listening.

Higher. Just to go to the answer. This is the figure as mentioned in the question. We're going bringing fast charge at the zero. Okay. Energy required to bring a second charge to be. That is equal to change in potential energy. That is E B. Is equal to one by four pi epsilon zero indu Q square divided by a B. Oh that is equal to one by four. Pay absolute zero in the Q square. By To hear that is a BCE obscured by two. Here. Next is energy required to bring 30 charge at. To see that is easy. Is equal to one x 4 pay absolute zero. QA Qc. Do it by. Yes. See. Okay. Yeah. Plus one x 4 pay absolute zero hindu. QB Qc divided by busy what that is. U. C. Is equal to one by four pi epsilon zero. Yeah minus two square divided by 42. Yeah bless one x 4 pay absolute zero into mhm minus Q square divided by ruby two. Yeah that's rearranging. We get easy is equal to yeah minus. All right rooted to kill square divided by For pay absolute zero. Yeah. Mhm. Next is energy required to bring forth charge at the cube. Oh that is E. D. Is equal to one x 4. Pay Absolute zero. Yeah. Q. A cutely the word by beer. Bless. Qd Q B. Mhm divided by baby bless. Okay. Yeah Qd Qc divided by B C. My substituting value of QA QB Qc and qd by charge. Q. Big H E D. Is equal to one by four by absolute zero. Into minus he was square divided by hold off. Yeah. To a Plus -2 square root off to a plus Q square debate by do you therefore the total energy required to combos? The arrangement is equal to E plus E plus E. C plus E. D. That is E. Is equal to zero plus. Then we had a V. Be this one way For pay absolute zero Into your Squire by two years. Bless. Then next is value of easy. That is minus routed to kill square developed by For pay absolute zero. Yeah. Yeah plus Okay. Okay minus two minus routed to kill square. They will buy four Pepsi 10 plus one by for by absolute zero India Q score by to hear that is well of is equal to one by four by absolute zero window. Kill square by a hindu. One minus two rooted to. That is option is correct. This is the answer. Thank you all


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