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What does the small in the notation WThat does M| stand dor" te" epital M Me:n"' Hxou wanted t0 make need I0 mak e L; What % is this 7M solution...

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What does the small in the notation WThat does M| stand dor" te" epital M Me:n"' Hxou wanted t0 make need I0 mak e L; What % is this 7M solution ofKCI solution? (MIW 74.51 Hci What Much do you is the osmolarity of this solution? E) Describe how solution. you would make 100 mLofa [:10 dilution of the above

What does the small in the notation WThat does M| stand dor" te" epital M Me:n"' Hxou wanted t0 make need I0 mak e L; What % is this 7M solution ofKCI solution? (MIW 74.51 Hci What Much do you is the osmolarity of this solution? E) Describe how solution. you would make 100 mLofa [:10 dilution of the above



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A mathematical equation useful for dilution calculations is $M_{\text {dil }} \times V_{\text {dil }}=M_{\text {cunc }} \times V_{\text {cvac }}$. (a) What does each symbol mean, and why does the equation work? (b) Given the volume and molarity of a $\mathrm{CaCl}_{2}$ solution, how do you determine the amount (mol) and the mass (g) of solute?

This washing says that a mathematical equation useful for dilution calculations is em deluded. Times v diluted equals m concentrated times ve concentrated. Then it asks, What does each symbol mean and why does this equation work? Given the volume and polarity of a calcium chloride solution, how do you determine the amount in moles and the massive grams of solid? So let's do that first question first. What do we to these symbols mean? M stands for malaria t So right that out that is moles of Salyut per leader of solvent V is volume, which is just measured in leaders. And this equation says that the concentration or malaria, t of a solution times its volume in the diluted form is equal to the concentration in its concentrated form times the volume from its concentrated form. That's what those symbols mean. And now why does this equation work? Well, I'm going to just a race here volume to say that if we take the concentration of a solution, which is the number of most for leader and we multiply it by the volume well supplied by the volume leaders cancel and we're just left with moles. This will be equal on both sides of this equation. Even if there are different volumes on both sides. Say there was 10 milliliters on the right and 100 mill liters on the left. Those will cancel one another and we'll be left with just molds to the number of moles of Salyut is always equal in a solution if you're going to just dilute it to a different amount. So that's why this equation works the way that it does. And so for Beets has given we have the volume. So we have the volume and the polarity of a solution of calcium chloride. How do you determine the amount of moles and the mass? So I'm just gonna say we have arbitrary units. Here we are arbitrary numbers. We have, ah, one Mueller solution. And we have, uh, 100 milliliters. Okay, so one Mueller solution equals one mole, one more her leader. This is what we have. And if we simply multiply by the volume like you do on either side of this equation, I'm gonna convert mill leaders toe leaders by dividing by 1000. So you multiply this by 10000.1. Sorry. 0.1. Leaders leader units cancel. We multiply these we get 0.1 knows. So that's how you calculate the number of moles. If you're just given the concentration and some volume that asks, how do you calculate the mass in grams? You simply multiply this by the molar mass of the solvent, so grams of calcium chloride per mole of calcium chloride moles cancel and you're left with grams of calcium chloride. That's how you calculate either the moles or the grams of salt. You'd given just the concentration and volume of the solution.

So for this question, we're asked between the two solutions. Which one can we find the molar ity for? Directly up the polarity of the solution using the Moeller mats of n a C L. So if we look at the first solution, we have given 50 grams of N a C l, which is dissolved in one litre of water. Now we know to calculate similarity that is equal to the moles of any CEO divided by the total volume of the solution. No, For this moles and a seal, we can find that using the molar mass because we're given 50 grams and we can find the number of moles using by doing mass divided by molar mass. So that part is good but were given one litre of water. Now, this one leader of water is not the volume of the solution and we need the volume of the solution to calculate polarity. This one litre of water is just the volume of the solvent or one component of the solution. We don't have the volume of the total solution, so therefore we cannot calculate the polarity directly. Now for the second solution, we have 50 grams of sodium foot sodium chloride that is dissolved and enough water to make one liter of solution of That's the key here. One enough water to make one leader of solution. So again we can calculate polarity by doing, um, Sequels and over V so mulls over volume you can find the most of N a. C. L. Using moles is equal to mass over molar Mass, and we have the volume of solution in this case because it says enough water to make one leader of solutions. We have one leader of solution, and I'll just do the calculation really quick to show that So the moles will be equal to the Mass, which is 50 grams divided by the molar mass of sodium chloride, which is 58.44 grams per mole. So 50 divided by 58.4 and we'll get 0.855 approximately moles, huh? And a CEO, And we didn't find the polarity by doing that number of moles divided by R. One leader of solution. So our polarity can be found directly using the more mass to be to your 0.855 molars

Hello and welcome to this video solution of numerous. Here we are given that flew oxy mess theron C 20. Let me write down the formula C 20 age 29 F or three rate. So this is an anabolic steroid. Now a 500 ML solution is prepared by dissolving 10 ml of the steroid in water. One ml portion of the solution is diluted to a final volume of one little. You have to calculate the resultant modularity of the solution. Big. So first of all will calculate the molar mass of the solution. So molar mass of this steroid. So I am equal to 12 times of 20 plus 29. Thus 19 plus three times of 16. Great. So this gives us the Molar mass has 336 grandpa normal. Now a 500 ml solution is prepared by dissolving 10 mg of the steroid in water. Right, That means 500 ML solution will have in milligram of this, correct? Right that means one ml will have 10 x 500 milligrams telegram of this solution of this ah steroid right now you have to calculate the number of moles of this steroid raid. So we have got 10 mg. So 10 times after enter your minus three g by 500 Times of 3 36. Right, which is the molar mass. So these smalls off The steroid will present in one ml of the solution. Now this has been diluted to 1000 ml rate That is one little do we have the majority. Well to polarity equal to number of moles by the total volume. So a number of moles is already calculated as here from here itself. So, so we have caught this number of multiple, calculate this is 5.95 Times tend to the bar of -8 moles. Now this by one letter will be same right? 5.95 times 10 to the power of -8. This will be Mueller. And if you check the options, it is an option C. I hope he's scared to you and have a very good rest of the day. Thank you.

Question Number five in this section is a mole Arat e calculation. Knowing the mass of the salute and the volume of the solution to calculate molar ity, we need to convert the mass of the salute into moles of the salute and then divide by the volume of the solution in leaders. So for the first, um, compound sodium nitrate, we have 10 g. We can convert the grams of sodium nitrate into moles of sodium nitrate by dividing by its smaller mass, you can look up the molar mass so you can calculate the molar mass from the periodic table by summing up the mass of one mole of sodium, one mole of nitrogen and three moles of oxygen, and you'll get 84.995 Then, when we have the moles of sodium nitrate, which is in this numerator we divide by. The volume will get Armel Arat e 0.12 Moeller. We'll do the same thing with cadmium nitrate. Did, however, has a different Moeller mass of 236.42 g per mole. Divide the moles of cadmium by the volume of the solution and we get four to Mueller in the case of 10 g of Lead the Mueller masses 331.2 g. So we get 0.30 Moeller. So the follow up to this after calculating the morality of each solution, is which solution has the highest morality? Well, the one with the highest morality is the one that has the lowest Mueller mass. With all of the masses being the same 10 g, The one that has the highest density is going to be the one that has the most mass per leader. Well, they're all the same. So the density for all of them is going to be the same because the masks for all of this all utes are the same and the volume is all the same.


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