4

91 Magnesium reacts with hydrochloric acid to produce magnesium chloride and hydrogen gas according t0 the reaction: Mg 2 HCI MgClza) Is the equation balarced?b) Wh...

Question

91 Magnesium reacts with hydrochloric acid to produce magnesium chloride and hydrogen gas according t0 the reaction: Mg 2 HCI MgClza) Is the equation balarced?b) What volume; in of hydrogen gas at STP is generated when 8.25 & of magnesium isused?

91 Magnesium reacts with hydrochloric acid to produce magnesium chloride and hydrogen gas according t0 the reaction: Mg 2 HCI MgClz a) Is the equation balarced? b) What volume; in of hydrogen gas at STP is generated when 8.25 & of magnesium is used?



Answers

Magnesium metal reacts with hydrochloric acid to produce hydrogen gas, $\mathrm{H}_{2}$. $$ \mathrm{Mg}(s)+2 \mathrm{HCl}(a q) \longrightarrow \mathrm{MgCl}_{2}(a q)+\mathrm{H}_{2}(g) $$ Calculate the volume (in liters) of hydrogen produced at $33^{\circ} \mathrm{C}$ and $665 \mathrm{mmHg}$ from $0.0840 \mathrm{~mol} \mathrm{Mg}$ and excess $\mathrm{HCl}$.

So in this video we're gonna go over question 116 from Chapter four, which says when hydrofluoric acid reacts with magnesium metal, hydrogen gas and a quiz night museum chloride are produced. What volume of five more HCL is required to react completely with three grams of magnesium. So, Chris, let's write out the reaction, what's happening? And then we can balance it so that we know this toy geometry of the reaction. So we're told that hydrochloric acid that's HCL is reacting with my museum metal That's just mg and we're producing hydrogen gas, which is each to hydrogen, is a diet on the gas and, um, and eight Mia's magnesium chloride. So that's MG seal, too, Uh instance, since we have both a strong acid in an egg Leah's Ionic compound. I'm gonna go ahead and write this as the complete Ionic equation, so we have a TSH plus plus C l minus, plus M g yields H two plus M. G plus two. My museum takes a plus two on charge when it's an island under an ionic compound. Um, and we have our seal minus, um, so let's take each species in this complete ionic equation. And what's a sign? Oxidation states. So in hydrochloric acid, we have our protons. Those have, um, those have our plus one oxidation state. Um, so we have a plus one, Um, and then for our chloride ions, those having oxidation state of minus one and then our solid my museum metal. That's just going to have an oxidation state of zero because it's in the pure elemental form. Um, and then we have a tsh to gas again. It's the pure elements. So we have an oxidation state of zero, just hydrogen bonded to itself. Um, and then with our islands here, they're going to take the charge of the oxidation. Say it's gonna be the same as the charge. So we have plus two and minus one. So where the oxidation states changing? Well, we have a change from zero to plus two. So we're increasing our oxidation state on magnesium, which means that we're losing electrons in my museum is being oxidized. We also have a change in the oxidation state on hydrogen. From our reactions to products, we go from a plus one oxidation state to a zero oxidation state, which means that we see a gain and electrons or reduction. So let's go ahead and write out our two oxidation reduction, half reactions. So for our oxidation half reaction, we have MG Thio Energy plus two. And then for our reduction, half reaction, we have each plus T h two. So these were pretty simple to balance. So first we want to balance our atoms. So for hydrogen here we have two hydrogen atoms over here and just one hydrogen over here, some musical efficient of two in front of our age Plus which is gonna give us a coefficient of two in front of our HCL. Um and then we just need to balance charge. So my mg plus two plus two charge over here. No, not charge over here. So I need two electrons, my products and then again, a plus to charge in my reactant CE and no natural by products. I'm gonna add two electrons to my reactant And both of my half reactions have the same number of electrons. So I can just go ahead and Adlai together and, um, be balanced. A reaction is MG plus two H plus yields each too, plus M G plus two. So this is my reaction. And what did I learn from this? I learned that my hydrochloric acid is going to react in a 2 to 1 ratio with my my museum metal eso we were given that we have three grams of my museum. So let's go ahead and calculate the number of moles of magnesium that corresponds to So how many moles of my museum do we have? Well, we take the three grounds and we divide by the molar mass of magnesium, which is 24 0.305 grams per bowl. So when we divide that, we end up with 0.12 three for moles of nine museum s. So how many moles of hydrochloric acid is that going to react with? Um, so we have our 0.1234 moles of mg. And because we balanced our redox reaction, we know that for every one mole, um um, of my museum, we react with two moles of HCL, um, or age plus. So this gives us 0.2469 moles of hydrochloric acid. And then we're told that our hydrochloric acid solution is five Moeller s so now, in order to get the volume of hydrochloric acid, I'm going to take the number of moles of hydrochloric acid that I am reacting with. And I'm going to divide by the concentration. So I have 0.2469 moles, Um, and then I'm dividing by five miles per leader and this gives me 0.494 leaders or 49 point or no leaders and I only have three significant figures.

Chapter six Problem 104 asks us about the reaction between hydrochloric acid and magnesium metal and specifically to determine what volume of five molar HCL is required to react with three grams of magnesium. So let's start by reading out are balanced chemical equation here. So we're told that we have hydrochloric acid and we're reacting it with magnesium. The problem here tells us that the products are hydrogen gas and remember that hydrogen is a dye atomic molecules, so it's when it's alone will form each to. So if hydrogen gas plus magnesium chloride, that's m G. C l. And to balance out the charges that EMU seal too, because magnesium has a charge of plus two. So first, let's balance this out. We first noticed that hydrogen isn't balanced, so we need to add a to in front of HCL on with that, we see that everything is balanced here. Okay, so now the process of solving this problem, we're given the amount of magnesium, so first we can convert that promotes once we have moles of think museum will use their balanced chemical equation to determine moles of hcl. Finally, remember that polarity is moles per leader. So if we divide moles by molar ity that will give us leaders of HCL. So let's go through that process. We're starting with three grams of magnesium and we'll use the molar mass here where one mole is equivalent to 24.3 Gramps. Now we have moles of M G. Next we can multiplied by the ratio from the balanced chemical equation. One mole of M G is equivalent to two mall of hydrochloric acid. So now we have moles of HCL. We can now use molar iti to go for moles, toe leaders and our military here is five. MOL is equivalent to one leader. So if we multiply all of this through, we find that we need 0.494 leaders of HCL, which is equivalent to 49.4 millimeters

Question. Number 77 is mostly a stoy geometry problem and a unit conversion problem. We have a chemical reaction of magnesium with hydrochloric acid producing hydrogen gas and magnesium chloride. A table is provided that looks something like this, whereas the reaction proceeds from time 0 to 3 minutes. The magnesium mass goes from 6 g to 4.5 g. So this is what might be related to the rate of the reaction where you could calculate the average rate of the reaction in terms of grams of magnesium per minute. However, this is not a rate question. There is no use of the rate law in any form in this question. It then tells you that you we have no hydrogen gas at STP before the reaction begins. But then we make some hydrogen gas and you're asked to determine the amount of hydrogen gas. Well, if we look at the mass that has changed of magnesium, it goes from 6 g to 4.5 g. So in three minutes, 1.5 g of magnesium must have been consumed if 1.5 g of magnesium has been consumed. This is where the Stoke Eom a tree comes into play and the unit conversion. We can convert the grams of magnesium two moles of magnesium by dividing by the molar mass of magnesium and then convert the moles of magnesium. Two moles of hydrogen gas. Looking at the stock geometry of the balanced chemical reaction, which is one toe one and then moles hydrogen gas to leaders. Hydrogen gas at STP, recognizing that one mole of any gas at STP has a volume of 22.4 leaders. Thus, after three minutes we have produced, we would have produced 1.38 liters of hydrogen gas at STP.


Similar Solved Questions

5 answers
Suppose Youi Ineed t0 mix some 40 alcohol solution and some 20% alcohol solution to end up with 10 liters of 2856 solution How many liters of the 20 solution will you need?0 20 60 3
Suppose Youi Ineed t0 mix some 40 alcohol solution and some 20% alcohol solution to end up with 10 liters of 2856 solution How many liters of the 20 solution will you need? 0 2 0 6 0 3...
5 answers
Question 7Part ATo whal volume should you dilute 70 mL of a 12 0 M H2SO4 solution to oblain a 80 M H_SO4 solution? Express your answer using two significant figuresAZdmnLsubmitMy Answers Give Up
Question 7 Part A To whal volume should you dilute 70 mL of a 12 0 M H2SO4 solution to oblain a 80 M H_SO4 solution? Express your answer using two significant figures AZd mnL submit My Answers Give Up...
5 answers
) (20 = 4 > Tioou 9 - 50 L4,84 ~0.208/17.2 42mole Kci 92 374' 55 = 218g kci 2 . molof CaCl; 2 H,O in boiling water 152 CaCl; 2 HO in 100 Wale. The solubility limit reach this solubiliry limit, would the water Ifyou dissolved enough C Ck; 2 HO in water boil if the water was initially 20,0'C? pts) z090 4tintiot 4TtingiRamember; You need to bring jump drive for See the Light Iab.eaction
) (20 = 4 > Tioou 9 - 50 L4,84 ~0.208/17.2 42mole Kci 92 374' 55 = 218g kci 2 . mol of CaCl; 2 H,O in boiling water 152 CaCl; 2 HO in 100 Wale. The solubility limit reach this solubiliry limit, would the water Ifyou dissolved enough C Ck; 2 HO in water boil if the water was initially 20,0&#x...
5 answers
Aregression analysis is performed using data for 32 single-family homes to predict appraised value (in thousands of dollars) based on land area of the property (in acres); Xti, and age (in years), X2i, in month Use the results below to complete parts (a) and (b) below: Standard Variable Coefficient Error t Statistic p-value Intercept 397.16508 46.65841 8.51 0.0000 Area, X1 450.48931 101.85546 4.42 0.0001 Age, X2 2.15264 0.71533 3.01 0.0054
Aregression analysis is performed using data for 32 single-family homes to predict appraised value (in thousands of dollars) based on land area of the property (in acres); Xti, and age (in years), X2i, in month Use the results below to complete parts (a) and (b) below: Standard Variable Coefficient ...
5 answers
Question 5Which of the following compounds can exhibit cis-trans isomerism?[Mn(HzOJCla]"[Fe(CN)e]?-[Fe(H2OJ2(NH3l2h2+[Cr(COJs(C1O2)i2+ [Zn(CO)scij+
Question 5 Which of the following compounds can exhibit cis-trans isomerism? [Mn(HzOJCla]" [Fe(CN)e]?- [Fe(H2OJ2(NH3l2h2+ [Cr(COJs(C1O2)i2+ [Zn(CO)scij+...
5 answers
Write the contrapositive: For all heroes in the MCU, if Thanos is purple then Iron Man is red and Hulk is green:
Write the contrapositive: For all heroes in the MCU, if Thanos is purple then Iron Man is red and Hulk is green:...
4 answers
Find the area of the triangle using determinant of correct matrix (Hint: remember to do this one vertex has to be at the origin)
Find the area of the triangle using determinant of correct matrix (Hint: remember to do this one vertex has to be at the origin)...
5 answers
Binomlal Probabilin Disnibution with random IarlablX() Explain why the distnbution below satisfies te two relts fot probability dstnbutionPO) 0490 0s0 320 0 075 0065What I$ thc probabihty tat x is ! or ? or J? That Ls, find Ptobrx-I OR X-? ORX-J)
Binomlal Probabilin Disnibution with random IarlablX () Explain why the distnbution below satisfies te two relts fot probability dstnbution PO) 0490 0s0 320 0 075 0065 What I$ thc probabihty tat x is ! or ? or J? That Ls, find Ptobrx-I OR X-? ORX-J)...
1 answers
Williams \& Sons last year reported sales of $\$ 10$ million and an inventory turnover ratio of $2 .$ The company is now adopting a new inventory system. If the new system is able to reduce the firm's inventory level and increase the firm's inventory turnover ratio to 5 while maintaining the same level of sales, how much cash will be freed up?
Williams \& Sons last year reported sales of $\$ 10$ million and an inventory turnover ratio of $2 .$ The company is now adopting a new inventory system. If the new system is able to reduce the firm's inventory level and increase the firm's inventory turnover ratio to 5 while maintaini...
5 answers
Sample of # gas originally a1 25 % and 00ain DTCSSHTCIi conainer subject t0" M DICSSUTC of U.85 alm and temperalure of 15 %C The final volume of the gas(2. D) 2 3 El0.38
sample of # gas originally a1 25 % and 00ain DTCSSHTCIi conainer subject t0" M DICSSUTC of U.85 alm and temperalure of 15 %C The final volume of the gas (2. D) 2 3 El0.38...
4 answers
Ms. Saker was hired at a small business to help maximize profit; for amount of sweaters sold: The revenue and cost functions for the production of a sweater are R(x) ~x2 200x and C(x) 105x + 22, respectively, where X is the number of sweaters produced: The average profit for this company is defined by the function A(x) PC) , where P(x) is the profit function: Determine the production levels, in interval notation, that make A(x) > 50,rounded to two decimal places.
Ms. Saker was hired at a small business to help maximize profit; for amount of sweaters sold: The revenue and cost functions for the production of a sweater are R(x) ~x2 200x and C(x) 105x + 22, respectively, where X is the number of sweaters produced: The average profit for this company is defined ...
5 answers
Respondents for the pretest and the survey should be drawn from________ population(s).a similarthe samea differentthe entire population in the United States
Respondents for the pretest and the survey should be drawn from ________ population(s). a similar the same a different the entire population in the United States...
5 answers
Limiting current density as a function ofxi Agives current density distribution along the flow channel length) ~hm ~hm i(x) = n.F hm Cm,in exp =n.F. hm Cozin exp Um Um 0.08 2[m/s] 2*10 u/) i(x) = 4 [electron] x 96500 [C /electron] x 0.08 [m/s] x 8.588 [mole/m3] x i(x) = 265197 . e(-20x) [A/m?]
Limiting current density as a function ofxi Agives current density distribution along the flow channel length) ~hm ~hm i(x) = n.F hm Cm,in exp =n.F. hm Cozin exp Um Um 0.08 2[m/s] 2*10 u/) i(x) = 4 [electron] x 96500 [C /electron] x 0.08 [m/s] x 8.588 [mole/m3] x i(x) = 265197 . e(-20x) [A/m?]...
5 answers
Two strings support uniform rod as shown below. The rod is 20.Ocm long with a weight of 5.OON and is supported as shown. The rod is tilted at 25.02 from the horizontal. Tensions and angles are balanced s0 as t0 make the left string horizontal. Draw the free body diagram of the rod. Find the tension in the lelt string; Find the tension in the right string:
Two strings support uniform rod as shown below. The rod is 20.Ocm long with a weight of 5.OON and is supported as shown. The rod is tilted at 25.02 from the horizontal. Tensions and angles are balanced s0 as t0 make the left string horizontal. Draw the free body diagram of the rod. Find the tension ...
5 answers
None Or tne Jduve LutiliPick the formula that was used to compute the interval given: a) {*2(5 (-W)+2E +4 b) c) ( ~ttFC+4 d) (1 - p2) t2 [u+lae) None of the above Pick the appropriate t or 2 value used in the above interval. 1.645 b) 1.960 c) 2.228 d) 2.179 None of the above
None Or tne Jduve Lutili Pick the formula that was used to compute the interval given: a) {*2(5 (-W)+2E +4 b) c) ( ~ttFC+4 d) (1 - p2) t2 [u+la e) None of the above Pick the appropriate t or 2 value used in the above interval. 1.645 b) 1.960 c) 2.228 d) 2.179 None of the above...

-- 0.022644--