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A whire solicl imparrs a violer colour ro a hunscn tlame. On bcing heared wirh concenrrarct $\mathrm{II}_{2} \mathrm{SO}_{A}$, the solid gives violcr vapours rhar rurns starch paper blue. The salt may be (a) KI (b) $\mathrm{NaI}$ (c) $\mathrm{MgI}_{2}$ (d) $\mathrm{CaB} r_{2}$

In this problem, just look at it carefully. BB I too, will react in pageants of BSE here, too. ECU was to give compound Are we change which aid 80 cl here, which it A d c L. Here? So this is white PPT. They said white PPT. Therefore, according to the option option, age, correct and said for this problem, A d c l a will be the white PPT in this problem.

Question is which of the following is not a crime try and receive is represented by that molecules that have actually get so we can observe that he'll start strong feeling and so it will be good to have and industrial. So first option is BDCL four who minus. So it will be, it always Bs people have palladium and platinum is always so people have read so correct on duty.

Okay. This problem is asking us to perform a little conversation with the following molecule. So the following molecule they did not necessarily give it to us. They just say it is Heck sane dial Diao. Okay, so denial. As faras naming goes, we recognize the Al as corresponding to an allied we recognize die as correspondent to to Alba hides and then hexane is correspondent to six carbons. So 12345 six carbons Okay, and then Alba hides associated with each of them. I know those other hides are associate with the terminal carbons. Just because if are to put them in the middle, then they want to be technically allies. That would be considered key tones. Okay, so 123456 carpet is perfect. Okay, So if this molecule works to undergo an algal conversation with itself, then it would be an intra molecular album conversation. So what I would do is react this with sodium hydroxide or just any standard base. Good to see you, sodium hydroxide. Sodium hydroxide is going to deep. Probably most aesthetic Hodges. So most, instead of hydrogen is the one associated with the awful carbon. So right here associated with this Carbonell or right here. So to do with this carbon. Okay, these Hodgins on the seemingly awful positions are not considered to be acidic. Okay, so we don't department those, so I'm going to be probably this one, for example. Okay, So certain hydroxide reported that of the electrons onto that carbon resulting in this product in which we have, um, lone pairs on that carpet now. Okay, so those lone pairs are now going to react with my carbon on the other side. So the question is, why does it attack with this Carbonell? And the answer is because if it were to attack this Carbonell, then it would form an impossible structure. It would make. We could say that it would make a double bond, but we have the resources and the connect connectivity to make a rinse structure. Okay, so what I'm gonna do is count how many carbons away this carbonless, and it is one I always label my new people of carbon is 12 345 So this carbon would, um the nuclear folk attack of that carbonell would result in a 55 carbon compound, specifically a cyclic structure. So I make sure that all my Adams air Carbons 12345 k Good. They're all carbons. I'm gonna drive home, I five carbon compound five carbon compounds. Okay, so associated with, um, one, which will be right here. 12345 associated with carbon number one I have attached to it. My Alba. Hide right there. So here is my all the head. Okay, attached. Number two is nothing. Just Hodgins. Three. Nothing. Just evidence for nothing. Five. I have my, um, Cardia. So when this lump air attacks that carbon, the electrons move up to this auction. So I should get this Just an auction right there. Okay, Now we can proceed with my although conversation. Okay. So because I just used sodium hydroxide deep, rotate that carbon, then I get water. Water is going to add as a protein source for this negatively charged oxygen. Something important that deponent my hydroxide. Sorry, water. And I should get this in which I have my cycle. Penton, my other head and then my alcohol. Now. OK, ok, ok. So the question is, how do we proceed with this instrument left of their alittle conversation. So right now we just formed my alcohol hydroxide ion from the deportation of water. Now we have to consider what are we going to d prone eight. So don't be fooled by the seemingly, um, approximately two. This this alcohol to this all the head Because we do have one extra carbon right here. Okay. To that carbon is carbon this carpet. So this is still consider to be in a standard alba conversation. So associated with this carbon in my hydrogen, which is the awful carbon relative to this Carbonell. We have that hydrogen that is considered to be acidic. It's going to get deep pregnant by my hydroxide, moving the electrons onto that single bonds make a double bond in the process, kicking off that hydroxide. So after all that, we should get this in which we have a double bond here. And then my mother died

So first off, for all of these were gonna be starting with this compound. So I just want you to keep that in mind as we go along here. Okay? So for a we'd for 1st 3 that compound with H to give us the whiteness in a plus plus h two. And we would treat that, um then with ch three, we are, and that will give us our desire product. And for B, we're gonna start same compound, treat it with CIO cio three and purity, and that will give us styrene. Then we would treat that with rco three h and we get the desired product, which is fennel epoxy ethane. Now for C treat the molecule above with first H d o c o c a 32 with c h three to see i and second with in a beach for and they'll give us our final product, which is tart beetle. One Central Ethel, either. And lastly for deal start to product or the mark you above treated with PBR three to give us that. And then he treated with that to give us our one fennel ethane. The, um they feel


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