Going to be going over how to draw essentially uh compounds given a certain amount of information. So we're starting with compound a. We were we were told that this has the formula of c. five H. 8. We are also told is that it is not optically active and it cannot be separated into inanity murders. So the thing that stands out in terms of that description is that we are essentially limited into as to uh perhaps how we could draw this, but we're not so limited because there are multiple ways in which we can in fact um draw this particular molecule. There's actually a couple of ways. There's more than two ways. But for this video, I'm going to be showing one possibility. You may come up with your own way in which you can draw this and then further on in the video in terms of uh compound reacting with several other substances and giving us our different products like compound B compound sing compound D. Um so again if we're uh the formula of itself C five H. A suggest in and of itself that there are two sides of unsaturated in. And if you want to think about on saturation, you think you can think about on saturation as something that has less hydrogen. Right? If we know our hydrocarbon formula or hydrocarbon formula typically would be CNN and being the number of carbons, right? H. Two N. Plus two. So let's say if we um for example are given um six carbons, if we want to draw a hydrocarbon with six carbons and then the number of hydrogen is that are needed to just for that single thing to be just a single chain of Accardo carbon. Then we would put C. Six and an H two or 2. And sorry that she went to in to end plus two. So we have six here and then two times six is 12 plus 2 2014. So their formula would be C six H 14. That is completely saturated with all the hydrogen, is that it should have. But in this case, if we have, if we're going by this formula, we have C five H eight, then going by the hydrocarbon formula, we should ideally hydrocarbon with five carbons. We should have 12 hydrogen. Um So that's why I mentioned that this has 22 sides oven saturation. Right? So one possibility in which we can draw this um is that we could draw this as a pentagon or a cycle plantain. Let's go ahead and get our marker here. Let's get this ready. We can draw it like, so this again a ring. This is a ring in and of itself. Remember the rules for a saturation or drawing saturation. A double bond counts as 1° Oven saturation A ring cancers, 1° on saturation. A triple bond counts as two degrees oven saturation. So one possibility is that we have here, um a five carbon I five carbon uh ring, for example, um and we can go ahead and start putting in our double bond as well. So that's putting a cool two degrees because we make sure that there are two sites oven saturation in this compound, given the formula. And if we want to go ahead and double check our formula, make sure that our our drawing matches the formula. Let's go ahead and put compound A. We have 123455 carbons. Now, how many hydrogen are present? There's gonna be one here, three because there's two years. So 13 5, 7 and then one extra, there's going to be eight. So this drawing does in fact match our formula. So we can go ahead and start working with this one. But doesn't match the fact that it's not optically active. Well it's not optically active. This is not a Cairo. This is not a Cairo compound. So it's something that is not Cairo is not going to be optically active. And essentially it's also not going to be separate to nancy Meyers, meaning that there is there is no asymmetric carpet present. Um So for this uh so it does meet those criteria. So we can start working with this one. And then we are also told that it reacts with rooming in order to form compound be. So compound B. Let's go ahead and type this up here. We can put me here, Compound B. Is going to have the chemical formula. Or that is going to have the formula of Let's go inside here c. five H. Eight. We are. So that's a chemical, that's the formula for compound B. And if your reaction grooming Which can be br two in carbon tetrachloride to record, remember this when you have a double bond present and you have uh blooming like this and it's a die atomic bombing. Um You are going to perform a diet halogen nation or and this is where the booming is going to be uh placed across the double bond. Um We are going to be going through the mechanism in this video. But the product of this desalination or discrimination. You go ahead and draw that cycle painting a little better. It's going to look like this. Remember there are brahmins are going to be placed right across the double bond here and let me go ahead and edit this formula just a bit because I forgot here that are brought me there should be two, bro, means not just one. So C five H eight. We are too. And again, making sure that our or drawing matches the formula, we have 12345 We have five carbons. Uh we have we're supposed to have eight hydrogen, so one 2345678 eight hydrogen. Is that that satisfies it and then to bro means that's perfect. All right, so we have compound B. And then now we're also told that compound A reacts with a with hydrogen H two um with a some other type of metal catalyst in order to give us C five H 10. So that's going to be uh compound C. So let's go ahead and put H2 H two here and we can just put a palladium as our metal catalyst so that what would give that member when you have this is going to be um uh hydration reaction essentially, you're you're you're basically going to be reversing um the saturation process that was that happened on this particular molecule. You're going to be putting just like our bombing here were replaced the BR two across the double bond. We're also going to be placing this H two across the double bond, so each hydrogen is going to be placed right across the double bond. So we have our cyclops maintain once more and we can put you don't have to put this, but this is just for emphasis that are, hydrogen is replaced right across in the formula For this compound here is going to be C5H 10. It's going to count the number of hydrogen. So there's going to be to hear so 2468 10. Perfect. That's 10 hundreds. And there's five carbon. So that does match. And let's go ahead and indicate that this is compound C. Alright, Rama's done here. And lastly, we do have a formation of compound D when it reacts with compound A. Um One thing that the thing that reacts with compound A. Is hydrochloric acid. So we can put another arrow here, we can put H. C. O. So again, just like basically the other to the reactions that we've done, our HDL is going to be added across the double bond. And in this particular case it doesn't it does not matter where we place our chlorine. Um Either here at the top position or here on this other position. It does not matter in this particular case because we have a symmetric cyclo, cyclo painting. Um So we can go ahead and draw out our cycle painting, We can just go ahead and place our chlorine here. Um and we can place our hydrogen here again. It does not matter where you put your chlorine either here or here. No other place though, it's going to be added across the double bond. Um And then the formula for this, mhm Should turn out to be when it reacts, it should be C5 each. Nine xia. Yeah. And let's go ahead and count five carbons. There's one chlorine and there's 1234567 And 8. 9. Perfect. So it looks like everything does in fact match in terms of what we needed and that's going to be your product. This is going to be compound D let's go ahead and labeled as compound D. Right here And again. So this is pretty much this is one possibility. Keep in mind that I chose to start off with this particular type of compound compound in this, uh in the way that I drew it like this there, you could have drawn it as um in a linear form. You could have drawn it with two double bonds. That would have still satisfied the fact that it it has a 2° oven saturation. Um You could have drawn a a single chain with five carbons and you could have added a triple bomb, for example. Um Those are other possibilities, but I just chose to go with this one. I was one example and I just went from there.