5

Soluton of K CrOa was titrated wih AGNO , using Silver indicator electrode and S.C.E. reference electrode: Tne procuct, AgzC 0 , has 10 -2. E? 0.558 Ten potentlal a...

Question

Soluton of K CrOa was titrated wih AGNO , using Silver indicator electrode and S.C.E. reference electrode: Tne procuct, AgzC 0 , has 10 -2. E? 0.558 Ten potentlal at tne equlvalence point woulc be 0.328Hint: Use Ks? calculate [Ag+] Use Nernst equatlon Declce which form more Bv2 lable based on the pH Do not forget Nernst equation

soluton of K CrOa was titrated wih AGNO , using Silver indicator electrode and S.C.E. reference electrode: Tne procuct, AgzC 0 , has 10 -2. E? 0.558 Ten potentlal at tne equlvalence point woulc be 0.328 Hint: Use Ks? calculate [Ag+] Use Nernst equatlon Declce which form more Bv2 lable based on the pH Do not forget Nernst equation



Answers

You have a concentration cell in which the cathode has a silver electrode with 0.10$M \mathrm{Ag}^{+} .$ The anode also has a silver electrode with $\mathrm{Ag}^{+}(a q), 0.050 M \mathrm{S}_{2} \mathrm{O}_{3}^{2-},$ and $1.0 \times 10^{-3} M$ $\mathrm{Ag}\left(\mathrm{S}_{2} \mathrm{O}_{3}\right)_{2}^{3-}$ . You read the voltage to be 0.76 $\mathrm{V}$ .
a. Calculate the concentration of $\mathrm{Ag}^{+}$ at the anode.
b. Determine the value of the equilibrium constant for the formation of $\mathrm{Ag}\left(\mathrm{S}_{2} \mathrm{O}_{3}\right)_{2}^{3-}$.
$$\mathrm{Ag}^{+}(a q)+2 \mathrm{S}_{2} \mathrm{O}_{3}^{2-}(a q) \rightleftharpoons \mathrm{Ag}\left(\mathrm{S}_{2} \mathrm{O}_{3}\right)_{2}^{3-}(a q) \quad K=?$$

So here essentially we're giving information about specific reaction. Where we have the oxidation of chloride to chlorine and our other corresponding half reaction is essentially the reduction of die chromite to essentially chromium three plus. And we see that we need the falling in order for the equations to balance out. So we can multiply the first equation By a strike a metric coefficient of three in order for the number of electrons to cancel out. And now we can write our net chemical equation which we see as the following. And under standard conditions, we can determine the value of the reduction potential from a table which we find is equivalent to negative 0.03V on their nonstandard conditions. We have to use essentially user in your equation And we can see here that there is essentially six moles of electrons transferred based on the following. So this is the number of moles of electrons transferred. The reaction question is essentially the concentration of products divided by the concentration reactions on their current conditions, adjusting for strike geometric coefficients. And we see that this gives the falling and were given information that the concentration of H plus is essentially 6.0 molars. Were given that the concentration of diet chroma is 0.10 molars. The concentration of chromium is 0.10 Mueller. While the concentration of all our chlorine and chloride species are just one. So we can ignore them in our expression. And now we essentially have sufficient information to determine the cell potential. So negative zero point, there are three minus the R. T. Over n. F. Factor. And we're going to take the temperature to be 298 calvins. Then we essentially take the corresponding natural log of the numerator and the denominator. And as a result, we see that the cell potential is equivalent to about 0.087V. And this gives our final answer.

To calculate the silver concentration at the analog. For this concentration cell will use the nursed equation for the concentration cell, which is always the measured cell potential equal to the standard cell potential, which will be zero for a concentration cell minus 0.5916 divided by the molds of electrons transferred for silver one. Plus it's one log of again. It's always theano compartment, which is the lower concentration over the cathode compartment, which is the higher concentration which was given to us. Appoint one rearrangement of this equation that allows us to solve for the silver concentration, which is one point for two times 10 to the negative 14 then for Part B and asked us to determine the value of the equilibrium constant for a given chemical reaction at equilibrium. Constant for that given chemical reaction is going to be the A. G s 203 to 3 minus concentration over the silver concentration and then the file sulfate as to go three to minus squared because the stool Akiyama tree of the reaction we have a coefficient of to becomes an ex opponent will be then plug in the values that are given to us in the silver concentration that we calculated and we easily get the Caspi value. I'm sorry. Just a k value. This is not Caspi of 2.8 times 10 to the 13.

Heroin. So this is the nurse equation that were given. And so we do have to rearrange it. But I'll put the original here, so Oh, are t and the animal supply. We are too. So we do have to set G zero and rearranged secretion so we'll do that here. Okay? And this stays the same. So in the end, if we plug in the numbers from figure 32.49 a what week it is on equilibrium potential her k plus of negative 80. And then we get in the equilibrium potential her any plus of 55 0.5, that's all. You want to be accurate, Thanks.

To calculate the cell potential, we first need to determine the standard cell potential from the given lying notations for each cell. From the line notations, we can write the balanced chemical reaction, recognizing what is being reduced and what is being oxidized in line notation What is being oxidized? The a note is written first on the left. What is being reduced is written second on the right. So sl standard then is going to be what is being reduced the cathode minus the potential for what is being oxidized. And we get 765 volts. Then we'll use the Nerdist equation. SL equals SL standard which we just calculated minus 0.5916 divided by the moles of electrons that are being transferred which is to when we look at the change in oxidation states up here, mn is going to m in two plus multiplied by the log of the concentrations of the products raised to their coefficients, divided by the concentration of the reactant raised to their coefficients. And we get a cell potential of 0.785 Well, then do the same thing for the next one right out the chemical reaction, recognizing what is being oxidized and what is being reduced and then go to the table in the back of the book in order to get a little bit of help. So we know what these half reactions are. SL then will be what is being reduced, the Catholic potential minus what is being oxidized, the Anna potential, and we get 0.46 volts. Then we'll use the Nerdist equation. SL equals SL standard, which we just calculated minus 0.5916 divided by N. We could look at magnesium, which goes from zero oxidation state 22 plus. So that's two electrons, but there are three of them. So that's six multiplied by the log of the concentrations of the products raised to their coefficients, divided by the concentration of the reactant raised its coefficient to, and we get a cell potential of 0.196 volts


Similar Solved Questions

5 answers
Im MaYeY {idic ICHU} Wc ITI;4I- T 'iny if; 0th Wie ilil FxtHi'il APila#We C: JICSie (#HIii; 44rz: Ile} IVaJlanule: Matkulauiic TE FHTAK nitilWttIu{ il Wfua (ila JIAuuir MalileK uift IKIrz;We;k_HoK: (Mlfuletlcz : inti YVall fer #e: [Kpulzjient FMipKirticm "Feund TTEe decimal places needed }
Im MaYeY {idic ICHU} Wc ITI;4I- T 'iny if; 0th Wie ilil FxtHi'il APila# We C: JIC Sie (#HIii; 44rz: Ile} IVaJlanule: Matkulauiic TE FHTAK nitil WttIu{ il Wfua (ila JIAuuir MalileK uift IKIrz; We;k_ HoK: (Mlfuletlcz : inti YVall fer #e: [Kpulzjient FMipKirticm "Feund TTEe decimal pla...
5 answers
Evaluate the following iterated integral: I = f 5-3 60y4 dy) ds. Your answer can be expressed as an exact decimal expression in correct Maple syntax For example: 51/5 OR 10.2. Or for example: 25*(343) OR 675
Evaluate the following iterated integral: I = f 5-3 60y4 dy) ds. Your answer can be expressed as an exact decimal expression in correct Maple syntax For example: 51/5 OR 10.2. Or for example: 25*(343) OR 675...
5 answers
QuesticnThe area of ine region enclsed by tne functions fk)=x? and gkx)=Vx is:Not yet ansieredMarked out of 2,00Flag question36 12
Questicn The area of ine region enclsed by tne functions fk)=x? and gkx)=Vx is: Not yet ansiered Marked out of 2,00 Flag question 3 6 12...
5 answers
2[35 pts:] Solve +V, tu=e"Jy subject (0 the auxiliary = condition u(x,0) =0 for ~0<x<w ,
2[35 pts:] Solve +V, tu=e"Jy subject (0 the auxiliary = condition u(x,0) =0 for ~0<x<w ,...
5 answers
[Rclcrences] compounds expected to be more soluble acidic solution than in pure water?Which ofithe followingOHg (CH, COOJz [email protected](NO; ) OMn(CN)a
[Rclcrences] compounds expected to be more soluble acidic solution than in pure water? Which ofithe following OHg (CH, COOJz OHgBrz @Mn(NO; ) OMn(CN)a...
5 answers
Determine the inverse Laplace transform of the function belows -24s2 + s +24Clickhere_to_view the_table of Laplace_transfoms Clickhere_to_view the_table_of properties of Laplace_transformss - 2 4s2 +S + 242-
Determine the inverse Laplace transform of the function below s -2 4s2 + s +24 Clickhere_to_view the_table of Laplace_transfoms Clickhere_to_view the_table_of properties of Laplace_transforms s - 2 4s2 +S + 24 2-...
5 answers
T3 2. Evaluate the integral dx using: 1-x2 a) w substitution b) Trig substitution c) Partial fraction decomposition
t3 2. Evaluate the integral dx using: 1-x2 a) w substitution b) Trig substitution c) Partial fraction decomposition...
5 answers
The planar structure of $mathrm{BF}_{3}$ can be explain by the fact that $mathrm{BF}_{3}$ is(a) sp hybridized(b) sp $^{2}$ hybridized(c) sp $^{3}$ hybridized(d) sp $^{3}$ hybridized
The planar structure of $mathrm{BF}_{3}$ can be explain by the fact that $mathrm{BF}_{3}$ is (a) sp hybridized (b) sp $^{2}$ hybridized (c) sp $^{3}$ hybridized (d) sp $^{3}$ hybridized...
5 answers
H(xy) Find allthe 2 + 8y + second-order partial derivatives of the following function
h(xy) Find allthe 2 + 8y + second-order partial derivatives of the following function...
5 answers
Are there any circumstances where the intentional introduction of an exotic species can be considered a good thing because it enhances biodiversity?
Are there any circumstances where the intentional introduction of an exotic species can be considered a good thing because it enhances biodiversity?...
5 answers
CHECKING SOLUTIONS OF EQUATIONS. Check to see if the given value of the variable is or is not a solution of the equation.$$5+x^{2}=17 ; x=3$$
CHECKING SOLUTIONS OF EQUATIONS. Check to see if the given value of the variable is or is not a solution of the equation. $$ 5+x^{2}=17 ; x=3 $$...
5 answers
2. When someone says, “energy is stored in bonds”, what do theymean? Or rather, why is this confusing and how could you state thisidea more clearly?
2. When someone says, “energy is stored in bonds”, what do they mean? Or rather, why is this confusing and how could you state this idea more clearly?...
5 answers
Problem 3_Multiply polynomials (EB)16 and (A9)16 in GF(28) efficiently:
Problem 3_ Multiply polynomials (EB)16 and (A9)16 in GF(28) efficiently:...
5 answers
Let E = {Vi. Vz. V3 and F = {WI, Wz. W3 be two ordered bases for R3 with "-H--[--[JW['[H--N--[4 If the Transition Matrix from E to F isthen find the elements of the transition matrix.fisChoose _Choose _h is Choose _iisChoose _b is Choose _9 is Choose _
Let E = {Vi. Vz. V3 and F = {WI, Wz. W3 be two ordered bases for R3 with "-H--[--[J W[ '[H--N--[4 If the Transition Matrix from E to F is then find the elements of the transition matrix. fis Choose _ Choose _ h is Choose _ iis Choose _ b is Choose _ 9 is Choose _...
5 answers
Sob Sraphithe solutions toylxm
Sob Sraphithe solutions toyl xm...
5 answers
For the following function { find the antiderivative F that salisfies the given condition . flu) = 82" _ 2 F(O) = 6 he antiderivative that satisfies the given condition is Fu) =
For the following function { find the antiderivative F that salisfies the given condition . flu) = 82" _ 2 F(O) = 6 he antiderivative that satisfies the given condition is Fu) =...

-- 0.020239--