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Use the diagram below to answer question20 m/s3.0 m/sinto three identical pieces that cause the toy to come apart Predict the direction travelled by the third A toy...

Question

Use the diagram below to answer question20 m/s3.0 m/sinto three identical pieces that cause the toy to come apart Predict the direction travelled by the third A toy contains three different springs in the diagram: that all move along the floor as shown piece of the toy:749 S ofE B. 870 W ofN 139 NofW 870 N ofE

Use the diagram below to answer question 20 m/s 3.0 m/s into three identical pieces that cause the toy to come apart Predict the direction travelled by the third A toy contains three different springs in the diagram: that all move along the floor as shown piece of the toy: 749 S ofE B. 870 W ofN 139 NofW 870 N ofE



Answers

In the figure below, $\triangle \mathrm{CHI} \cong \triangle \mathrm{MES}, \mathrm{CI}=$ $2 x+3,$ and $\mathrm{MS}=30-x .$ Also, $\angle \mathrm{H}=$ $(36-5 y)^{\circ}$ and $\angle \mathrm{E}=(3 y+148)^{\circ}$. (FIGURE CAN'T COPY). Find MS.

Now wait is mg that is acting downward. So that's look at here. So this is the free body diagram. The on the force acting on the bodies MGI, that is downward and there are no other force. And this is prepared ignoring here resistance. However, on the way up, the velocities upward and the acceleration is downward at the top, the velocity equals zero and the accident issues downward on the way down the velocities downward and the acceleration is downward. Acceleration is the same in all the cases.

Alright, so here we have some toy which I've just drawn as a block. It's sliding along with a value of negative 0.4 m per second in the X direction. It's mass combined. And I just had into the three parts together to get a massive 1.3 kg and then at some point it springs apart and all three parts go their separate ways. Now on the table, we're told that the mass of that the section B and section C each are going to have a positive velocity, which means that they're going to change direction from the initial uh the initial motion of the toy. And we need to figure out what the velocity of the third section section A is going to be. And so this is just a conservation of momentum where we have an explosion happening and we need to use our momentum equation to figure out something about one part of that explosion. So the initial momentum is the total mass times the initial velocity and the final momentum's are. If we add them together, they need to equally same value. So the initial momentum that we get is -0.52 kilogram meters per second. And the momentum for or so we've got the mass of A. Times velocity of A plus massive B, times velocity B plus massive C, times velocity of C. And what we really want is to add this. So we're going to subtract these from both sides. So we're going to have mass times velocity, total mass times initial velocity minus massive, be velocity B minus massive C, velocity C. And that's going to equal massive A velocity A. And then divide both sides by massive A. To get the velocity of A. So if we plug our values in here, we're gonna get 1.3 times minus 0.4. So that's this value right here minus .6 times point to -10 times .3. Do that calculation and then divide the whole thing by .5. And you should get a value of negative 1.4 m/s. So of the three pieces only piece A. Is continuing in the same direction. So Peace A speeds up an additional meters per second. Well, pieces B and C. Get shoved backwards.

So particles going around this track, everyone to get its speed of BC and then the height at the turning point. Somebody take a minute to draw this out, feel Frida past four or just chill out while I slowly draw this. Okay, who's one hump it? 3.8 another at 2.6 and what else is going on? Austin in the reach of the bottom at 1.3. No, just use my creative license to make this a little longer than it is in the figure. You know, we want to figure out. So this was be think B and C. Now we want to get the speed and B and C and the turning point. So let's get this B and add be so it's gonna be a So there's no, uh, it's frictionless, So there's no non conservative forces acting or something. It's just gravity. That's acting, which is Conservatives weaken say energy is conserved so we can say the energy at a equals the energy at B. What we can really say. It's equal to the energy. It a equals energy. B equals energy at all points, but this is going to be useful for us cause we know something about the energy at a We know what that rest. Hey, Ray, just double checking starts that rest. Great. So, um, we know that here is no springs or anything this problem. So if we just have gravitational potential, So let's just use, um let's say that this is height equals zero just on the bottom. We could make height equal zero here. Um, but I'm just gonna go with the more intuitive idea, in my opinion. Um, just so I can use all these labels, so that's gonna be mg attempts of high today, and then we with the energy at B, so I'd be there is still potential rate. There's it's not at ground level. So some g should be, but, um, doesn't have quite as much potential energy, So someone's gonna be converted into kinetic energy, So that's RV. So now if we just algebraic Lee solved for V one. Nice thing is that the masses all cancel and then we could be is a square root of two g, um, times h A minus. H b. And so there's a che 3.8. This is HB. It's to be totally clear. I'm gonna label those barely have enough room and I'm gonna plug out into a calculator. So see, the difference between A and B is 1.2. So then that's gonna be for the does most shut up. Does most 9.81 your type type tonight, one times 1.2 and then I get 4.5 meters per second. Seems somewhat reasonable. And I love to double check numbers. So I'm just gonna go ahead and track that it's 3.8 in 2.6. Yep, So that difference is 1.2 wonderful. And that's what I plugged into my calculator. Great. Um, so there's a There's be absolutely cord enough A Put it in a little bubble. This doesn't look too messy, but the end. So now we want to find the energy, the speed at sea so we can use the same approach. We could just say, you know, a equals yet see, and again we could have used E b. But we all we know from here that's equality. A. So when I use this with a little simpler and then EA is gonna MGH a and then he had C is equal to, uh, again m g you should see plus 1/2 MV squared, and then this is gonna be in V etc. So let's just like note that this was a B says be it c squared. And then again, we could just soft algebraic Lee previous. See, that's unequal sign with a little tail. So that's gonna be to g times the height difference between a see now that height difference is 2.5. So to g time, not 1.2. But if you play so then we get seven point. Oh, oops. Just ignore this, um, all a race it just to avoid confusion meters per second. You know, we want to know its turnaround point. Well, it's gonna turn around when it has no more kinetic energy. And so we know that. But if you wish side this kinetic energy equal to zero, we know that that is gonna just have to reach the height of a So it's gonna so for C. So it's really simple. It's just going to go up to three point aid meters, just a track that that's what they're asking for. So it's gonna be kind of like right in my diagram it maybe a month to draw all this right? Here's the turn around point. Of course, if you have imagine someone escape park.

All right in the first one, we're starting with a velocity vector like this and then the velocity vector gets shorter and then the velocity vector goes to zero. And so the acceleration is decelerating, so the acceleration would be in the negative direction, so the arrow would be arrow five B. Um So it's going this way and then it's going slower in that direction and then it stops so it's accelerating to the right, decelerating to the left is the same as accelerating to the right. So the arrow for acceleration would be that one, see its velocity is this way, but then it changes and its velocity goes to this way and then it changes and its velocity goes that's not a very good drawing because this way Okay, so the change in velocity would be V two minus V one. So V two, let's say that this is B one and this is V two. V two minus V one would be this. And so the acceleration is like that V three minus V two would be like this. So again, whoops, I should have drawn that in green. So again, the acceleration is this way. So the best answer would be the downward one, which is number seven. Thank you for watching.


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