5

Tkna the eq Uatn Jhe pe peni Cuularz biseeCor Jue kne Rea mext dolvtivv Fhe peswtx ACL,4 )8.d8659)...

Question

Tkna the eq Uatn Jhe pe peni Cuularz biseeCor Jue kne Rea mext dolvtivv Fhe peswtx ACL,4 )8.d8659)

Tkna the eq Uatn Jhe pe peni Cuularz biseeCor Jue kne Rea mext dolvtivv Fhe peswtx ACL,4 )8.d8659)



Answers

Solve the given problems. By completing the steps indicated before Eq. (30.16) in the text, complete the derivation of Eq. (30.16)

Today, we're gonna be looking at the differential equation X of tea minus why Prime prime of T equals T plus one and ex Prime A T plus. Why? Prime of tea minus two. Why equals activity? We're gonna be trying to solve this system of, uh as equations. Now, the trick to different you know, these equations is to first differentiate this equation by t We obtained that ex prime a T minus. Why? Triple prime of tea equals one in particular. Explore. I'm a t is equal to one. Plus, why trouble prime empty. And we can plug this into this equation to obtain one plus triple prime of tea. Plus why prime of T minus two. Why equals e to the T or reorganizing? What? Crime? Crime. That's why prime minus two, why equals B to the T minus one. Now, this equation can be solved by standard techniques using the method of undetermined coefficients. We're gonna write l as D cubed plus D uh, minus two so that our equation is l y equals u to the T minus one. Now this factors into D minus one times D plus one over two square plus seven over four. Now the e to the T term is annihilated by D minus one. So if we're gonna find a particular solution y zero such that l Y zero is equal to e to the t Then the method of undetermined coefficients tells is that wise there is equal to a t eat the tea for some constant A. The reason this extra T term appears is because d minus one IQ accuse here and also occurs here. Now if we plug er l y zero back into the original differential equation, then we obtain, um, this is equal to four a eats the tea and that for a is equal to whenever. Four. Uh, next, we're gonna be solving the part of the problem. L Why one equals negative one now l won. The constant is annihilated by a single differential operator, which doesn't occur in the original equation. Therefore, why one must be equal to a constant. And if we plug this constant back into the equation, then we obtain that this is gonna be equal toe negative too, eh? Must be negative. One toe a must equal one over to two. Putting everything together. Um uh putting everything together. We note that ah, the general solution must be given by one of the two plus t e to the t of a four, plus the general solution to the equation with a general session G to the equation algae equal to zero using the factory ization. Here we obtain that G must be equal to a times a constant U to the T plus B e to the negative t of it too, cause route seven over four T plus C B to the negative to sign Route seven over four tea and putting this term here completes the solution. Uh, just to go over this more slowly, the e to the T term comes from this part of the factory ization of the differential operator, whereas to each the negative t ever to times coastal sign of Route seven over fourty comes from the factor D plus one over two squared plus seven over four dea one over to term is where we get the E to the negative t over to and the coastal sign Route seven over four comes from taking the square root of this term here

In this video, we're gonna go through the solution. Thio question first to chapter 5.4. We asked to find just the form off the particular solution to the following different equation. You know, I still actually find what the secret solution is. Well, they're just full of it. So first we look at the genius part and it would help if we write this in a slightly different way by taking out a factor off e to the two tea that leaves us with one last ti course. See square. So now we have a on exponential part on a polynomial part, as that motivates a form, uh, follows. So we want a an exponential part with and to t because we already have the bot in the in her in her genie genius term. And we want a general second order polynomial. So a one cause eight Sorry. 88 0 was a one Time T plus hey to times t squared. There's nobody going any higher order in porno Meo because all those trophies zero and one final thing we need to track is the roots of the auxiliary equation. Because if the roots, if it is a room off, too. And that will mean that we need to change the form somewhat. So the exhibit equation is R squared minus one equal to zero, which has solutions are equals plus a minus war, neither of which are equal to two. So therefore we're happy with this form for ah particular.

In this problem, I'm writing the reaction. Just look at it carefully. See us afford Plus to K C N will react to give, get to and so forth. Plus see you CN two to see you. CN two will react to give to see you CNN plus CNN too. Finally see you CNN Plus today K C N will react to give jittery. See you CN food. So the answer for this problem is option B. Option B. It correct answer.

So according to the latin naming system, a metal catan, a metal catan with low charge with the lower charge I am is named with the suffix or US and iron with the higher charge is named with the Suffolk. I see. So starting with option A we have kubrick c u p e r I see because Because the charge here is Plus two, which is a high charge. Now now we have iron with two positive, it is paris. I am. So in in the case of iron, the plus two is actually a low charge because iron also goes to plus three options. See we have Stannis, I am or Cindy, we have limbic I am.


Similar Solved Questions

5 answers
A) What arc the moles of an unknown diatomic gas that occupies volume of 3.7 L at a pressure of 1.5 atm and 0 "Cb) If you have 6.9 grams of the unknown diatomic gas and using the moles You obtained from a), wha would be the molar mass of the gas? Identify the gas.
a) What arc the moles of an unknown diatomic gas that occupies volume of 3.7 L at a pressure of 1.5 atm and 0 "C b) If you have 6.9 grams of the unknown diatomic gas and using the moles You obtained from a), wha would be the molar mass of the gas? Identify the gas....
5 answers
18. Find the open intervals where the function f(x) =9x is concave upldown6x2 + 9x - 8, Find the absolute MAXIMUM; if it exists _ as well as all values 19. Given f(x) = of X where It occurs on Ihe domain [2,5] #'(x) Sx2 .|2x+9
18. Find the open intervals where the function f(x) = 9x is concave upldown 6x2 + 9x - 8, Find the absolute MAXIMUM; if it exists _ as well as all values 19. Given f(x) = of X where It occurs on Ihe domain [2,5] #'(x) Sx2 .|2x+9...
5 answers
(C) Complete the Road Map by providing the missing reagents for each step above (or beside) the arrow and the missing products/intermediate products in the boxes_TBSOTBSOTBSO .Ihen H,o OhTBSO ,,TBSO'product ol and (CinJ
(C) Complete the Road Map by providing the missing reagents for each step above (or beside) the arrow and the missing products/intermediate products in the boxes_ TBSO TBSO TBSO . Ihen H,o Oh TBSO ,, TBSO' product ol and ( CinJ...
5 answers
How long will it take S1013.00 to accumulate to S1143.00 at 6% pa. compounded semi-annually? State your answer in years and months (from to 11 months):The investment will takeyear(s) andmonth(s) to mature
How long will it take S1013.00 to accumulate to S1143.00 at 6% pa. compounded semi-annually? State your answer in years and months (from to 11 months): The investment will take year(s) and month(s) to mature...
5 answers
Dcoie:0 Oi| pt28 of 7727.6.7Find the derivative of the given function. y=7et ( e 3t e t)dy dtl
Dcoie:0 Oi| pt 28 of 77 27.6.7 Find the derivative of the given function. y=7et ( e 3t e t) dy dtl...
5 answers
4 1 1 1 1 L IU 1 3338238 3383 83333483338 88992,03330049 32853
4 1 1 1 1 L IU 1 3338238 3383 83333483338 88992,03330049 32853...
5 answers
Acetone (left) and isopropyl alcohol (right) are shown below: Acetone has a vapor pressure of 10 mm Hg at -31 *C, while isopropyl alcohol has a vapor pressure of 10 mm Hg at 2.4 "C This observation can be attributed to:OHCH HaC CHgHaC -London dispersion forcesdipole-dipole interactionshydrogen bondingthe Heisenberg Uncertainty PrincipleCHg
Acetone (left) and isopropyl alcohol (right) are shown below: Acetone has a vapor pressure of 10 mm Hg at -31 *C, while isopropyl alcohol has a vapor pressure of 10 mm Hg at 2.4 "C This observation can be attributed to: OH CH HaC CHg HaC - London dispersion forces dipole-dipole interactions hy...
5 answers
Rework problem 3 from section 3.1 of your textbook, aboutevents A and B of a sample space S, butassume that Pr[A′]=0.35, Pr[B]=0.4,and Pr[A′∩B]=0.15.Find the probabilities of the following events:(1) Pr[A∩B]=(2) Pr[A∪B]=(3) Pr[A′∪B]=
Rework problem 3 from section 3.1 of your textbook, about events A and B of a sample space S, but assume that Pr[A′]=0.35, Pr[B]=0.4, and Pr[A′∩B]=0.15. Find the probabilities of the following events: (1) Pr[A∩B]= (2) Pr[A∪B]= (3) Pr[A′∪B]=...
5 answers
The half life of a first order reaction, A → 2B,is twenty seconds. How many milligrams would remain after a 2.0 gsample reacted for one minute?
The half life of a first order reaction, A → 2B, is twenty seconds. How many milligrams would remain after a 2.0 g sample reacted for one minute?...
5 answers
HowHow many MOLES CRAMS of Qluorine of nitr picscnETImoles.
How How many MOLES CRAMS of Qluorine of nitr picscn ETI moles....
5 answers
Trigonometric functlons of 0 satlsfylng the glven conditlons Find the exact values of the remaining cos 0 tan 0 < 0sin 0 =tan 8 =csc 8sec 0cot 0 =
trigonometric functlons of 0 satlsfylng the glven conditlons Find the exact values of the remaining cos 0 tan 0 < 0 sin 0 = tan 8 = csc 8 sec 0 cot 0 =...
2 answers
The National Football League (NFL) polls fans to develop arating for each football game. Each game is rated on a scale from 0(forgettable) to 100 (memorable). The fan ratings for a randomsample of 12 games follow. 58 62 85 73 72 73 20 56 80 79 84 74a. Develop a point estimate of mean fan rating for thepopulation of NFL games (to 2 decimals). b. Develop a point estimate of the standard deviation forthe population of NFL games (to 4 decimals).
The National Football League (NFL) polls fans to develop a rating for each football game. Each game is rated on a scale from 0 (forgettable) to 100 (memorable). The fan ratings for a random sample of 12 games follow. 58 62 85 73 72 73 20 56 80 79 84 74 a. Develop a point estimate of mean fan rating ...
5 answers
Calculating equilibrium concentrations when the net reaction proceeds in reverse Consider mixture C , which will cause the net reaction to proceed in reverse_net [XI 0.300Concentration (M) [XY MY initial: 0.200 0.300 change: FI equilibrium: 0.200 + I 0.300 0.300 The change in concentration positive for the reactants because they are produced and negative for the products because they are consumed_
Calculating equilibrium concentrations when the net reaction proceeds in reverse Consider mixture C , which will cause the net reaction to proceed in reverse_ net [XI 0.300 Concentration (M) [XY MY initial: 0.200 0.300 change: FI equilibrium: 0.200 + I 0.300 0.300 The change in concentration positiv...
5 answers
1516 F=x Yty10 7
15 16 F=x Yty 1 0 7...
5 answers
FvammteS+iver3 4 +
Fvammte S+ iver 3 4 +...
5 answers
As pure molecular solids, which of the following generic compounds exhibit only induced dipole/induced dipole forces: A B, € ?-Xei;
As pure molecular solids, which of the following generic compounds exhibit only induced dipole/induced dipole forces: A B, € ? -Xei;...

-- 0.070035--