Here. Although the multitudes were given, We have to find the orbital radio so we can say that our sub a would be equal to 6370 kilometers above the surface, plus the radius of the earth, 6370 kilometers. And this is equaling 272,000 another 12,740 kilometers. We can then say our sub B, this was going to be equal to 19,110 kilometers plus 6370 kilometers. This would give us 25,000 480 kilometers. Now, at this 0.4 party, we confined the ratios of potential energies. You sub be divided by use of A. This is giving us negative g times am times and divided by our sub B divided by negative G Time's and time's M spotted by our sub A and essentially all of these cancel out and this is equaling the radius of a divided by the radius of be that we had just calculated. We don't even need to change it into meters because of the units are also gonna count are also going to Ah, cancel out. And essentially, we have 1207 Sorry, 12,740 divided by 25,480 this is essentially one over two. So this would be the ratio of the potential energies. Four part B. We know that we're going to be using Equation 13 28 13 38 rather, And we can then say that the ratios of kinetic energies would be equal to the gravitational, constant times the mass of the essentially this Matthew Satellite times the mass of the Earth. There are two by two times the orbital radio of satellite be divided by got gravitational, constant times the mass of the satellite mass of the earth divided by two times the orbital radio of satellite A. And so again, this is gonna be equal to the radius. The orbital rate radius of satellite aid. About about orbital radius of satellite B, this is equal in again one over two. This would be our answer for part B from essentially from equation 13 40 for part C. We know that here it's gonna be clear that the satellite with the largest valley of our has the smallest value of absolute absolute rather the smallest value of the magnitude of the total energy. And since the values of energy are negative in this case, we can then say that the smallest value of E corresponds to the largest energy E, where we can say smallest value of the absolute value of B, uh, corresponds, essentially largest energy. Yeah, So we can say here, satellite be has being largest energy. And again, this is because essentially both of the both of the values, the values of the of the energy are negative. So the smallest value of the absolute value of the energy would equal the largest energy value. Um, the largest true energy value. So here satellite be had the largest energy and then for part D, we confined the difference. The change in the energy would be equal to the energy subete minus the energy. So a and this is gonna be equal to negative G times sometimes am to fight it by two multiplied by one over our sabian minus won over our sub A and again, uh, remember to convert these two meters. So now when we calculated the change in energy. These have to be converted two meters and not kilometers. So we find that the change in energy is that gonna be equal to 1.1 times 10 to the eighth. Jules, this would be our final answer for a party. That is the end of the solution. Thank you for watching.