5

11. Which structure best matches the IR spectra shown below.LtrnumhtrNHzNHz...

Question

11. Which structure best matches the IR spectra shown below.LtrnumhtrNHzNHz

11. Which structure best matches the IR spectra shown below. Ltrnumhtr NHz NHz



Answers

How would each of the following pairs of compounds differ in their IR spectra?

For structure A. We can tell from the IR spectrum that there is a carbon steel group And the mass spectrum tells us at the molecular weight or molar masses 1 14. So, if we take those two factors into account, we can infer that the Molecular Formula is C seven, age 14. When we look at the NMR spectrum, we see the signal that's characteristic of a proposal group. So Oprah Poll has three signals in it. So that implies that there's a symmetry involved, perhaps to equivalent proposal groups. So the structure that make sense of all of that would be for hep to known or Hempton four own where the key tone is in the middle of a seven carbon chain, and the two sides are symmetrical in terms of the hydrogen is in carbons. And their arrangement for structure be The mass spectrum gives a molar mass of 154 g per mole. But we can also tell that there's a chlorine in the structure. And we can tell that because the M. peak at 154 is about three times bigger than the peak had. Uh the M plus to peak at 1 56. So 3-1 ratio is characteristic of chlorine. So based on that mass, we have two possible formulas C nine H 11 cl Or C887 Cielo. When we look at the ir spectrum, we see a signal around 1700 that corresponds with a carbon eel group. So that leads us to Use the Formula C887 Cielo. From the NMR spectrum, we can tell that there is a mono substituted aromatic grain and there's also a highly D shielded CH two groups. So the best way to combine those pieces together would be in a structure that has a mono substituted benzene Bonded to a ketone bonded to a CH two cl group.

This is the answer to chapter 20 to problem number seven from the Smith Organic Chemistry textbook. Ah, and this problem asks us, how would the compounds in each pair differ in their i r spectra? Okay. S o for a, um we are comparing. And Esther to a name. I ah. And so, for a name, I'd We're gonna expect the carbon double bond oxygen peak to be at a lower wave number on, and so that would be the major difference there. The carbon double bon oxygen peak is going to be at a lower wave number. Uh, Okay, so for B, we're comparing a six member lack tone to a five member black tune. Ah, and so the smaller ring eyes gonna have, uh, the carbon oxygen double bond at a higher wave number. Okay. For sea, we are comparing a secondary. Am I to a primary a mind. Ah. And so the secondary a mite is gonna have only one n h peak. Um, whereas wth e, uh, primary A mine is going to have to n h peaks. And we will see distinctly that there are two peaks there as opposed to a one. So That would be how how we could distinguish between the two of them. Um, And so for D we are comparing in anhydride to an S Koran. Let me move this up a little bit. Oh, this behind. All right, So there were ghosts or comparing anhydride too. And ask chloride. Ah. And so for the anhydride, we would expect to see to, uh, carbon oxygen double bond peaks. Ah, and obviously, for the acid chloride, we would only expect to see one. Okay, Uh, so that would be the differences between each pair in these four pairs, and that is the answer to chapter 20 to problem number seven.

So absorption is 824,720 suggests we have all the hide. 3000 absorption suggests we have hydrogen attached to SP three rods and SP to hybridize carbon. So therefore, from this analysis, we may determine to have two missile butor are behind which is drawn just below moving on to our second example here we have broadband at 3300 corresponding to an n H group. This is confirmed by the 1600 absorption. Secondly, there is an absorption at 1280 which is a me throw. Therefore we may have pro pro No a might present Well, we have that a might functional group moving on to our last example Here we have an absorption absence at 1600 meaning that there is no benzene ring. We don't have any meats are groups either are suggested by the absorption at 1380. Strong absorption at 1700 though, indicates the presence of a key tone. So our structure may in fact be set cloak Ito. Where are key tone is a carbon I'll that has to armed groups where neither off the ah group or protein protons on. We have six members Cyclical ring will the single bonds

Of a few different oxygen containing compounds. Okay. So first starting off on the left here, what we're going to do is we're gonna move down each one and see how they would differ. There I are as well as the H NMR. Okay let's maybe move back down so we have space. Okay. We'll start off with the I. R. Okay. Which is you know the infrared. Thanks. So if you start at the most left here with this cycle of magazine at the mouth, what we'll see here is we have an alcohol. Okay, so we know alcohol's will appear, the O. H. Stretch will appear and around 3000 wavelength and they'll be very broad and intense. Okay so that will that will be the biggest signal here in this compound. Yeah. There's also going to be we know we have sp three hybridized carbons here. So we'll see that signal atZ 3000 from 3002 two. I was in 850 wavelengths. And that will be um you know, just a not broad, like a thin a sinner peak. And that's where the sp three carbons. Okay, so let's just move that over. So we will have room the sp three carbon, hydrogen ond vibration. Yes, that's an old sea there for at once. Now, if we move on to the other, we'll have the same 3000 with number rod intense alcohol peak. But what will also get now is we have an aromatic which will appear but differently here. So, we'll see at now at 350, 3115. So 30 50 wavelengths, we'll see, you know the sp two carbon, hydrogen bending and vibration there. Okay. And we also see the carbon to carbon double bond vibration at 16,000 wave numbers. So that will allow us to really pinpoint that we have an aromatic. Okay, and this information that I've highlighted here, let's just will be common in the rest. Okay, so I'll just some repetition there. So all of these will experience this sp two carbon hydrogen and carbon carbon peaks there. No. If we move on to the ether now it's gonna be a little bit different here. So we have a carbon oxygen bond that is slightly different here. So the C. O. Bond can't really be seen too well in the I. R. Since it appears Below the 13,000 range. Okay. And it became really differentiated amongst all of them. So this point right here will also be pretty common amongst the others as well. Yeah, but so this one will be I guess the the compound that is that shows the least info. So just write that there. Okay, and that's just to move quickly along here. Now, with once we reach the carbon heels, now we're going to experience some pretty unique carpet oxygen want. So the other hide, I will be one of the lowest and the ones that will be the most, we'll have the most up field peak will be the key to. Okay, so let's find the key tone. It's the last one here. It's carbonell. So what I'm going to mention right now here, this is carbon Neil, um, carbon oxygen bending. So for the key tops that will take place at 7 25-7 oh five with numbers And we'll move along to the all the height. That will be at 742-720. Okay. Then the car box. Little gas. It will be also quite low as well At 1725 to 7000. Okay. So how will really also told the difference between the car box and gas said though, is that it will also have the broad alcohol stretch. Okay, from, you know this. Ohh, there. Okay, then, lastly, the Esther will be the most upfield carbon steel or downfield carbon will stretch. And well, the data we have right now, I'll be at 1750 1730. That's latino stone feels it. Um, all the had that would actually belong either to the and hydrated. So cool. Right. But this patch, it is, you know, most downfield people. That's just the I. R. So, if we know, consider the NMR, the H of the mark, what are the differences here? Okay, so what we'll see here Is this one will be the most upfield. Okay, so the rest of them will have the bands like hydrogen that's on PPM. This one will luck those shifts. Okay, so, luck. That's one. Okay, that's pretty characteristic of this peak here. Is that This will also we're looking at the asians in this alcohol if we're not going to capture this alcohol peak here. So, what we'll see is, you know, just five hydrogen weapons old hydrogen and actually there's only three kinds here, since it's pretty symmetrical there. So, what we'll see there is, and everywhere else actually Is three bands like hydrogen. So, if I label the screen, that's common for the rest of them. But what, what will really allow two different sheets? These the sixth actually is what sort of alcohol? That would be the most downshifted keith there for this um per box sleeps hydrogen, That will be And I'll just certainly we believe that that will be 11- 12 ppm. Okay, then, after that will be all the height, I'll be at 9-10 ppm. And let's just get rid of units. for now. We know we are looking at the Tamar. So it's 9-10. That's actually here. 9 to 10. Next up, Bull, we'll have the Esther this hydrogen here will be the one of the other pretty dumb shifted signals at four. Okay. You know, the unique signally here. And then what we'll have after if let's look at the key topic eternal. Actually pretty be pretty upfield. That's what's unique about it. And Blanquita will be around 2.2. What else? Yeah. And if we look at this, either eat their compounds should be quite downfield as well. And 3.5. And the initial alcohol that we looked at their we have a buffalo lean here. So you will see that at around, you know, 1.3. But they don't have an integration of two, which is unique naturally. Very upfield as well. Okay, so the main difference here is gonna be, you know, in this our group for these ones, and I've listed the art group, hydrogen is here and then for, you know, the cycle hex at home. Well, just, you know, like be liking the Bins allocate region there, that will allow us to distinguish all these compounds and, um, are and I are.


Similar Solved Questions

5 answers
Dx at 0 6293x 959 ton 'C) -0 7524 (041) -0*L8493 x (It- 0 7241 (9 1) dt 0 4781snitoble Liabuhov funckoa Taen sov (a) Constvnct ct (o-03, 0 058) is spiral sik the Cri - ticdl PoInt
dx at 0 6293x 959 ton 'C) -0 7524 (041) -0*L8493 x (It- 0 7241 (9 1) dt 0 4781 snitoble Liabuhov funckoa Taen sov (a) Constvnct ct (o-03, 0 058) is spiral sik the Cri - ticdl PoInt...
5 answers
Problem 1: Suppose p is &a large prime and primitive root (mod p). For m > p3 define & hash function h(m) = a2m (mod p): (a) Explain how h is pre-image resistant. (b) Show that h is not strongly collision-= ~free by finding counterexample_
Problem 1: Suppose p is &a large prime and primitive root (mod p). For m > p3 define & hash function h(m) = a2m (mod p): (a) Explain how h is pre-image resistant. (b) Show that h is not strongly collision-= ~free by finding counterexample_...
5 answers
LiCHzCH3 PrHOiii)iv) HO"HO PrHO Pr
LiCHzCH3 Pr HO iii) iv) HO" HO Pr HO Pr...
5 answers
Suppose biologist studying gene locus in American Bison discovers that there are two alleles at the locus and E) and that they show incomplete dominance When the biologist surveys genotypes within deme; she finds that there are 10 bison with the TT genotype, 60 with the TE genotype, and 30 with the EE genotype (6 points):
Suppose biologist studying gene locus in American Bison discovers that there are two alleles at the locus and E) and that they show incomplete dominance When the biologist surveys genotypes within deme; she finds that there are 10 bison with the TT genotype, 60 with the TE genotype, and 30 with the ...
5 answers
In the figure solid 0.3kg ball rolls smoothly from rest (starting at height H 5.9 m) until it leaves the horizontal section at theend ofthe track;atheight h 2.2m How far horizontally from point Adoes the ball hit the floor?Number6.08Units
In the figure solid 0.3kg ball rolls smoothly from rest (starting at height H 5.9 m) until it leaves the horizontal section at theend ofthe track;atheight h 2.2m How far horizontally from point Adoes the ball hit the floor? Number 6.08 Units...
5 answers
29 _ Find the area of the region bounded by the curves y = 2 and I = 2y2 2 30. Find the area of the region bounded by the curves y = Sin I and y = sin 21 on the interval [0,7].
29 _ Find the area of the region bounded by the curves y = 2 and I = 2y2 2 30. Find the area of the region bounded by the curves y = Sin I and y = sin 21 on the interval [0,7]....
5 answers
10.2.41Find the vertex,focus and directrix of the following parabola. Graph the equation: y2 = 24xThe vertex is(Type an ordered pair )Enter your answer in the answer box and then click Check Answer:3 parts remaining
10.2.41 Find the vertex,focus and directrix of the following parabola. Graph the equation: y2 = 24x The vertex is (Type an ordered pair ) Enter your answer in the answer box and then click Check Answer: 3 parts remaining...
5 answers
=(6 2 3 2 Express the given = unction h composition ol two funcions Tand 1 0 9)X) 1onmne functions ,
=(6 2 3 2 Express the given = unction h composition ol two funcions Tand 1 0 9)X) 1 onmne functions ,...
5 answers
(Gpts) Fiezann 8 li bounded (Hint: 8 Ricmann ietramable function 2 Provc thet {
(Gpts) Fiezann 8 li bounded (Hint: 8 Ricmann ietramable function 2 Provc thet {...
5 answers
Given family with three children, find Ihe probabillity of Ihe ovent; The oldest two are girls, given that - the " oldest iS gir.The probability that the oldest two are girls, given that the oldest Is girl Is (Simplify your answer: Type an integer or a fraction )
Given family with three children, find Ihe probabillity of Ihe ovent; The oldest two are girls, given that - the " oldest iS gir. The probability that the oldest two are girls, given that the oldest Is girl Is (Simplify your answer: Type an integer or a fraction )...
5 answers
Find 8 equation the plane containing 8 point(1,2.3) and the Ine
Find 8 equation the plane containing 8 point (1,2.3) and the Ine...
5 answers
The probability of observing the sample is if the mean is actually 1.2
the probability of observing the sample is if the mean is actually 1.2...
1 answers
Nuclear magnetic resonance can be used to determine the mobility of molecules in liquids. A set of measurements on methane in carbon tetrachloride showed that its diffusion cocfficient is $2.05 \times 10^{-9} \mathrm{m}^{2} \mathrm{s}^{-1}$ at $0^{\circ} \mathrm{C}$ and $2.89 \times 10^{-9} \mathrm{m}^{2} \mathrm{s}^{-1}$ at $25^{\circ} \mathrm{C}$. Deduce what information you can about the mobility of methane in carbon tetrachloride.
Nuclear magnetic resonance can be used to determine the mobility of molecules in liquids. A set of measurements on methane in carbon tetrachloride showed that its diffusion cocfficient is $2.05 \times 10^{-9} \mathrm{m}^{2} \mathrm{s}^{-1}$ at $0^{\circ} \mathrm{C}$ and $2.89 \times 10^{-9} \mathrm{...
1 answers
Solve using the elimination method. If a system is inconsistent or dependent, so state. For systems with linear dependence, write the answer in terms of a parameter. For coincident dependence, state the solution in set notation. $$\left\{\begin{aligned} 3 x+5 y-z &=11 \\ 2 x+y-3 z &=12 \\ y+2 z &=-4 \end{aligned}\right.$$
Solve using the elimination method. If a system is inconsistent or dependent, so state. For systems with linear dependence, write the answer in terms of a parameter. For coincident dependence, state the solution in set notation. $$\left\{\begin{aligned} 3 x+5 y-z &=11 \\ 2 x+y-3 z &=12 \\ y+...
5 answers
(Ch: 5 Two identical, perfectly conducting loops are far apart and share the same axis. Each has self-inductance and a current flowing in the same direction, so the energy in each loop is {LI. They are then brought together and superposed. What is the final current in each loop? (b) What is work done in bringing the two loops together? Is the work done on the loops or by the loops?
(Ch: 5 Two identical, perfectly conducting loops are far apart and share the same axis. Each has self-inductance and a current flowing in the same direction, so the energy in each loop is {LI. They are then brought together and superposed. What is the final current in each loop? (b) What is work don...
1 answers
Perform the indicated operation. $$\frac{1}{3} \div\left(-\frac{1}{2}\right)$$
Perform the indicated operation. $$\frac{1}{3} \div\left(-\frac{1}{2}\right)$$...
5 answers
Is the second derivative of f(x)= arctan(x) an oddfunction?
Is the second derivative of f(x)= arctan(x) an odd function?...
1 answers
In Exercises $99-102,$ use the functions $f(x)=x+4$ and $g(x)=2 x-5$ to find the specified function. $$ g^{-1} \circ f^{-1} $$
In Exercises $99-102,$ use the functions $f(x)=x+4$ and $g(x)=2 x-5$ to find the specified function. $$ g^{-1} \circ f^{-1} $$...

-- 0.019258--