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Hellutinu MDNA MLTLAI complementan cpal nott the photo ahaudl dleach Mrand pLace ONE ATA MME; |gnnngCompare' the base xquenco the strands 0f thcse t10 new'...

Question

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Answers

Describe the structure and complementary base pairing of DNA.

a. DNA is made up of two strands that are twisted around each other to form a helix. Adenine pairs up with thymine and cytosine pairs with guanine. The two strands are anti-parallel in nature; that is, the 3’ end of one strand faces the 5’ end of other strand. Sugar, phosphate and nitrogenous bases contribute to the DNA structure.
b. DNA is made up of two strands that are twisted around each other to form a helix. Adenine pairs up with cytosine and thymine pairs with guanine. The two strands are anti-parallel in nature; that is, the 3’ end of one strand faces the 5’ end of other strand. Sugar, phosphate and nitrogenous bases contribute to the DNA structure.
c. DNA is made up of two strands that are twisted around each other to form a helix. Adenine pairs
up with thymine and cytosine pairs with guanine. The two strands are parallel in nature; that is, the 3’ end of one strand faces the 3’ end of other strand. Sugar, phosphate and nitrogenous bases contribute to the DNA structure.
d. DNA is made up of two strands that are twisted around each other to form a helix. Adenine pairs up with thymine and cytosine pairs with guanine. The two strands are anti-parallel in nature; that is, the 3’ end of one strand faces the 5’ end of other strand. Only sugar contributes to the DNA structure.

We want to write the complementary DNA strand to a piece of template DNA. We've been given so really easy to remember guanine and cytosine complimentary adnan. And I mean, so if we have a look, we're just going to go, we've got a guanine, have sat seen another. We have five means we have an asinine and so on. Okay. And as a means we'll have a family in there. We'll have a sight unseen still get a guanine like the fastest. Um, so as you can see wherever we have gone and we have a side scene where we have a diamond, we have an antonin cytosine, guanine. And and as a means of diamond.

So we're giving a segment of DNA. Um, and you want to know which is part, um are we want to know if the dean a plan race will start replicating the segment from the right. Um, so the question A which will be the template for the leading shrimp so of replication is proceeding such that the DNA on the right is replicated. First, the top strand is a tip of road leading strand. And for B, we're gonna draw them all killed when the dina plan raises halfway along the segment. So here we have five prime a T t See e g t uh, a c g a tcg. And then it breaks off a c j c g t a c t Hey, see, a g t c. This is three crime. And so this is the, um, leading strand. Well, then, on the bottom here we have, um, three prime. And this is the art. A primer for the Okazaki of every fragments. Now we're gonna draw the to complete daughter molecules. Um, so we'll have five prime. And then will this repeat the opposite with a eagling t and see equaling G still continue on like that. And, um, this will be the same as the other daughter cell. And then lastly, um, is the diagram a compatible with bi directional replication from a single origin, the usual mode of replication. And, yes, it simply represents replication at one of the forks.

Okay, So the question is given this strand of DNA, starting with the five prime and all that is is just giving us What direction is it going forwards? Or is it going backwards or whatever? And that's just telling us that this is the template given this strand G T T T c T T c a g a g A And what would be then the compliments. So just like what we did with the base pair rules. And we talked about this before Kirby letters with Kirby letters, G see, the next one is G. And so, of course, you would expect for tea to be its base pair t straight letters with straight letters. And so it's gonna be the we're gonna have a That's gonna be the base period to the team. That's for each of those three letter tease. We're gonna have three Letter A's, then here, see? So it's the flip of what we did at the beginning, and but it's C and then we're gonna have g down here in the one that we write is our answer. Quote unquote, this is again that it's just the other side, so this would be like the left side, and this would be the right side. However, you want to think of it as your writing this on your paper. So in answer to this question, then G T T T C T T C A A G a G a is the response C c a a g a a g T T c T c T. It's just a demonstration of the base pair of rules.

Hello Everyone. Welcome to Chapter six. Question number one. Here we have two questions. A look at this picture. The distance between replication for four and 45 is about 280 can responding to 824 nucleotides. These two replication force would can lead in about eight seconds and the folks seven and the folk eight more away from each other and therefore never can lead. Now, let's look at this picture. Question number two, the total lines of the D N. A. Saw in the electron micrografx is about one point to find nuclear nuclear nuclear tights responding to 4400 nucleotides. This is only about 0.002%. And now let's look at the equation. This is the total D N. A. In flying style. Thank you for listening.


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