In this question given that is that is in the playground, there is a small medical around is given having a radius that is Our is given, there is 1.20 m and uh the math of this merry go round is given. That is and one is equal to 1 80 kg. And further data is given that his days of corrosion is given for merry go round. That is K is equal to 91 Centim or I can see it in the entire unit, it will return is that is 0.91 m. And now in the question is saying that there is a child whose mass is given, that is M2 is equal to 44 kg. So this child is run at a speed given that is we is equal to three m/s along a path that is tangent to dream of initially stationary merry go around and then it is jumped on. So in the kitchen it isn't that the neglect friction between the bearing and the soft of merry go round and follow the parts given. So here you can see that three parts given. So let's start asking every part one by one. So in the party it is asking that we have to find the rotational inertia of the medical around, about it axis of rotation. So I considered that will witness that is I is equal to and one that means myself merry go around, multiplied by areas of cooperation is square. That means K square. So now for the data that is given. So I will get the answer. Power party, january internet series I is equal to 1 80 kg. Multiplied by 0.91 Weather is Squire, so not simplified. The answer is That is 149 Kg meter square. So this is the answer for part. Now come to the next part. That is part B in which it is asking that we have to find the magnitude of angular momentum of the running child about the axis of rotation of merry go round. So I can see that that will recognize that is angular momentum of the child about the axis of rotation. That will be equal to I am too. That means mass of child multiplied by is plenty of spill. That is we multiplied by. Yeah, eight years old. A small merry go round. So now next step is years after the data. That is human. So I'm too is human in the equation that is math of child, that is 44 kg and the animal spirits given that is we, that is three m per second And our is human that is 1.20 m. That means status of medical around so subdued here, then I will get the angular momentum of the child about the axis of rotation of the merry. Go round. So it will be a nice that is held. Child is equal to 44 times of 44 kg terms of three m per second, times of 1.20 m. So after falling where you will be, that is 158 kg meter square per second. So this is the answer for part B. Now come to the last word that is far to see in which it is has hindered that we have to find the angular speed of merry go round and child after the child has jumped onto the merry go round. So I will consider that the anglo spirit of medical around and child after the child has jumped daddy's omega. So that means omega of maybe go down. So in the party it is asking that we have to find the angular speed of America around and child after the child has jumped onto the merry go around. So I will consider that angular speed will be Daddy's omega. So for finding this omega that is angular speed here. I will use the angular momentum conservation forum because there is no external torque is acting. So the according to angular momentum conservation. The next step will be euthanized. That is initial angular momentum will be equal to Angela. Finally, final angular momentum. So initial angular momentum will return is that is M. V. R Plus zero. So 0 is showing that the angular momentum of maybe go around. So because this is a stationary so it will return to zero. And and we are seeing the angular momentum of the child about the axis of rotation. So that will be equal to Now I'm writing the on the right side that is final angular momentum that will return as it is. I system times of oh my God! Here I systems will be witnessed. There is total rotational inertia about the axis of rotation, so that will return us. There is equal to I considered rotation initiator of medical down plus rotational inertia of the child. Mhm. Multiplied by now. Right, the remaining term that is remaining factor that is omega. And this omega we have to find out that is angular speed of the maybe go around and child after the child has jumped onto the merry go round. And now left side will witness that is after simplifying. It will return issues and we are so No next step is I considered on the right side. I might go That means the rotational inertia of merry go round will be organized by using the answer from party. That is 149 daddy metal square plus. Now the additional inertia of child about the axis of rotation will create a nice that is. I can see their families. There is M2. I was squared. Are the square multiplied by now. Right? The remaining factor that is omega that will be called to. I consider it on the left side. I would write NvR mm. Yeah we have to write the and that is showing the muscles child. So that means and we are now next to be subdued. The data that is human. Em to his mass of child that is 44 kg. Multiplied by these human that is three m per second. Multiplied what it is is given that is equal to 1.20 m. That will be equal to 149 plus two is one that is much softer, that is 44 kg, multiplied by art is square. That means 1.2 is square times of omega. Now simplify it, then I will get the answer for parts seat that is equal to 0.744 radian per second, so this is the answer of party. Now you can see that I had solved every part that is part, having answered that is 149 kg meter square. Then part of me having answered that is 158 kg meters squared per second and parsi, having answered that is 0.744 radian per second, Thank you.