5

7c_gracili;_ add it to the figure above AND to your 30 skeletonl ORIGININSERTIONPREDICTED ACTION Does this muscle ABDUCT THE HIP 0r ADDUCT THE HiP? (Choose one: ACT...

Question

7c_gracili;_ add it to the figure above AND to your 30 skeletonl ORIGININSERTIONPREDICTED ACTION Does this muscle ABDUCT THE HIP 0r ADDUCT THE HiP? (Choose one: ACTUAL ACTION Doos this muscle ABDUCT THE HIP or ADDUCT THE HIP? (Choose ono. PAPATION CanYOU feel Ihi:k muscle when contracts? LYES NQL

7c_gracili;_ add it to the figure above AND to your 30 skeletonl ORIGIN INSERTION PREDICTED ACTION Does this muscle ABDUCT THE HIP 0r ADDUCT THE HiP? (Choose one: ACTUAL ACTION Doos this muscle ABDUCT THE HIP or ADDUCT THE HIP? (Choose ono. PAPATION CanYOU feel Ihi:k muscle when contracts? LYES NQL



Answers

Leg lift You are doing one-leg leg lifts (Figure P8.67) and decide to estimate the force that your iliopsoas muscle exerts on your upper leg bone (the femur) when being lifted (the
lifting involves a variety of muscles). The mass of your entire leg is $15 \mathrm{kg},$ its center of mass is 0.45 $\mathrm{m}$ from the hip joint, and its rotational inertia is 4.0 $\mathrm{kg} \cdot \mathrm{m}^{2}$ , and you estimate that the rotational acceleration of the leg being lifted is 35 $\mathrm{rad} / \mathrm{s}^{2}$ . For calculation purposes assume that the iliopsoas attaches to the femur 0.10 $\mathrm{m}$ from the hip joint. Also assume that femur is oriented $15^{\circ}$
above the horizontal and that the muscle is horizontal. Estimate
the force that the muscle exerts on the femur.

Let's apply traditional form of Newton's second law to the femur leg. The torque exerted about the hip joint is due to the forces exerted by the um if you s always I right, So force exerted by force Exerted by Helio Service on length. This is the force exerted by Elias s on leg, uh, and exerted by the lake. Wait. So force exerted by the earth on the lake This is force exerted by the earth on the leg. Now apply the rotational form of Newton's second Law about the hip joint, the axis of rotation. We know that Net Dark is equal to I times Alfa High Times, Alfa. Now let's write down the dark. First of all force exerted by the Earth Force exerted by the earth on the leg in the Y direction multiplied by, uh, length, right Same stands for the center of mess Less if exerted by I own leg on leg a dime sign off 15 degrees time sign of 15 degrees multiplied by l. One divided by course sign of 15 degrees which is equal to high times elephants right now for 6. 30 by I own l so forth exerted by I on l is equal to high times. Alfa High Times l far less mg times L Center Off Mess Divided by 10 15 10 15 Multiply by 0.1. Now let's plug in numbers for here. Four multiplied by 35 less, 15 multiplied by, uh, 9.8 9.8 Multiply by 0.45 Divided by, uh, 15 degrees. Multiply by 0.1 So force exerted by eye on L is equal to 7.6. Hello, Newton.

It is thickest in upper and back sections of that seat. Pabulum, which forms the hip joint socket movement such as running, jumping and walking, apply for us to this part of the hip, so it makes sense that it's the biggest here.

This's Chapter one problem. 56. So in this problem, we're given five vectors. We're told the magnitude of each vector when which is all the same among all the vectors we've got. That's 2.75 mutants, and we're told the directions. The vectors, which are different reach one Call us are the magnitude of the vector in every case. And so we're asked to add up the vectors, even victor components, to find the magnitude and direction of the resultant force when we add those altogether. So in Part B, were asked to do a graphical some I'm actually going to start with that just to get a sense of how that will look. So starting from the right, most vector in the in the figure given in the text Let's have this length we 2.75 Newton's and let's say it's a needle of 20 degrees in the next one is bent little 10 degrees to the right, the next one ten 10 degrees to the right of that 10 degrees to the right of that, these air supposed to really small angles, and you could draw better if you have a straight edge and 10 degrees to the right of that. So this last one should be. I've drawn maybe a little too curd, but should be 60 degrees from vertical 20 plus 10 plates, 10 plates, 10 plates. 10. So if there were a vertical, this should be 60 degrees and this one 20 degrees and the others are at all the multiples of 10 degrees in the in between and the resulting vector. See, these were all drawn out tip to tail. Now's the result in vector goes from one end of the line straight to the other. All right, so what we want to do is add up components. So in the extraction, the ex component of the result in vector and actually, if you want, are to be the man with you. The result. Invest very better. Call this someone something else. It's like call it f its just the attitude of one force. So the ex component of the resultant is the sum of the ex components of all of these other factors. And remember, for the diagram given X is going straight up. So all these angles here, the 20 degrees that are marked the 60 degrees it's marked and the 30 40 50 in between. The's are measured clockwise from the counter clockwise from the X axis on the counter. Clockwise from the X axis is what we need when we're using expressions to find the components where our exes are. Co signed data data is that angle measured counter car cars from the X axis or are signed data for the wife opponents? So, in this case, are ex Component is going to be of the first factor is 2.75 Newtons Times Co. Side of 20 degrees plus 2.75 Newton's Times Co. Sign of 30 degrees plus 2.7 time five Newton's Times Co. Signed for injuries and so on and so on. So actually, write this a little more simply by factoring out the 2.75 Newtons and doing co sign 20 degrees plus Co. Signed 30 degrees. And so on a live 60 degrees, I notice that you can factor out the 2.75 Newton's klutz. It's really just a number. Multiply it by the sum of co signs. You cannot factor out. The co sign itself, cause co sign is a function That's the kind of thing that people might be tempted to dio bits. But do not you have to compute each of these co signs individually and add them all up, plus co sign of 60 degrees. Great. So that's some of co signs will dip, lied by the magnitude of just one of the vectors is going to get us our ex component, and that is 10.2 Newtons. And so that's going to be put it in red on the diet around that's gonna beat this. This component this distance here for the Y component will do the same thing except replace the ex with Why replace all the co signs with sign, etcetera, etcetera, and she'll end up with a slightly different value and even the angles involved. On average, these individual force factors are a little more aligned with the X axis on the Y axis. So expect the Y component to be a little smaller. And in fact it is. We had met with 8.57 mutants. It's a seven here. Great. And so once you've got these components now need to convert them back into a magnitude and direction. So what for that, we use our formula for man getting magnitude from components. The magnitude is the square root of the sum of the squares of the components. So our ex squared plus are y squared. We substitute in 10 point to Newton's for RX 8.57 Newtons for our why, and you end up with 13.3 Nunes, which looks reasonable. If you look at the vector, the diagram above and remember that one of those black vectors was 2.75 Newton's and this blue back there should be 13.3, and then our angle here and in the diagram that's going to be this angle drawn and blue fi is the inverse tangent of our Y Over rx, and so we're expecting something between zero and 90 degrees here. Plug in are y over rx and you get exactly 40 degrees. And it's no coincidence, given how these five individual actors were evenly spaced, that this angle comes out, too. The average of the five different angles involved and that is, since we've already done Part B really got the graphical some, and you could draw it. You could draw it carefully with a ruler and protractor picking some scales in length scale to be equivalent to one Newton on your paper at home. You could do it really carefully to check that the magnitude and angle come out right away. We have drawn it. We just have, ah, sense that it looks looks reasonable. So if he is, we already done for B and that stand of the problem.

Yeah. So for this problem we're finding the result of the force of the pull of these five tendons on the bone here. So the steps to do this Alright as fellows when we want to find the component forces for each tendon and then we're gonna add them all up. And then we're gonna use these new X. And Y. Components to find the magnitude direction of the resultant force. Soon I've drawn the picture. Listen, textbook of the five forces and their degrees along with we know that each pole with the force of 2.75 newtons. And to break up each of these forces under their component forces, we have a good use these equations. The X component of the force is equal to its magnitude. I'm the co sign of its angle and the Y component of the force is equal to the magnitude times the sine of a tangle. And this one's a little tricky because we have the X and Y axis flipped. Yeah. Okay, okay. So once you do that as I've done here already calculated Imola and then we can add them all together for the total component vectors for X. It's 10.3 and why? It's 8.7. And once we have these two total component vectors, it's easy to find the magnitude and direction because the magnitude of the force is equal to 10.3 squared plus 8.7 squid and all that square rooted not equals 13.5. And to find the angle we take the inverse tangent of the Y component over the X. Component. So 8.7 over 10.3. And that gives us 40.2 two degrees. And then part B. Of this problem is to draw a picture labeling a result in victor. So we can do that as well. So you can kind of think of putting each tendon or each force tip tip to tail. So we have the first one which is 20 degrees from the excessive X. Axis. Remember their flip? So it's like this and we have another one so we're just putting them tip to tail and stacking them on top of each other floor right? And then the resultant vector goes from the very beginning. Very first vectors tail all the words of the very last victor's tip. That's the result in victor whose magnitude is 13.5 and it's at an angle of 40.2 degrees from the X. Axis.


Similar Solved Questions

5 answers
Weanaud F answers lhe quesiions on this workshocl; use Ihe IR spectrscopy handoui? eleetlg Inciudiing the "Protsch 'handout Ior Inlorpreling lingerprint reglon (<1500 panau Con sider the [nlrared spacirum below and ansie questions16503022 2928Whal bonds the molecule produced these absorptions? (ex sp' C-H)3022 cm-12928 cm"1650 cmThe compound has six carbon atoms. Circle the most Ilkoly identity this compound.
Weanaud F answers lhe quesiions on this workshocl; use Ihe IR spectrscopy handoui? eleetlg Inciudiing the "Protsch 'handout Ior Inlorpreling lingerprint reglon (<1500 panau Con sider the [nlrared spacirum below and ansie questions 1650 3022 2928 Whal bonds the molecule produced these a...
5 answers
GLb0tleQerotoonatt Amitatatnind-pondent velabk tr Wldd AZSv-0" Caudn Eutrt tbtor eandao Dacaeede 147_ 16. euton equato OonitoLluton meaEt_ ndaperdert runablo
GLb0tleQ erotoonatt Amitatatn ind-pondent velabk tr Wld d AZSv-0" Caudn Eutrt tbtor eandao Dacaeede 147_ 16. euton equato Oonito Lluton mea Et_ ndaperdert runablo...
3 answers
The matrixhas complex eigenvalues , Au 0 Ebi, where The corresponding eigenvectors are V4,;? c Edi,whereandand
The matrix has complex eigenvalues , Au 0 Ebi, where The corresponding eigenvectors are V4,;? c Edi,where and and...
5 answers
Generate an O(h?) (second-order) approximation to the first derivative of some function f(x) using 3 points, 80, 81 and *2 using the polynomial interpolation approach: Give the finite difference formulas for each of the points To, €1, and T2- Assume they are equally spaced, with spacing h.
Generate an O(h?) (second-order) approximation to the first derivative of some function f(x) using 3 points, 80, 81 and *2 using the polynomial interpolation approach: Give the finite difference formulas for each of the points To, €1, and T2- Assume they are equally spaced, with spacing h....
5 answers
Draw the mechanism for the reaction shown below (2 points)-HzSo
Draw the mechanism for the reaction shown below (2 points)- HzSo...
5 answers
ACIDS AND BASESCalculating the pH of a strong base solutlonA chemist dissolves 635. mg of pure potassium hydroxide in enough water to make up 70. mL of solution: Calculate the pH of the solution_ (The temperature of the solution Is 25 %,)Round your answer to 2 significant decimal placesDo
ACIDS AND BASES Calculating the pH of a strong base solutlon A chemist dissolves 635. mg of pure potassium hydroxide in enough water to make up 70. mL of solution: Calculate the pH of the solution_ (The temperature of the solution Is 25 %,) Round your answer to 2 significant decimal places Do...
4 answers
[0o0 -7Time (heur)Using the graph above: deterinine the average rate Of reaction between ( = 2h & [= 24h. (1 mark) b) determine the instantaneous rate of reaction when the concentration is 10 mgfmL_ (1 mark)
[0o0 - 7 Time (heur) Using the graph above: deterinine the average rate Of reaction between ( = 2h & [= 24h. (1 mark) b) determine the instantaneous rate of reaction when the concentration is 10 mgfmL_ (1 mark)...
5 answers
The equation 1+8 %y ANzty )dx + -4+l)dy - = 0 zy Vy"is an exact equation if A=
The equation 1+8 %y ANzty )dx + -4+l)dy - = 0 zy Vy" is an exact equation if A=...
5 answers
How many valence electrons does the following atom have?Provide your answer below:
How many valence electrons does the following atom have? Provide your answer below:...
1 answers
Simplify. Do not use negative exponents in the answer. $\left(3 u^{-2} v^{3}\right)^{3}$
Simplify. Do not use negative exponents in the answer. $\left(3 u^{-2} v^{3}\right)^{3}$...
1 answers
Knowing that the radius of each pulley is $200 \mathrm{mm}$ and neglecting friction, determine the internal forces at point $J$ of the frame shown.
Knowing that the radius of each pulley is $200 \mathrm{mm}$ and neglecting friction, determine the internal forces at point $J$ of the frame shown....
5 answers
Kewpalel Drthe Eelewilng true regarding DNA structure"Eikjple ChalceAdenine-thymine bose palrs foxm threz hydrogen bonds, while guanine-cytosine base pairs fom {woAdenine thymlne base palrz form two hydrogen bonds While uenine-Gosin base pairs TonM ihreeTwo hydrager bonds exist between each base pabonds Klst Derwe-n each bos? pr
Kewpalel Drthe Eelewilng true regarding DNA structure "Eikjple Chalce Adenine-thymine bose palrs foxm threz hydrogen bonds, while guanine-cytosine base pairs fom {wo Adenine thymlne base palrz form two hydrogen bonds While uenine-Gosin base pairs TonM ihree Two hydrager bonds exist between each...
2 answers
Find the centroid of the region bounded by the graphs off(x)=x^2 and y=x+2
Find the centroid of the region bounded by the graphs of f(x)=x^2 and y=x+2...
5 answers
Please explain the question belowIf Y = b1X1+b2X2 + b3X3, thenthe parameters b can be calculated by the equation:[B] = ([XT] [X])-1 [XT][Y]where X is the matrix of experimental observations, Y is thematrix of the values of the dependent variable, andXT is the transpose of matrix X. Calculate theparameters b1, b2, andb3 from the following data: X1 1 2 3 4 5 6X2 0.2
Please explain the question below If Y = b1X1+ b2X2 + b3X3, then the parameters b can be calculated by the equation: [B] = ([XT] [X])-1 [XT] [Y] where X is the matrix of experimental observations, Y is the matrix of the values of the dependent variable, and XT is the transpose of matrix X. Calculate...
5 answers
Determine the PH of a solution with [H30 ] = 5,28 * 10 5 M Your unswrer should contain decimal places a5 this correspondsto 3 significant Iigures when dealing with logs PH =
Determine the PH of a solution with [H30 ] = 5,28 * 10 5 M Your unswrer should contain decimal places a5 this correspondsto 3 significant Iigures when dealing with logs PH =...
5 answers
Use the equation Y = x' -Jr' t0 answer the following questions: 4) (2 points) Find the domain ofy Xerpoints) Find the x-interccpu(s) &s points Y- X 3x(2 points) Find the y-interccpt(s) points: Y-X-3x Y:0 3 ' Y:0(10 points) Find any maximum and minimum points_points) Find any points of inflection.
Use the equation Y = x' -Jr' t0 answer the following questions: 4) (2 points) Find the domain ofy Xer points) Find the x-interccpu(s) &s points Y- X 3x (2 points) Find the y-interccpt(s) points: Y-X-3x Y:0 3 ' Y:0 (10 points) Find any maximum and minimum points_ points) Find any p...
5 answers
Consider Uhe Novann8E boup X graph which represents (re fumba stok t5 $0 4 For Urree dllerent (cmpanesImust be Urue about tne dna Sets dbove Whch o/the bobonrg stxements dstribution has the lest QRv t Company Q1 foc Compary (djla Q3 for Compay Ad3u 8 Fowet [nan [ne ( Uhan (herange &u Comrpany € The (ange of Compjry A Varger(and ( c only Nore ofthe above /5 true(and (ony (and ( Wory(ony
Consider Uhe Novann8E boup X graph which represents (re fumba stok t5 $0 4 For Urree dllerent (cmpanes Imust be Urue about tne dna Sets dbove Whch o/the bobonrg stxements dstribution has the lest QRv t Company Q1 foc Compary (djla Q3 for Compay Ad3u 8 Fowet [nan [ne ( Uhan (herange &u Comrpany ...

-- 0.019276--