5

B. F(s) = (s + a)(s + b)2s - 1F(s) = s2 _ 6s + 18s2 + 6s + 9d. F(s) = (s - 1)(s - 2)(s - 4)...

Question

B. F(s) = (s + a)(s + b)2s - 1F(s) = s2 _ 6s + 18s2 + 6s + 9d. F(s) = (s - 1)(s - 2)(s - 4)

b. F(s) = (s + a)(s + b) 2s - 1 F(s) = s2 _ 6s + 18 s2 + 6s + 9 d. F(s) = (s - 1)(s - 2)(s - 4)



Answers

a. $8+3[-2-(6+1)]$ b. $(8+3)[-2-(6+1)]$

In. The problem you have been given is off base plus twice is because 10 is Squire. Last 12 days 14 4 Now we have invasive equals. 2 10 is squad. Last 12 is last 14 or is less in your inspire minus two ways to now. This is a region as your worries last to last. The last see overall is spy minus two is last. So we have to find for NBC by using it and try it. So wait three be well on C four Now this is three over His last two last seven is last hole is spot my nesting phase last. Now we define the lab waas So please not Les Waas This 32 last lap Listen worse off 78 plus for full Squire minus two is last two. This equals two. Now that is to last lap. Blessing words off. Seven days minus one over is minus one for this part. Last one homeless choir less Listen was off 11 over is minus one This part plus one whole list. While now this is equal to three into B to the power minus duty. Last seven needed a power t costing less level, even about ng sci fi. So this is the answer

In this question we have to find the value of A plus B plus C plus D plus E plus F. Where a B C. D. E F. R A M S between two and 12. Given this is for you mm B She B E s uh athletic means between two and 12. Therefore, two mm B. See B mm F. And to well R N A P Who's Yeah. Common difference is. Yeah. Yeah. Mhm. The is equal to feel good to help minus two upon six plus one. Therefore B is equal to 10 upon seven. Here. Number of tones He had a number of times in AP is eight. Therefore two plus E plus B plus C plus D plus Ive plus F plus 12 is equal to some of victims of given A P with the critical people. 14 plus A plus we plus C plus B plus he plus F. Is equal to eight upon to into to into plus eight minus one. Into then upon seven. Okay. 10.7 is the value of common difference. 14 plus A plus B plus Simples. Deep liss E plus F is equal to full into four plus. Okay then, isn't it A plus B plus See Plys Deep Bliss Sleepless F is equal to open food into 14 minus. She's 14 A Place B plus Simples. Deep plus E. Plys F is equal to 42 A plus B plus seedless. Deep Bliss. E. Bliss F is equal to 42. This is our final answer for this question.

In the problem events. The thing is, the This is why I minus the knees that's two over is into is my is my left six. Now, this is original Hill six minus the knees. Let's see. Oh, isn't too is minus into a minus six if he wants to. Your ways left. Buba, raise my C over is minus six. No, we have this. Six is on study days. Last two equal to a into is miles into a C minus six. Class B is into age minus six. Plessy is in the age Miles or is in his mind is my six over is in the minus one into a small six. So this is the spot overall, we have this time now really finding bye, darling. In matters or he didn't finding a BNC. So simplification. We have equal one about three. The other one on C equal footing over three. No, we have to put this one of our country is class one over is minus. Last 14/3 into a C minus six. So after the lab listen worse off this way. Have this sequence one upon three. Last year. The party last. Do you know what? Three. Even the power 60. So this is the answer

Really asking us to do is to calculate the universe transform of the rational function escape plus full of the s squared plus X minus six s lead plus X Now the first step to performing the transformers to obtain the partial fraction to composition which will start by breaking the denominator in too linear terms. Since all the linear terms of distinct we can actually write this as some number over s minus two plus some number of s plus three plus some number over S plus five plus some number over s. To obtain each of these numbers, we plug in the value which would cause this to be equal to zero, um into this equation, ignoring the problematic terms where you will get an infinity in the denominator. For instance, to get this constant, we plug in X equal to two into this equation, ignoring this term here. If we do that, we'll get the particle a fraction decomposition forever. This Dean native 13 over 30 negative. Two of the three and five of the six. If we now take the inverse transform of this, then we'll get for over 15 times e to the two t minus 13 over 30 times E to the negative three T minus two over three times E to the negative five t plus five of the six times a constant.


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