Yeah. All right. So, we were given some information about birth weights, birth weights example, random sample of 30 girls have a standard deviation of 829.5 HD. And there's a claim that birth weights of girls have the same standard deviation as birth weights of boys, which is 660.2 is G. And once you use alpha equals 0.01 we will identify the null hypothesis. The alternative hypothesis. The testes cystic, the p values and the critical values or the critical values. Make conclusions about the null hypothesis. And what does that mean for our claim? So, first listen, and find the null hypothesis. We're talking about standard deviation. So it's gonna be sigma And we're claiming that they are the same as the boys, which is 660.2. The alternative Is that well, the waste of the girls do not equal the waste of the voice or the standard deviation. So sigma does not equal 660.2. So, note, we are used doing a two tailed tests. Yeah. So now that we know are no alternative hypothesis, let us find the testes statistic for the testis cyst IX, Since we're assessing standard deviation is going to be a chi squared And the death statistic is N -1 times squared divided by sigma squared. So, looking at our information, we know we have 30 girls are and is 30, So we have 30 -1 -1 S squared is going to be the standard deviation from the girls, which is 829.5 squared. Yeah. And the standard deviation is going to be the standard deviation given the null hypothesis of 660.2 squared? Yes, if we were And this should give you approximately equal to 45 point 78. Mhm. So that's our PVA So that's our test statistics next to find our P value. If we're trying to use the table method. Mhm. The first thing we want to we need fire degrees of freedom, Which again is in -1. So in this case 30 -1 is 29. Yeah, we can find us in the table. So we're it won't give us an exact number For the chi squared but if we go down to 29° of freedom, we're trying to find Between what two alpha values, 45.78 falls under and that will fall under 0.0 25. Saint alpha. Less than 0.1 I think of those science the wrong way. Yeah, but remember, this is a two tailed tests. So when we're dealing with to tell test, once we find where Alfa falls under, we're gonna multiply both sides by two. So this is actually a 0.05 rather than Alpha, which is greater than 0.02. So what we know from the table is that our alpha value falls between 0.05 and 0.02. We don't know the exact alpha though. If you want to get more accurate number for R. P value or far p value we can use our again for our since this is a two tailed tests we're gonna have to have To so this would be two times Yeah P chi square. So the peak i squared is telling us the probability for the sky square, where on what our testes, cystic. So 45.78. This is from our chi square test. The degrees of freedom, Which in our case is for 29. This is our degrees of freedom and there's one more argument which is lower dot tail. This is going equal to false. If it's a lower tail test then this will equal true. True. It is the right tail is equal force and its two tails you want equal to force. And we will multiply this by two. So if you were to put this into our you have to times the p squared. So normally this would be 0.02467139. When you multiply that by two you got 0.04 93 4 to 78. So this is a more accurate reading of R. P value which again agrees those should be P let's just call it p value R. P values between those and this agrees with what we had before this p value is in between these two numbers. So now we can make our conclusions were going to use conclusions based on the p value in alpha. So remember if the p value is greater than alpha, we will accept don't know hypothesis. And if P value less than alpha, we will reject the null hypothesis. Yeah. So here we have a P value of 0.049, and we're using an alpha value of 0.01. So since the P value, Which equals 0.049 Is greater than our alpha, which is 0.01, we fail to reject no hypothesis. So, what that means for our claim, if we go back up to the claim. So since we fail to reject the normal policies, we the birth weight of girls have the same standard deviations as birth weights of voice, which is the 660.2 at a significant level of 1%.