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The solubility product constant oflead (I) chloride,PbClz, is 1.7 x 10s Calculate the molar solubility in pure [email protected] a 0.50M solution nf sadiumchloride Cic...

Question

The solubility product constant oflead (I) chloride,PbClz, is 1.7 x 10s Calculate the molar solubility in pure [email protected] a 0.50M solution nf sadiumchloride Cic

The solubility product constant oflead (I) chloride,PbClz, is 1.7 x 10s Calculate the molar solubility in pure [email protected] a 0.50M solution nf sadiumchloride Cic



Answers

The solubility of cobalt $(\mathrm{II})$ sulfide, coS, is
$1.7 \times 10^{-13} \mathrm{M}$ . Calculate the solubility
product constant for $\mathrm{CoS} .$

Now we'LL work on problem eighty eight from chapter seventeen. Look here for several compounds were given Mueller saw liability and were asked to calculate the K S P. So for every other equations are the chemicals we can draw the equation for the dissolution of Thie Ionic compound. So first we have very, um Romain. And that could dissolve to form barium two plus and crewmate C R o four to minus. Now if we draw our his table, we have no initial concentration change of s. And so now we're given Mueller Selya bility. So we have K s p is able to s squared from this here s times ass and this is equal to, um or we can plug in for s since that's what we're given in the problem. One point zero eight times ten to the menace. Five five. Let's make sure this looks like a five. Yeah, squared. And so if we take the square root of both side, we can get s is equal to one point one seven times ten to the minus ten so we can move on to part B where were given silver, so fight a G too s o three solid dissolving to form silver, two silver kid ions and the soul fight. And I wonder so if we draw our eyes table we have no initial concentration of the ions We're gonna add two s because of the coefficient of silver s of so fight as to s equilibrium for silver. And as for Sophie So when we have this the's terms here for the equilibrium concentration the K S P will be equal to four s cute and we can go ahead and plug in our Mueller Sally ability here, which is one point five five times ten to the minus five. And when we do this calculation, we did a value of one point four nine times ten to the minus fourteen. Now, for the third part, part C, we're given palladium fire scientist P. D. S C. And No. Two, which is a solid and can dissolve to give palladium. Two plus are curious and then too s c n minus minus. You do our ice table and we can draw our term for chaos p which, because we have s into a s when we multiply them together and square two s we had four as cute, which comes from here to be clear. And so when we plug in the value that were given for S which is two point two two times ten to the minus eight huge, we get a value of four point three eight times ten to the minus twenty three.

This question. Ask us to calculate the molars are ability off co about hydroxide. So first to the chaos P off CO about hydroxide is last. No one times turned to the active 14 which is all true ionization Constanta water. So if so, let's assume the solution is in th seven. Then the concentration of hydroxide I annihilate is one times 10 to the negative seven from the chaos P constantly question we can calculate The concentration of CO by CO about Kyle is 2.5 times 10 to the negative. 22 no.

All right, so, this video is going to go over a problem 54 in Chemistry, second edition um chapter 15. So, this is going over selling ability, um equilibrium, a solid ability to be exact and then this is specifically the kalmunai an effect. So what happens with the common i in effect is pretty similar to last at least principle. And the fact that if you have a reaction and you add a product, um it will cause the reaction to shift towards the reactions and make more reactions. Um and that's, I mean, that's really what the common ion effect is. So we're trying to calculate the muellers variability. So, if we remember the muellers variability is when you have uh ice table or a rice table, this is what we refer to as X. So it's a concentration of um the ions that is in solution basically. To put it simply, it's a little bit more complicated than that, but in this case it will be so. And then we're trying to calculate the Mueller scalability of KGB are in a solution of point 035 molar sodium bromine. So we have our silver bromine and first of all we want to ride out a reaction. This is just how I always start when we have Celje bility problems. Um And we have our silver bromine solid is going to disassociate into a G. Plus, Equus and br minus. Equus. Yeah and we don't have to worry about solids for ice table. Um And then we don't start out with any silver plus, but we do start out with some beer minus and that is in our sodium bromide since the br is has a coefficient of one within this uh sodium bromide, it's a 11 ratio sodium bromide. This is the concentration of our bromide. If there were if it was like uh barium bromide er be a uh BR. Two, then we would have to do a little bit different of a calculation to figure out the exact concentration of real mind but we don't have that. So we can go ahead and just put this concentration as br minus and our change is going to be um So we're going to add some silver bromide solid into our solution and hopefully we will increase our ions where I on amount probably by just a little bit but based off our chaos P value which is pretty small. Uh Yeah, so then our A. G. Plus we'll have an equilibrium concentration of X. And this is our Mueller's value ability, our X. So that's what we're solving for. And our equilibrium concentration of bromide is going to be 0.35 plus X. All right, so now we can write our KsB expression to R K. S p for silver, bromide is the same as an equal and concentrate or expression. We don't include our solid. So in this case we're just going to be focused on our products and no coefficients to worry about. It's a wonder on ratio. So that is our r k S P expression and we know that it is equal to five times 10 to the negative 13. Now we can go ahead and plug in our equilibrium concentrations of each of these. So we have our Mueller scalability for silver and then we have 0.35 plus X for bromide five times 10 to the naked 13th. Now we can go ahead and rearrange this. So we have 0.35 actually. So this is going to be a little different. So you could go through, you could multiply these two um, within these parentheses out and then calculate the X based off of that using quadratic formula and all that. However, r K S p is really, really small. So this means that very little amount of each ion is going to actually go into solution and even less. A less amount because we have a lot of bromide already. And so we can say that are 0.35 plus X is approximately equal to 0.35 because X is going to be so small. That is not really going to change that number until this is kind of the exception. We use when we have a small K sp and we start out with a large amount of common my own and we can use this exception. So we can say that it's X times 0.35 And completely disregard this X right there. Mm hmm. All right. And so now to get our answer, we just have to divide both sides by 0.35 to get X on its own. All right. And when we put that in a calculator, we get one point for three times 10 to the negative 11. So this is our answer. This is our Mueller scalability. And we can see that. So this would be the concentration in polarity of silver that it exists at equilibrium. And then this would be the change in their growing. So we can see that this is very small. So that makes sense because if we did 0.35 plus R Mueller scalability, it would be about equal 2.35 So, it's only going to change our answer by a little bit if we use that exception. All right. So that is the end of the question. We got our Mueller scalability. Hopefully that helped

So the Solidarity product constant K s P is the equilibrium expression for a chemical equation that re prisoners the dissolution. Often I only compound So for a component, the general formula I am X n the celebrity product constant will be it to depart in plants. The scent is coming from here in plus to the power em times X to the power this a miner's to the power in


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