5

ASuntv = ASurr AS,s" Cakulata Conslder 8 Number 04 EJi ~74161 folowing V JIK { { Veq Find 1 at 298 K: h entropy values F oHV 2210 2...

Question

ASuntv = ASurr AS,s" Cakulata Conslder 8 Number 04 EJi ~74161 folowing V JIK { { Veq Find 1 at 298 K: h entropy values F oHV 2210 2

ASuntv = ASurr AS,s" Cakulata Conslder 8 Number 04 EJi ~74161 folowing V JIK { { Veq Find 1 at 298 K: h entropy values F oHV 2210 2



Answers

Calculate the entropy change $(\mathrm{J} / \mathrm{mol} \mathrm{K})$ of the given reaction. The molar entropies [J/K-mol] are given in brackets after each substance. $2 \mathrm{PbS}(s)[91.2]+3 \mathrm{O}_{2}(g)[205.1] \longrightarrow 2 \mathrm{PbO}(s)[66.5]+2 \mathrm{SO}_{2}(g)[248.2]$ (a) $-113.5$ (b) $-168.3$ (c) $+72.5$ (d) $-149.2$

Execution. We are given an equation with states edge to engage his home plus year to engage his home forms. The product to S. C. L. Guess is this is the product and these two are the reactant. Now we need to find entropy change for reaction. So that can be written as delta as so delta as for the reaction can be written as delta as for the product entropy change for the product minus entropy change for the victims. For the reluctance deltas product means the entropy change of SCL. That will be to multiply entropy change of at C l minus deltas reactant means change of entropy of H two minus change of entropy of C. L two. Now as given in the question put the data here. Delta SHCL is given as 186.7 minus delta S H two is given as 1 30.6 and delta S. C L two is given as two three. If it's all this we get 19.8 jules far Calvin mole. So this is going to be the entropy value for the reaction. So in the given options option they will be the right option

This is an equation that we can use to solve this problem. It's by scientist named Holtzman. Um, where s is the entropy? K B is both been constant. And then at your log of W, which is the number of micro states we're going to calculate entropy for a mole of hydrogen gas title hydrogen at standard conditions. So to 98 Calvin in one bar for pressure. So given the entropy. So it is 130.7. Jules Mobile, Calvin that's gonna equal are both one constant, which we know is 1.38 I'm sent to the tweet negatory third, and then we don't know W's or trying to find W which isn't micro states. We're gonna divide over, um, both men's constant and multiply it by this side. We're divided by this side, and we're going to get, um, a staggeringly large number for the answer unidentified this over by both sides. And then we're gonna do the opposite natural log, which is taking the answer and raising it from an e. So our answer for micro states could be exceedingly large is could be in two 9.47 to the 24th micro states her goal, and this is huge. And this is so big that we can't even simplify this further. So this is almost like an calculus where you have something. Purchase infinity. This is true. Huge. So this is a large, very large number Micro states for this amount of entropy for this hydrogen.

Were given to different chemical reactions, each with a known change in entropy, Delta s which we can label A and B from these two reactions. We want to determine what the change in entropy is For an unknown reaction we need to combine in algebraic we manipulate the given equations in order to you re rated in such a way that will produce the equation that we want to find the change in entropy of so we can use Hess's law to help us solve this problem. If we look, we see that and our target reaction. We want eso three in the product side and here we have eso three in the products in reaction be and noticed that the switch geometric coefficient varies by a factor of four. So we have to multiply that second reaction which we labelled reaction be by four Also notice that we want s eight and the reactant side and as eight is in the reactant side in reaction a in each one of these have a stroke, you metric coefficient of one So we have to add reaction A as it is to four times reaction be so when we do that we can begin by writing out reaction a again which is s eight s, eight waas 802 goes to eight s 02 and the change in entropy for that reaction was given to be 89 Jules per Kelvin. And now we need to add that reaction to four times the second reaction. And when we compare what we want to the given reaction, we see that we have to multiply this too by four to get eight s 02 waas, one oxygen times four So four oxygen's in the products will be four times to eso three so eight s 03 were the delta s value. Since we multiplied this chemical reaction by four, we have to multiply be given Delta s of this reaction by four as well and four times negative 188 jewels per kelvin comes out to negative 752 Jules her Kelvin And now we just add these two reactions Together we can see that when we do that we have s eight waas eight and four oxygen's air both on the reactant side. So 12 oxygen's and we noticed that eight s a tattoos on each side of this. This reaction aerial cancel out with one another. So the only product is eight eso three. And now we can see that when we combine the equations in this way, you produce the reaction. Our target reaction s eight plus 12. 02 goes to eight s 03 You know, all that's left is that we need to add the to enter peace together, get the total change in entropy for the target reaction. We others together, we see that Delta s comes out to be negative. 600 63 Jules perk help in. That's so you can determine the change in entropy, the reaction using as his law

All right, so Ah, this question is a Hesse swell question. So we're given the elementary steps, um, one and two here. Right? So it's we're talking about sulfur. So for reacting with eight, oxygen's gives eight sulfur dioxide. That's a question one in an equation to is to sulfur dioxides plus o two again gives you to suffer. Try oxides, and the entropy values are on the right. And we have to figure out, um, what the entropy change is for the overall reaction, which I haven't written yet. It's ah, sulfur. So for eight plus 12 02 will give you A S 03 Um, so something that the way that I like to approach these problems is Look for the intermediates. Right. So look for, um, the compounds that are in your elementary steps, but they're not in your overall equation. So for that, that's gonna be, um, this guy right here s 02 Um, So once you identify that, you have to essentially figure out how you're gonna cancel those out, right? So you'll notice that there are two eso Jews. Excuse me. There are two s o two's in equation too. And there are eight s o two's in equation one ones in the products to their in the reactant. So, um, they're gonna cancel out if you add the two reactions together, but they won't cancel out completely. So you'd still have six. S 02 is left over in the reactant. If you added them as they are now, so you have to do is you have to, um, when you're doing the Hess's law analysis, you have to multiply equation two by four. So when you do that so I'm gonna multiply, um four. Sorry. I put the multiply side of the road points. There we go. Someone before, um, Times equation number two. And what that's gonna do is that'll give me. I'm gonna sum them up right away, too. So that will give me overall. So when I add up essay. So here's essay from Equation one plus eight. 02 And then I'm gonna add the reactions from equation two times four. So four times to s 02 Solid. Um, plus 4 +02 gas. Um, that's apprentice season of one, and that's gonna give me I'm gonna write the products of beneath it. If that's Okay, um, that's going to give me eight s 02 That's from the first equation. And then four times two s 03 That's from the second equation. And that's a guess. Um, so now you can cancel out. Right? So you have eight s 02 here four times to you have eight s 02 down here. And what's gonna happen is you're going to get eight s 03 in your products, which is what we need. Um, and you're also going to get eight plus four is 12 0 two's. So that worked out in solving the fact that we needed to get more equivalents of options somehow. So this is actually the overall equation. So once you simplify, um, off this right, So that that goes away, um, you're gonna end up with, um, 12 0 two's and then, um right. Your, uh your s 02 is canceled out, and you're going to That's not what I wanted toe happen. L miss a race. It, um And you end up with, um, eight s o threes. So, um, I put an equal sign. This isn't math mat. Um, so why that's important is because now we have the overall reaction. Now we have to actually do the problem and answer the question. We're just calculated the entropy change. So remember that it's thesame off all the elementary steps, right? So we didn't do anything to Equation one, which means we're gonna add we're gonna keep that is 89 jewels for Kelvin. But we did multiply equation two by four. So we have to multiply the amount of entropy in that for that chemical step by four. Because it takes four of those reactions toe happen to eventually arrive at one equivalents of our overall reaction. So 1 88 we multiplied by four. But we have to some them together, right. It will be four times negative. 1 88 Make sure you get your keep your you're ah, you're signs correct. And when you evaluate that, you're going to get 600 and sorry. No. Hey, negative. 600 nomine black again. 663 jewels Per kelvin. Um, I guess if you wanted to keep it in three, I think we have to do to Sig Figs because 89 jewels for Calvin, there's only two significant figures um So if we act around this to two significant figures, you could just round up, um, to negative. 660 Jules per Calvin as your final answer.


Similar Solved Questions

1 answers
14. Find the poles of below discrete time state space system: Is the system 0.6 stable? Explain Xk+] ~11/xk + [ilux; Yk [3 o]xk
14. Find the poles of below discrete time state space system: Is the system 0.6 stable? Explain Xk+] ~11/xk + [ilux; Yk [3 o]xk...
5 answers
8 8 8 U 1 Il letal HH I MAA 1 1 1 1 J U 1 1 11: absolufel / | L 4/3 Problem 1 conoicna; convergenr or Oiyengem [Fadsoineiy Converden Condmondy converdoni 1 9
8 8 8 U 1 Il letal HH I MAA 1 1 1 1 J U 1 1 11: absolufel / | L 4/3 Problem 1 conoicna; convergenr or Oiyengem [ Fadsoineiy Converden Condmondy converdoni 1 9...
5 answers
(6) Repeat the computations of Example 8.5.1for the funetion g(z) AHd] exaine graphs for some partial Sums_ This time make use of the fact that 9 is eVCn (g(r) 9(-#)) to simplily the caleulations By just looking at the coeflicients_ how do we know this series converges uniformly something?
(6) Repeat the computations of Example 8.5.1for the funetion g(z) AHd] exaine graphs for some partial Sums_ This time make use of the fact that 9 is eVCn (g(r) 9(-#)) to simplily the caleulations By just looking at the coeflicients_ how do we know this series converges uniformly something?...
5 answers
6.1.27Use the confidence interval to find the margin of error and the sample mean.(1.57,2.05)The margin of error = (Round decimal places as needed:)
6.1.27 Use the confidence interval to find the margin of error and the sample mean. (1.57,2.05) The margin of error = (Round decimal places as needed:)...
5 answers
(1) (20 points) 274o (2) (20 points): 2(0-70))(3) (25 points) Solve the Initial value problem: +2y=x}(0)=5
(1) (20 points) 27 4o (2) (20 points): 2(0-70)) (3) (25 points) Solve the Initial value problem: +2y=x}(0)=5...
5 answers
Evaluate the following integrals Statelandvenfz the theorem(s) used, include sketch of the given contour where relevant: All curves are with anli-clockwise orientation unless stated othenwise2 - 4i dz ; C:Izl =4 23 + 42Evaluate it using Path Deformation Theorem:Hint: express the integrand in terms of partial fractions
Evaluate the following integrals Statelandvenfz the theorem(s) used, include sketch of the given contour where relevant: All curves are with anli-clockwise orientation unless stated othenwise 2 - 4i dz ; C:Izl =4 23 + 42 Evaluate it using Path Deformation Theorem: Hint: express the integrand in term...
1 answers
How many permutations of $\{1,2,3,4,5,6\}$ have (a) exactly 15 inversions? (b) exactly 14 inversions? (c) exactly 13 inversions?
How many permutations of $\{1,2,3,4,5,6\}$ have (a) exactly 15 inversions? (b) exactly 14 inversions? (c) exactly 13 inversions?...
1 answers
Write the percent proportion. $$ 103 \% \text { of } \$ 40,000 \text { is } \$ 41,200 $$
Write the percent proportion. $$ 103 \% \text { of } \$ 40,000 \text { is } \$ 41,200 $$...
5 answers
(20 Points) Evaluate the following integral using TWO different methods: Make sure vou identify each method: In other words, let me know which of the techniques you Jre using: Each method will be maximum of 10 points:Jvg-zdr
(20 Points) Evaluate the following integral using TWO different methods: Make sure vou identify each method: In other words, let me know which of the techniques you Jre using: Each method will be maximum of 10 points: Jvg-zdr...
5 answers
Write an equation for the function graphed below-6Preview
Write an equation for the function graphed below -6 Preview...
5 answers
4. Solve the following integro-differential equation:Y(t) - 2f6 v() sin(t t)dt = 1, y(0) = -1
4. Solve the following integro-differential equation: Y(t) - 2f6 v() sin(t t)dt = 1, y(0) = -1...
5 answers
Qusnor Bpurucuaar feaktion 74td AkP _ ushe 0t.161 Nand ASO ot-15' Mmol Kat 298 K Cukculste 4G9 at 550 Kin} JSsUtt rg that Am'Jnd = Asoe Rampeteiur nardly change withQuzsTion ?perticul_ teelontul 4xo vaue o +103Nanid As"0u-Jo4 Vral Kat 298 K Kswuring thet 4h9 mdAs? hardy chanie nith (mtierttuie: detenmna temacradie n %C Ml mfich the spanlaneiy of (JS reaction changes Ine
qusnor B purucuaar feaktion 74td AkP _ ushe 0t.161 Nand ASO ot-15' Mmol Kat 298 K Cukculste 4G9 at 550 Kin} JSsUtt rg that Am'Jnd = Asoe Rampeteiur nardly change with QuzsTion ? perticul_ teelontul 4xo vaue o +103Nanid As"0u-Jo4 Vral Kat 298 K Kswuring thet 4h9 mdAs? hardy chanie nith...
5 answers
1) Based on the fundamental Gibbs equation;Based on the definition of G = H TSa) define 4,G" in terms of 4,H , 4rS" at constant temperature:b) define 4r S" in terms of ArH" at equilibrium:
1) Based on the fundamental Gibbs equation; Based on the definition of G = H TS a) define 4,G" in terms of 4,H , 4rS" at constant temperature: b) define 4r S" in terms of ArH" at equilibrium:...

-- 0.018632--