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Suppose that the height of a falling object t seconds after being dropped Irom $ beight ot 272 fcet & given by f(t) = 272 1612 feet: Find the average velocity b...

Question

Suppose that the height of a falling object t seconds after being dropped Irom $ beight ot 272 fcet & given by f(t) = 272 1612 feet: Find the average velocity betwcen times 4ud ((Us

Suppose that the height of a falling object t seconds after being dropped Irom $ beight ot 272 fcet & given by f(t) = 272 1612 feet: Find the average velocity betwcen times 4ud ( (Us



Answers

An object dropped from rest from the top of a tall building falls $y=16 t^{2}$ feet in the first $t$ seconds. Find the average speed during the first 3 seconds of fall.

Person number two. So here when object is dropped from the arrest, uh the top of the building, that force what the distance even by physical Egyptian. So finally wow. And when the average speed during the past 47. Thanks. So why is it called to extend this thing supposed to use the time? What is the distance? So again and say that our breast. Okay. Uh huh. Course. Certainly record too. And then. Right. No guarantee. So one oh minus Y zero by foreman. Zero. I was 16. And to force to us When a zero x 4. Okay. 30 weeks 64. Okay. What? Okay. Right. Uh huh. Of business? Second time. Uh huh, veracity losing farce or certainly 64 mm. Last. And I'm thank you.

We're given the following function for the height of an object thrown upwards, and we want the average rate of change off the height from one second, 22 seconds. So let's find first h of to This will be negative 16 times two squared, plus 48 times two, which will give us 32 feet. Now let's find age of one. So the negative 16 times one squared plus 48 times one, and this also gives 32 feet. So our average rate of change will be 30 to minus 32 divided by two minus one, which is just zero.

All right, we're giving the following height formula, and we want to find the average rate of change from T equals one to t Eagles three. So let's go ahead and find out what h. Of three is putting this information in. Negative 16 times three squared plus 48 times three. This will give us zero and let's find age of one. It's just native 16 times one squared, plus 48 times one. This gives us 32 so the average rate of change will be zero minus 32 over three minus one. This is negative 32 divided by two, which is negative 16 feat for a second.

And this problem. We're gonna look at an object that has dropped from a tall building, and it falls based on the model y equals 16 t squared. We're looking for this speed here the 1st 3 seconds. So in the interval, 0 to 3 and you're gonna take, uh, take why of three minus y of zero. And we're gonna divide that by three minus zero. And this gives us 16 times three squared, minus 16 times zero squared, divided by three, which gives us 144 divided by three, which is 48. And in this case, our units would be feet per second.


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