Mhm. In this problem we have seven charges distributed. Has shown separation between any labor charges is D. So that between seven and four will be two D. And I've marked all of the appropriate charge values. Notice all positive. That tells us immediately and all forces between all Between any charge and seven are going to be repulsive. Same side. Repulsive. So I want to do Is kind of separate out charge seven. Just to give us some room. That the diagram would be just too too busy. So this is charged number seven here. And I will not I'll just be drawing arrows representing the forces. They are not intended to indicate any length relationship. Bank good relationship. But just give us directional information. Then we'll take care of the banquet of those forces in a minute. So we start with number one. As I said. All forces plus plus Everything's plus plus. So I'm repulsive. So 1 7 repulsive. That means it's going to move be a force to the right. F. 71 four on 7 2- one. Then we can do mother, let's just do the horizontal first three on one. That's going to be two left. Eft. I'm three on 7, I should say. So 73 four Also repulsive. How displaced them. So they again, don't read anything into the length of these indicate something is the same or longer or shorter. Just giving a sense of direction will take care of the magnitudes separately. So this is f. So that's everything. In the horizontal. Everything's along the line connecting the charges. So we don't get any angles out of these guys. Now let's look at two again are repulsive 2, 7. Repulsive. So that's going to be uh the negative Y direction. If you're thinking this this is our X. Why? Why negative Y direction. Then we have 57 repulsive And then we have 67 also repulsive cassette at all. All reports, it would be there will be nothing really to worry about if you had negatives in here. So you get some attractive ones. You draw an arrow, you know to the right or to the left when one of these would be the opposite are not anything of issues. So we have we have our six forces from the six charges on charge seven. And what we do is we know in general we look at athletics, We get the components of the vectors and then we would square each of those components to take the square root. That gives us the Mag two. So now let's let's just remember something about columns law the magnitude of the electric force, columns law the electric instead of constant K. Magnitude of one Charge Mag 2 to the second. Charge over the distance squared. That's the form of it. We've taken care of direction. This is the man to do. So we just got to put a plus or minus depending on if it's pointing in the plus X. Direction or the minus X. Direction or the plus Y or minus Y Direction. So let's let's start let's start with seven. Let's do with in order 134. And so on 71 is the pacific direction. So the ho vectors and the positive. So it's either plus or minus on that whole magnitude. So it's going to be a plus. Okay. And we can do it in any order you want 71 hears Q seven. He won over D squared. And then now for three for 37 that's in the negative direction. So minus K. Q seven Q three or D squared. Same way with four of the negatives -K. Q seven Q four. Now this one is 2 d. away so two D squares. Don't forget. That's not to D squared. That's in the end four. And then the race the second power because it's in the princess. Okay and we can put in we can put in our specific values here. It makes we can see it um one is to so this is going to be K. We have six e. And we have to eat, do you square minus K. Yeah 68. And three is E. Over the square minus K. Six. E. For is 48. And that's like I said over four D. Square. And we can then factor out we know it's going to be a K. E squared over D. Square. So let's factor that out K. E squared over D squared. And then when we have left 12 minus six minus 24 divided by four which is six. Well 12 -6 -6 zero. There is no that there is no X. Component of the net force and now we do the same thing and why And so we're going to have we're going to have We'll start out with 7 to minus K Q seven Q tube over D squared. Then we have we have the five trust Kay Q seven five over D squared plus K Q seven. You're six. And this one is again two D to D squared. So putting in our values out of this and it's K six E Q two is 4 E or D squared. Then we got plus K six E two eE over D squared to S K six E. Katie over two D squirt. And this comes out to be again we can factor out the K D squared K E squared or D squared. So we're going to get here -24 plus 12. And then we have here 48 Plus 48 divided by four. Well what do we have? 48 divided by four is 12, 12 plus 12. 24. zero. F net mm No. You just show you the general form F net X squared plus F. Now, why? That's what we would do if any of these, If these were 90, that's what we'd be doing taking the square root that give us the man, too. That's the way we do it for any factor. But in this case, Sarah, that's it. It's the whole problem.