5

Lue Diecm:Consider the reducing agents Cut(aql, Zn(s), and Fe(s). Based on the information given below, which is the strongest reducing agent?Cu2tlaq) _ Ao2c> Cu...

Question

Lue Diecm:Consider the reducing agents Cut(aql, Zn(s), and Fe(s). Based on the information given below, which is the strongest reducing agent?Cu2tlaq) _ Ao2c> Cut(aq) Fe2t(aq) 2e" CocC) Fe(s)0.54V-0.41 VZn2tlaq) + 2e" Ccc-o Zn(s)-0.76 VCu*(aq)Fe(s)0 Zn(s)56Question 6 (2 points) Given the data below, calculate E"cell for the reaction below:4Alls) 302lg) 12H*(aq)4A/3*(aq) 6HzO()Express your answer t0 two decimal places:A3-(aq)Alls)E'" = -1.66VOzle) 4h*(aq)22ce> 2HzO

lue Diecm: Consider the reducing agents Cut(aql, Zn(s), and Fe(s). Based on the information given below, which is the strongest reducing agent? Cu2tlaq) _ Ao2c> Cut(aq) Fe2t(aq) 2e" CocC) Fe(s) 0.54V -0.41 V Zn2tlaq) + 2e" Ccc-o Zn(s) -0.76 V Cu*(aq) Fe(s) 0 Zn(s) 56 Question 6 (2 points) Given the data below, calculate E"cell for the reaction below: 4Alls) 302lg) 12H*(aq) 4A/3*(aq) 6HzO() Express your answer t0 two decimal places: A3-(aq) Alls) E'" = -1.66V Ozle) 4h*(aq) 22ce> 2HzOU) E? 2 1.23 V Your Answer:



Answers

Consider these half-reactions: $$ \begin{array}{lc} \hline \text { Half-Reaction } & \boldsymbol{E}^{\circ}(\mathrm{V}) \\ \hline \mathrm{Au}^{3+}(\mathrm{aq})+3 \mathrm{e}^{-} \longrightarrow \mathrm{Au}(\mathrm{s}) & 1.52 \\ \mathrm{Pt}^{2+}(\mathrm{aq})+2 \mathrm{e}^{-} \longrightarrow \mathrm{Pt}(\mathrm{s}) & 1.118 \\ \mathrm{Co}^{2+}(\mathrm{aq})+2 \mathrm{e}^{-} \longrightarrow \mathrm{Co}(\mathrm{s}) & -0.277 \\ \mathrm{Mn}^{2+}(\mathrm{aq})+2 \mathrm{e}^{-} \longrightarrow \mathrm{Mn}(\mathrm{s}) & -1.18 \\ \hline \end{array} $$ (a) Which is the weakest oxidizing agent? (b) Which is the strongest oxidizing agent? (c) Which is the strongest reducing agent? (d) Which is the weakest reducing agent? (e) Will Co(s) reduce $\mathrm{Pt}^{2+}(\mathrm{aq})$ to $\mathrm{Pt}(\mathrm{s}) ?$ (f) Will $\mathrm{Pt}(\mathrm{s})$ reduce $\mathrm{Co}^{2+}$ (aq) to $\mathrm{Co}(\mathrm{s}) ?$ (g) Which ions can be reduced by Co(s)?

We have given different substances like Ireland, solid PV or toe solid hydrogen on a kiss. Hello, mini ums Solid form and the silver in the solid form and die a chrome at NCR two or seven to minus. We have us toe compare their oxidizing and reducing potential and to find which one is the strongest oxidizing agent and which one is the reduce, the strongest reducing agent and vice versa. So to compare their strength, we will write the reduction potential of each species. So the reduction potential part PB or two toe react with three hydrogen ions and H is for four minus. I'm We had gained two electrons toe form P. B s or four and two water molecule. So the the reduction for this is 1.6 to 8 world. Similarly, the reduction potential for the DIA chromatic on is the reduction potential. Father diagram it i n s c. R. Two or seven to minus plus 14 hydrogen on to gain six electrons to form toe C R. Three plus iron hair chromium from plus six oxidation. State reduces two plus three oxidation state and also from seven off water molecules. The North reduction for this cell is 1.36 world, while the a reduction for the silver I'm toe gain an electron and form Eiji. So far, the silver I'm the The reduction is zero point zero port for the hydrogen iron toe gain an electron and from ah hydrogen guest the reduction value is zero. Work for the iron if he to place toe gain two electrons and form iron solid. The E reduction is minus 0.45 world while for the hello mini um toe gain three electron from hello Mini. Um solid. The e not reduction is minus 1.66 Worked. No, we have arranged these species in an order. We're from top to bottom. Their reduction potential decreases. The one which has highest reduction potential will reduce is and will be strongest oxidizing agent, the one at the bottom will be will have low reduction pretension, so it will oxidizes. Therefore, it will be strongest introducing agent So let Oxide is the strongest oxidizing agent, While a low mini, um is the strongest reducing agent No p we all do a strongest oxidize engagement while among them hydrogen is we kissed oxidizing agent. Hello, Mini. Um, a strongest reducing agent while silver, as we guessed reducing agent see, you two plus can oxidizes both. Hello, Mini, um, And iron. While h toe or toe can reduces lead oxide and the dia chromite I'm

So in this problem, were given with four reduction reactions and their standard reduction part in shell. And in first part of this question, we were asked to find out the substance, which is the strongest reducing agent and the substance, which is the strongest oxidizing agent. So before finding out that lives right down the reduction relation equations. The 1st 1 is 83 Bless, taking up two electrons to become a plus and then be to place taking up two electrons to become be C two plus take up two electrons to become see and deep less will take one electronics. To meet M d, Maybe write down their standard relation. Putin chills 11 47 find 16 in a beauty 0.2 into one that negative 1.38. So the strongest reducing agent is the substance which has the least tendency to become reduced itself. And as we know that the lowered reduction important shell, the Lord that tendency off assistance to reduced so the substance with the lowest reduction part shield should be the strongest reducing agent. So from here we can see that D plus has that lowest tradition part in shallow minus 1.38. And that means do plus will be the strongest reducing agent. And on this four substances. And for the strongest oxidizing agent, that thing is just the opposite. That means the substance with the highest through different partners. Shield will be the strongest oxidizing agent because hired the reduction parting, she'll hired the chance of a substance to be reduced to yourself and a substance which, UM, which become reduced yourself, act as a oxidizing agent. And that means hired the value off relation potential, stronger doctor, rating agent And for American See that 83 plus has the highest tradition body shell of 1.47 That means three places that strongest oxidizing agent. Now, in second part of this course, Syria has to find out the substance, which can be oxidized by B two plus and which can be reduced to a seat so any substance can oxidize substances. We can lower reelection important shield, then there substance that means for B two plus, we can see that B two plus has a reduction party shell off born 16 and that means B two plus can oxidize substances which have lower correction pardon shield there yourself and for American see that See Toothless and D Plus has have lower reduction partition than be Tobler. That maybe two plus will be ableto oxidize C two plus and a two plus. Now we have to find out the substances, which can be reduced to by sea. So here were given the really important field for C two plus Net men's for C. The relation party shall be the opposite reactions, and in this case, the sign will be positive. Definite See has, in addition, body shallow quality 0.21 and any substance gang video substances, which have higher religion important shell than that substance. And for American see that B two plus has a higher addition potential of parents 60 then C two plus and A 3% had reached your potential of 11 47. That means see will be able to really use thes two substances, a tree plus and be topless. The last part of this question your extra fire right down the balanced equation for the overall celebration that will deliver the highest Walters, and we have to calculate the standard celebration for the creation. So the overall celebration that will deliver the highest voters is just the relation between, um, the substances here, which and the highest value in the relation parting shell or the highest folded in the relation Putin shell. So from here, you can see that the highest voltage irrespective off their sign are for it three plus, which is 1.47. And for deep less, which is 11 38. So the over a celebration from this among this four, this is the relation between a tree Bless and, um, de should give us highest folded. So if you write down the reaction equation 83 players having the, um, higher, less important shell, it will be reduced. So that means well, right. 80 plus in the form it is already in. And we'll have to write down thesis creation in the opposite direction, because do you will be oxidized here. So that means I will have rowed down a three plus blast e. And we'll get deep, less less shapeless. Now we have to balance the equation. So as we know that from a three plus toe a plus, we need to electrons. That means Judy will give us two electrons to become two D plus, and those three electrons will be utilized by a three plus to become a plus. So this is the world celebration for the highest voltage, really were in reaction. And now, if we want to calculate the standard self or unsure for this overall celebration, we just have crew right down the formula for standard sale potential, which is the submission off standard oxidation put in shell and standard reduction Borden Shield. So the standard oxidation putting shell here is the oxidation important shell for thesis reaction. And as we know, that oxidation potential is just the opposite of the reduction part. In show. Chapman's oxidation potential for this creation should be positive. 1138 And the reddish important shell is the relation parting shell for the station here, an ignition body should. He's one on 47 so we just have toe add up these two values, so that standard oxidation potential is 1.38 Plaza Standard if important, chilies 1.47 and that men's overall standards still sell potential is 2.85 fold. We have fold in every. So this is the standard cell potential for variation that will deliver us with the highest footage

Just questions. A little tricky. And that it is the reverse of table 17 1. You'll notice that we have the high reduction potentials up top rather than the low reduction potentials. So, everything in Table 17 1 has been reversed. Thus we are going to have the weakest reducing agent that is at the top left. So see you two plus is the weakest reducing agent. We're going to have the strongest reducing agent at the bottom I said left, I met right at the top right. Is the weakest reducing agent at the bottom right. Is the strongest reducing agent. And then with it being reversed from table 17 1, then we are going to have the strongest oxidizing agent at the top left and we'll have the weakest oxidizing agent at the bottom left, which would be Mn two plus. So in looking at this table mp three plus will be reduced by any product that is below it. So this includes um iodide, P B C D and M N. So P B can reduce F E three plus. PB two plus will be reduced by any product below it, but iodide is not below it, it's above it. So I'd I'd won't reduce PB two plus. Lead can be reduced by any product. Actually. We're talking about lead being reduced so lead can reduce any reactant that is above it. So we're looking at C. 03 plus, F E three plus and iodine. But it just wants to know the ion, so just these ions here and then iron three plus serving as an oxidizing agent, the strongest oxidizing agent being up top. So that means it can oxidize any product that is below it. So it just wants to know what metals and the metals that are products below it are PB cd and men

So we have all the cell potentials here, for part a the weakest reducing agent is the one that's um least likely to be oxidized. So we're looking here on the right hand side and we want the one with um the Lowest oxidation potential, meaning if we were to reverse the signs of these, which one would be the smallest. And that's going to be the first one here. Cobalt two plus the strongest reducing agent. I mean it's just going to be the exact opposite reasoning. The one that's easiest to be oxidizing has the highest oxidation potential. So that's going to be uh manganese. Then we want the strongest um oxidizing agent. So now we're going to be looking at the species that get reduced and gain electrons. So on the left hand side, the let's see what we want. The weakest. Yeah, no, the strongest oxidizing agent has the highest reduction potential. So these are the reduction potentials as written with the correct signs. So this is going to be cobalt three plus. And then the weakest oxidizing agent is going to be the one all the way on the bottom, which is Mn to close. Yeah, for part E we want will lead reduce iron. So it's certain go here. Here's the lead in the iron equations. Um If lead is gonna reduce iron, that means that iron has to have a higher reduction potential and let us have a higher oxidation potential and it indeed does. Uh let us lower down on the list of production potentials. So we have yes, for part F. Will iodine reduced lead? So let's just change the direction hero here. Um So iodine has a higher reduction potential than lead. It's higher up on the so the iodine species will tend to be reduced, not reduced. Let's so we'll say, you know, all right, and then we want which ions can be reduced by lead. So anything that has a higher reduction potential than lead um can be reduced. So that's going to be COBOL It's gonna be iron three plus. And that's gonna be I too. And then I was about to write F G. H. All right, Last one H. Which metals can be oxidized by iron. So if iron um if they're being oxidized, then iron is going to be reduced. So it has to have a higher reduction potential. Um And it says metal. So we ignore iodine. So it's gonna be lead two plus. Well actually it would be the other side. If they're being oxidized, then we would look on the right hand side. So it's going to be led, cadmium and manganese. And we're done.


Similar Solved Questions

5 answers
Problem 46_ A fluid': velocity field i8 F= (x Y,*) . Find the flur of F across the circle z2 _ y? = 1 the xy plane
Problem 46_ A fluid': velocity field i8 F= (x Y,*) . Find the flur of F across the circle z2 _ y? = 1 the xy plane...
5 answers
Find the exact solutions of the given equation; in radians ~ 2cos € =V32tn, where n is an integer andPreview2tn, where n is an integerPreview
Find the exact solutions of the given equation; in radians ~ 2cos € = V3 2tn, where n is an integer and Preview 2tn, where n is an integer Preview...
5 answers
[1] [1] [1] In Exercises 7-16, determine whether the given vectors are linearly pendent: If they are dependent; express one of them aSa linear combinat vectors_Vectors +t2 and 2t + t2 in Pz-
[1] [1] [1] In Exercises 7-16, determine whether the given vectors are linearly pendent: If they are dependent; express one of them aSa linear combinat vectors_ Vectors +t2 and 2t + t2 in Pz-...
5 answers
837=++40 82 #1 H 1 40t+1 1
837=++40 82 #1 H 1 40t+1 1...
5 answers
What mass of A/3+ is present in 57X 1015, formula units of Al203?
What mass of A/3+ is present in 57X 1015, formula units of Al203?...
5 answers
Find the domain of the functionV16 f(I;y) arcsin(zy) + In(z2 + y" )cos(z-y - 1)Sketch graph of the domain, and then determine whether is it open Or closed_ bounded or unbounded_
Find the domain of the function V16 f(I;y) arcsin(zy) + In(z2 + y" ) cos(z-y - 1) Sketch graph of the domain, and then determine whether is it open Or closed_ bounded or unbounded_...
5 answers
'6[-/4.54 answered Calculate Description all the Points] parts 1 + y2 doogle tnteg Make integral: DETAILS sure dA nof follow 'x)} y) | SCALCET8 the 0 <X<5, Instructions 15.1.515.XP set by 1 0/1 WebAssign Submissions when Used submittinSubmit AnswerView Previous Question
'6 [-/4.54 answered Calculate Description all the Points] parts 1 + y2 doogle tnteg Make integral: DETAILS sure dA nof follow 'x)} y) | SCALCET8 the 0 <X<5, Instructions 15.1.515.XP set by 1 0/1 WebAssign Submissions when Used submittin Submit Answer View Previous Question...
1 answers
Refer to the summary box (Partial Fraction Decompositions) and evaluate the following integrals. $$\int \frac{2}{x\left(x^{2}+1\right)^{2}} d x$$
Refer to the summary box (Partial Fraction Decompositions) and evaluate the following integrals. $$\int \frac{2}{x\left(x^{2}+1\right)^{2}} d x$$...
5 answers
Find the indicated functions.Express the circumference $c$ of a circle as a function of (a) its radius $r$ and $(b)$ its diameter $d$.
Find the indicated functions. Express the circumference $c$ of a circle as a function of (a) its radius $r$ and $(b)$ its diameter $d$....
5 answers
Consider the final arrangement of charged particles shown the figure below. What the work necessary very far from one another? (Let 91 6.5 nC; 3.0 nC and 93 -17.5 nC.) 1.75e-05 Your response differs from the correct answer by Icze than 1092 Double cneck vour calculationsbuild such an arrangement of particles assuming they were originally(-120 cm, 0)(12.0 cm; 0)(-120 cm; 120 cm)
Consider the final arrangement of charged particles shown the figure below. What the work necessary very far from one another? (Let 91 6.5 nC; 3.0 nC and 93 -17.5 nC.) 1.75e-05 Your response differs from the correct answer by Icze than 1092 Double cneck vour calculations build such an arrangement of...
5 answers
TeaEaeonacomRCOOOCR' compounds can be reacting smoothly and quickly by reflux with strong bases Ilke KOHFalse'trueCof Carbonylis joined to three other atoms by & bonds; since these bonds utilize sp3 orbitalstrueFalse
TeaEaeonacom RCOOOCR' compounds can be reacting smoothly and quickly by reflux with strong bases Ilke KOH False' true Cof Carbonylis joined to three other atoms by & bonds; since these bonds utilize sp3 orbitals true False...
5 answers
Find the local minimum value of f(t,v) =ITV:
Find the local minimum value of f(t,v) = ITV:...
5 answers
To perform a standardization of NaOH, 40 g of solid NaOH aredissolved in water to form a 1 L of solution. Titration of 100 mLof this solution uses 95 mL of 1 M HCl solution. What is theconcentration of the NaOH solution?
To perform a standardization of NaOH, 40 g of solid NaOH are dissolved in water to form a 1 L of solution. Titration of 100 mL of this solution uses 95 mL of 1 M HCl solution. What is the concentration of the NaOH solution?...
5 answers
A tank of gas at 250 K is isothermally expanded to twice its volume; what is the temperature of the expanded gas?400 K300 K500 K250 K
A tank of gas at 250 K is isothermally expanded to twice its volume; what is the temperature of the expanded gas? 400 K 300 K 500 K 250 K...
5 answers
Acg (2) | 4 #/yau 12/z-1-6122 PcaV; Jing ineqvalities 5e+ 0 f Po,ats i^the comelex lane drew sefarately 2
Acg (2) | 4 #/yau 12/z-1-6122 PcaV; Jing ineqvalities 5e+ 0 f Po,ats i^the comelex lane drew sefarately 2...
5 answers
Given the data in the table below and AH"mn for the reaction HzSOa () ZHCI (g) AH' -62 kJ sOzClz (g) 2Hz0 (AH of HCI (g) iskJimol:Substance AH; (kJ/mol) sOz (g) 297SOa (g) SOzClz-396364HzSO4 () Hzo (-814-286184MacBook Ai
Given the data in the table below and AH"mn for the reaction HzSOa () ZHCI (g) AH' -62 kJ sOzClz (g) 2Hz0 ( AH of HCI (g) is kJimol: Substance AH; (kJ/mol) sOz (g) 297 SOa (g) SOzClz -396 364 HzSO4 () Hzo ( -814 -286 184 MacBook Ai...
5 answers
Down payment, and take out 30-year loan at You want to buy S255,000 home You plan t0 pay 10% as 75% interest for the rest:How much is the loan amount going to be?b) What will your monthly payments be?How much total interest do you pay?oan in 15 years rather than 30 What will your monthly payment be? Suppose you want pay off theInterest will you save you (inance for 15 years instead of 30 years? How much money in
down payment, and take out 30-year loan at You want to buy S255,000 home You plan t0 pay 10% as 75% interest for the rest: How much is the loan amount going to be? b) What will your monthly payments be? How much total interest do you pay? oan in 15 years rather than 30 What will your monthly payment...

-- 0.063983--