5

Point) Let~4 13M =Find formulas for the entries 0f Mn where n is positive integerMn...

Question

Point) Let~4 13M =Find formulas for the entries 0f Mn where n is positive integerMn

point) Let ~4 13 M = Find formulas for the entries 0f Mn where n is positive integer Mn



Answers

Find the values of $m$ and $n$ that make each equation true.
$$
(2 m-3 n) i+(m+4 n)=13+7 i
$$

The given equation is to m plus five plus one minus end iota, which is equal to minus do plus for iota. We need to find the values off m and n such that this equation is true. In orderto find these values we first equate the imaginary parts on then the real parts off this equation so we can write first equating the real parts. Forget toe M plus five is equal. Don't minus two on equating the imaginary parts, we get one minus end. Is he called for now solving these equations individually, we get the value of M on end for which this equation is true. So we saw the first equation. Now the ad minus five on both sides of the equation on get tau M is equal to minus two minus five. So the equation becomes the women's equality minus seven. Now dividing both sides by two. We get m is equal. Don't minus seven by don't. So this is the value of M now for any be sold. The second equation which is minus and subtracting one on both sides we get minus end is equal. Do three on dhe, multiplying both sides by the negative sign we get and is equal to minus three. And these are the respective values off em on DDE n Soviet, right? The answer us for the values M is equal to minus seven by two on N is equal to minus three. The equation stands true.

In this question, we are given with a complex equation that is eight plus 15 iota equals to do m plus three an iota. Now we have to find the values off em on DDE n. In order to do so, we will equate the drill parts as well as the imaginary parts off the complex equation. Now, for the real pants, eight is equal to do him. And for the imaginary part, 15 is equal to 23 in now em equals 28 divided by two I am equals two full. Similarly solving for N We get 15 by three equals to end that is, five equals to end. Therefore, our final answer is N is equal to fool on n is equal to Fife.

To given equation is full bless and plus three M minus seven iota is equal to eight miners to iota on. We need to find the values off em on end such that the equation is true now To find these values, we equate the real parts on the imaginary parts off this equation separately. So equating the real parts we get four plus N is equal to eight on equating the imaginary parts we get. Three M minus seven is equal. Don't do now on solving these two equations. We will get the values off n and M such that this equation holds true. So it's all the first equation for finding the value of N subtract four on both sides of the equation Picket and is equal to eight minus four, which is equal to four. So the value and is four Now this all the second equation. So we add seven on both sides of the equation and get three m is equal to do plus seven. This simplifies to give nine. Therefore, three m is equal to mine. Now, dividing both sides by three v Get M is equal to three so we can finally write the answer us for the values M is equal to three on N is equal to four. The given equation holds true.

The given equation is M plus one plus three n iota is equal. Do five miners nine iota on. We need to find the values off em on end for which this equation is true. Now, in order to find the values, we equate the real on the imaginary parts to each other. So equating the real parts we get M plus one is equal to five on quitting the imaginary parts we get three n is equal don't minus nine. So on solving these two equations, we will get the values off em on end, respectively. So it's all the post equation. From here we get M is equal to five minus one, which is equal to four. On from the second equation. We get the value off m us. If a divide both decides by three, we get N Izzy called Oh minus three. So the answer becomes pat for the values. M is equal to four comma and is equal to minus three. The equation is true


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