Question
Finl #ke Pvo Juct 2,22 Gmf Ike "uotien) 21 exPress anf Ler in Pctac fora 22 2,= [z ((os (5o')+ i Sin [ (50')) , 22= ' 2,22 43 _ (tos(45' J+ iSih (45*9) 22
Finl #ke Pvo Juct 2,22 Gmf Ike "uotien) 21 exPress anf Ler in Pctac fora 22 2,= [z ((os (5o')+ i Sin [ (50')) , 22= ' 2,22 43 _ (tos(45' J+ iSih (45*9) 22


Answers
$49-56$ me product $z_{1} z_{2}$ and the quotient $z_{1} / z_{2}$ . Express your answer in polar form.
$$
\begin{array}{l}{z_{1}=\frac{4}{5}\left(\cos 25^{\circ}+i \sin 25^{\circ}\right)} \\ {z_{2}=\frac{1}{5}\left(\cos 155^{\circ}+i \sin 155^{\circ}\right)}\end{array}
$$
So we can solve for this quotient here z one the one divided by sea to buy first dividing our co efficient. So we have 45 divided by nine, which gives us a value of five. And for our angle here well, we can subtract 22 pi over 15 minus two pi over 15. So this gives us the value of 20 pi over 15 and we can rewrite this as four pi over three and then we have plus I sine for part three. So we know that Cosan of Four Pi over three is equal to negative 1/2. So we have five times negative 1/2 plus or rather minus because sign of four private three is negative. Route 3/2 I and so our solution here is is negative. 5/2 minus five, Route three over to I. And so this is our solution.
So we can solve for this quotient Here. See? One divided by sea to buy first dividing our co efficient. So we have 22 divided by 11 which gives us a value of two. So we have two times co sign and our angle here for this coastline is 11 pi over 18 minus 55 or 18. So 11 minus five gives us a value of six. And so 65 18 can be rewritten as pi over three. So you have coastline of firing three. Plus I sign of, however three. And so we know that co sign of private three is 1/2. So we have two times 1/2 plus Route 3/2 I. And so our solution here is one plus Route three. Hi. So this is our solution.
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