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#SF4Bonding domains: Non-bonding domains:VSEPR formula:Geometric Shape:Polar or non ~polar:#XeFzBonding domains:Non-bonding domains:VSEPR formula:Geometric Shape:Po...

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#SF4Bonding domains: Non-bonding domains:VSEPR formula:Geometric Shape:Polar or non ~polar:#XeFzBonding domains:Non-bonding domains:VSEPR formula:Geometric Shape:Polar or non ~polar:

#SF4 Bonding domains: Non-bonding domains: VSEPR formula: Geometric Shape: Polar or non ~polar: #XeFz Bonding domains: Non-bonding domains: VSEPR formula: Geometric Shape: Polar or non ~polar:



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An AB $_{3}$ molecules described as having a trigonal-bipyramidal electron-domain geometry. (a) How many nonbonding domains are on atom A? (b) Based on the information given, which of the following is the molecular geometry of the molecule: (i) trigonal planar, (ii) trigonal pyrametry of
(iii) T-shaped, or (iv) tetrahedral?

Right. So this question asked us to do a lot of things with this portable here. I'm only gonna have enough room to do the Louis structures. So I'll just tell you guys what to do for the, um, the Vesper structure. So for this first molecule, we know that carbon is the central Adams. We can start there. It's got and oxygen and two florins attached to it. And since that's everything we know, it's unusual. Molecule. We know Carbon wants four bonds. Oxygen wants to sleep. Put in extra bones here. Now everyone's happy. We need Teo determined the hybridization of the interior. Adam's first. So since carbon has three things around it, it's going to share those into three, even Orbital's. That's when the F P, too, and the extra pure battle that we didn't blend into this hybridization mix makes that double bond with oxygen. It's a very draw. This according to Valence bond theory, we wouldn't use thes right angles here because this is going to be tribunal, uh, Pointer. So these air all going to be one twenty degree angles, it's gonna fit essentially a triangle, and that will help us answer whether or not this molecules. Polar. So we've got polar bonds here. Oxygen foreigner. Elect your negatives. I'm drawing these sort of angles indicate that they should be pointing away from each other. Um, and if these were all the same molecule, they would perfectly cancel each other out. But because oxygen and foreign, they're going to pull differently. The smoke you'll will be polar. They don't perfectly cancel each other out. So next we have s two sealed too. And this little stripped here tells us that we're goingto have a corinne bonded to its sulfur, bonded to a sulfur bonded to according the news from all you Corning liketo have one bond. So for life tohave throughout the long pierce suffer like I have to. So everything is happy. They all have the right number of bonds I need to fill in. These won't parents here. Sulfur has six valence electrons uses two for bonding, at least four leftover goingto long bears. And same with the Koreans. It has seven electrons when it uses one to form a bond. It has left over just three low in pairs and everything here has only single bonds in it, which means it's all F p three but it's not going to be straight when here like this when you draw it because it needs to be in the hybridization of Tetra Hydro. So Tetra Hydro looks like sort of too wines like that and then a wedge in the dash Sort of like this on DSO This molecule is going to be poor because these bonds are going to twist it. They're not gonna pull evenly in each direction. Thes here are poor bonds between the sulphur and Corinne and if it was truly when you're like this, it wouldn't be poor. But these bonds are again not gonna be one hundred eighty degrees finally with S F four. So it's sulfur with four foreigners around it and the foreign zehr goingto have, there are tough, completely filled sulfur is going to do one of those rare exceptions where it's breaking the octet rule. That's because it has six valence electrons and it's made four bonds which was a two extra electoral chances. Go somewheres now. Is that ten total things around it. So you break the octet rule, you can't. You have to go higher than S P three in order to fit everything in. So this is f P three and then it uses a D orbital F P. Three d. This is going to form a seesaw type structure. It looks sort of like this in face where one of these is a bond out indicated by a wedge in the other one. Is the dash light indicating that's going back? So this is going to be polar because these bones here are all poor and the way that I drew it here in this Louis structure, they all perfectly cancel each other out. But since it actually on this seesaw, you see that you'LL pull in in this direction and in that direction, and that will cancel each other out. But then there's two arrows pulling down this way, and there's no third arrow pulling up to cancel them out. So this will be a polar molecule

For this question. We're going to give the electron domain geometry and the molecular geometry of the following. Okay, has four bonding domains and no non bonding domains. So we will use the letters AMG to represent the items. So they will be the central atom and B will be the surrounding atoms. So it has four bonding electron domains. So that means it has four bonds to four beats. The electron geometry in this case is the same as the molecular geometry. Since there is no lone pairs of electrons on the central atom that would change the shape and that is tetra hydro. Since there's four electron domains for beef, There is three bonding domains and to non bonding domains. So the three bonding domains would be three bonds And the two non bonding domains for two lone pairs of electrons. So the electron geometry is not going to be the same as the molecular geometry since there's lone pairs that will change the shape. So the electron geometry is tribunal by pyramidal since there's five electron domains in total in the shape or the molecular geometry, yeah, is T shaped for part C. There's five binding domains in one five bonding domains and one non bonded domain. So on the central atom there's five bonds, so one two three or five and 1 non bonding domain, so one alone pair of electrons. This has an electron geometry that is octahedron. Since there's six electron domains in total in the molecular geometry or a shape that is square pyramid. And lastly, we have four bonding domains into non bonding domains. So that means there's four bonds, mhm and too long pairs of electrons. This has an electron geometry that is off to a federal since there's six electron domains in total and the molecular geometry is square planer.

All right, guys, We're going to be doing problem number twenty four of chapter nine in chemistry. The Central Science. So they want us to find the electron to Mae Gentry. And like the gentry of molecule that has the following election, the following is like trying to make it on its central idea. So three bonding demands and no non bonding domains. So we're going toe a in the middle, and we're going to be a three bonding domains. So we're going to have X here, bonded here, so that means that s so if we have three bonding and no non bonding funding than the electron domain geometry is going to be Well, first of all, if there no loon pairs on our central Adam, then our electron domain geometry is going to be equivalent to our to our molecular geometry. So that means that in this case are less under main geometry and our electric Gemma is going to be tribunal plainer from be, we're gonna have three bonding domains and one non bonding domain. So So we're going in the center and three exes bond to it and one lone pair, so we're gonna have so for electron domain geometry. We have four electron domains. Ain't three bombing on one non bonding. So then it's are electrons remain. Geometry is going to be Tetra Hydro and our molecular geometry that's going to be that's going to be triggered. Hope your middle. Now for sea, we're gonna have to bonding domains into non bonding domains. So eh, so it's fun to ex Adams and two lone Paris, that means E therefore bonding domains. So that means is going to be sorry there, before electron mean so as that means he's going to be Tetra Hydro. That's going to be electron to main geometry and em that if we have to Electra too, two bones and to lymph Paris than I'm really a gem. She's going to bed.

Okay, so the 1st 1 that we have is a linear wanted you, which would be something like this. And since it's linear, the angle would be one ET here. Next one is a try. Gunnell. Planners on drive on a blander would look something like this. You can change the color. Okay, so it would be e be on bleed. And every single angle between two atoms would be 1 20 degrees. That's what it's called diagonal planner. Next one is going to be tetrahedron. So for that, you head Drew, we would have full atoms attached toe essential. Adam. Something like this on this would actually be in front on this would be at the end, like behind it. Behind the clean on the Andrew cure will be 109 0.5 degrees. So this is a tetrahedron. The next one is try Gunnell. Bible A middle. Okay, so in this case, I would have five Adams near essential Adam, So I would help. Oh, at the movie here and here. This would be ag nine did agree this angle would be 90 Andi and the one at 90 degree. And then I have one which is behind the plane on one which is in front offered. And this would again be 1 20 These two would be 1 20 this would be at 90 degrees to the plane. Okay. And the next one that we have is octahedron. So just like the name suggests it is, it is going to be like it. This this is one he did you need aid on, then? This is in front, off the plane, like it's coming out on. This would be behind the plane and this is again outside. And this is behind on the angle between one is 90. So this would be at 90 dignities on. If you look at this angle, this angle would also be 90 de gea's. So you


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