Question
16 _ How many JouICS per gralll OL suifur (Jlg Ss) are evolved when sulfur is bumed . following thermochemical equation: S8 accordling % * 02() 8 SO2le AH= 2374UJ
16 _ How many JouICS per gralll OL suifur (Jlg Ss) are evolved when sulfur is bumed . following thermochemical equation: S8 accordling % * 02() 8 SO2le AH= 2374UJ
Answers
Rhombic sulfur, $\mathrm{S}_{8}$, burns in air to give sulfur dioxide, $\mathrm{SO}_{2}$. When $4.809 \mathrm{~g} \mathrm{~S}_{8}$ is burned, $44.52 \mathrm{~kJ}$ is transferred to the surroundings under constant pressure conditions. Write a balanced chemical equation for formation of $\mathrm{SO}_{2}$ from rhombic sulfur. What is the molar enthalpy of combustion of rhombic sulfur? Note: S(s, rhombic) is often used to represent $\frac{1}{8} \mathrm{~S}_{8}(\mathrm{~s})$
We see if this is still recording, it is. This reaction is the synthesis of sulphur hexafluoride s eight and F two are combined to synthesize sulphur hexafluoride as indicated by the balanced chemical equation provided in this problem, we have to givens were given 1.6 moles of s eight and we are given 35 bulls of F to. Since we have to give in to this is a limiting reacted problem will have two tasks. We're going to determine which of our two reactors is limiting 1.6 miles of s eight or 35 moles of Florida, and we're going to calculate the amount. And when this text specifies amount, they mean moles of sulphur hexafluoride produced super simple calculation. This is going to be simply a mole mole calculation for each one of these. So going to set up our two givens use a mole ratio to convert to the more of the product. I'm doing a voice over on this one, so this will take a while for this toe, right? And I'm drinking coffee. I suppose you could hear me swallow that. Sorry. So I decided to do this and switch colors back and forth. I think this is about when I added that beautiful turquoise. So my mole ratios, we'll have the given in the denominator and the unknown in the numerator. It will be 8/1 reporting. It's to suit two significant figures. The answer is 13 bulls sulphur hexafluoride. Okay, switching colors. And let's that upper mole ratio for the Flory of moral bulls of flooring in the denominator. That's 24. That's a bunch. I forgot my Ellen moles. Okay, this will be 12 moles of sulphur hexafluoride. The lower value indicates the one that we're going to run out of. So the limiting reactant is Floren. We can produce 12 moles of sulphur hexafluoride and that's it. Problem solved.
Okay, So when you have sulfur as S. Eight combining with oxygen, which is die atomic, it's 02. And if it's at elevated temperatures it's heated, you would put a triangle over the arrow to convey that it's being heated and sulfur dioxide is S. O. To to balance this, you put an eight in front of sulfur. That gives you 16 oxygen to put an eight in front of this oxygen to give you 16. So that's your balanced equation. And be If you have 200 oxygen molecules And you're looking for how many sulfur molecules reaction to do a mole ratio using the coefficient. So you would put the eight Here on the bottom. So you have eight molecules. Didn't mean to abbreviate that as moles. Let's fix that, let's make this Molecules of 0. 2. And then you're going to one molecule of S. A. So it's 200 divided by eight. You're going to get 25 us eight molecules than for C if we're looking for how many sulfur dioxide molecules are formed in part B Well, if you've got 200 oxygen molecules And you've got 25 S. eight molecules, if you're talking about limiting reactant, you to figure out which one produces the least amount of products, so this would be eight oxygen molecules For every eight s. 0. two molecules, And this is 200 S. 0. 2 molecules, then You have one s. a molecule for every eight S. 0. 2 molecules using the coefficients. And the balanced chemical equation. So 25 times eight is also 200. So you're going to make 200 S. 0. 2 molecules because that's how much each one of them form, that's the least amount of product that you would form.
To determine the limiting reactant. We simply need to determine which reactant produces the least amount of product. Here's our balanced chemical reaction. So if we start with 1.6 moles of sulfur, Mr Akiyama tree is one multiple for eight moles of product, so we would produce 12.8 moles of product from the 1.6 miles of sulfur. We have 35 moles of flooring that is also reacting. We've uncovered the moles of flooring, two moles of product, knowing it's 24 to 8 based on the school efficient up here and we get 11.7 moles of product sulphur hexafluoride. So Floren, which produces the least amount of product, is the limiting reactant.