5

#e n-Uh pascual Sum Sn Com bl (xbl mn-o Sn scsul 6) , (oncluole Bae om lxe U Conoxglru Ocl wnothesl +e Sesues dsdoru I-2n 4"6-7) n=o...

Question

#e n-Uh pascual Sum Sn Com bl (xbl mn-o Sn scsul 6) , (oncluole Bae om lxe U Conoxglru Ocl wnothesl +e Sesues dsdoru I-2n 4"6-7) n=o

#e n-Uh pascual Sum Sn Com bl (xbl mn-o Sn scsul 6) , (oncluole Bae om lxe U Conoxglru Ocl wnothesl +e Sesues dsdoru I-2n 4"6-7) n=o



Answers

Microcosmic salr ant horax are uscd in the idcntification of cations by dry rosts. They arc, respccrively (a) $\mathrm{Na}_{2} \mathrm{~B}_{A} \mathrm{O}_{7}$ and $\mathrm{NaNH}_{1} \mathrm{HPO}_{4}$ (b) $\mathrm{NaPO}_{3}$ and $\mathrm{NaBO}_{2}$ (c) $\mathrm{NaNI} 1, \mathrm{HPO}_{4} .411_{2} \mathrm{O}$ ant $\mathrm{Na}_{2} \mathrm{~B}_{4} \mathrm{O}_{2}, 101 \mathrm{l}_{2} \mathrm{O}$ (d) $\mathrm{NaBO}_{2}$ sand $\mathrm{NaPO}_{3}$

Hi, I'm going to find the value of summation capable zero to N N C. K times Sine K. X. Time schools and minus K. X. So why do we need to find out here? So for that we can apply the method of rewarding the sweeties and then solving it. So what you can do here, let's just change here. Like they were starting from here a zero A one, a two, a tree and so on. We had I am start from here. Let's see here we have K. Placido Okay called one and we reach here. Okay, cool. Okay right now I just started the reverse order. So start from here so start from here like this so start from and then move like this a negative one and here we reach so reach here and negative case so that's how we reverse it. So we reach here now and negative case. So we will not revert this series here. So we get it as Some mission equals 0 to win. Have not changed our computer to win and then and See not uglier we're reaching 2K but now we're reaching to a negative case or have we have and negative K sign now here everywhere cable replaced by and negative case. So here we get signed and negative K. X. And then of course it will be and negative and negative that's coming out to be caused giggs. Now we have this series is the citizens asia and this is also as so we can just rewrite this so become some mission equals zero to end this property here and see and negative case anti case or to be and see okay sign and negative K. X course kicks what we can do now. So we have this series here the series and we have the cities here. So we will just add a two series so you get two times as that equals submission mm equal to zero to end to get N C. K. Times sine K X. Of course and negative gigs from here we get sign K expose and educate X. And then we have ach sign and negative K. X. Of course, K X. So you get here to S equals Submission K equal to zero to an and see okay now here we have signed Cosby plus cause there sign me what is coming out to be sign A plus beans. So we get here sign A plus B. We cannot simplify this. So it's coming out with us equals Submission K equals 0 to end and take it. We get your sign annex. No sign an X. Does not depend information because and it's a constant here. X would also be no different information so we can take it outside. So we get here to S equals sign N. X times we get no submission and see key. So that has given us and C0 plus And see one and so on. Rehab and see it. And it's been already there is given as to the far end. So it will be to S equals sign an X times towards the part. And and from here we get as equals Through the park and -1 sign annex Through the park and -1 sign MX. And that is coming hard to be option.

Hi, I'm going to find us. This some Q for this one. What you can do, we have a negative K. May we have K. Mrs Pelletier a negative K. You know, we have key so we can get some kind of solution here so we can use the reverse technique to find a thumb. So we have this is as here giving us this and what we can do, we can just worn in reverse order. So in reverse order removed. Okay becomes a negative so and somebody means thing starting from first time you're starting from last job, you're starting from K jump starting from a negative cater. So the sum is coming out of the same so we get some mission OK Colt 0 to end anti and negative K and this party are key will be replaced by a negative case. We get signed and negative gate X. Of course we get here that's coming up to be and negative and negative caters to be K. X. So have you get giggs what you can do now we can observe here. This is signing Cosby than courses signed me. We just add the two series here. We get to S equals submission gates Placido two and now N C K n C n minus K. They're saying reparative combinations. So we get here and see Cape this weekend now and we have Sina Costea then plus course A sign B that is coming out to be sign eight Plus piece. So we get signed. Mm He's given us okay And B K X and B has given us and next negative K. Actually we add them regarded as a sign Mx. So it's going to be sign and exhale now see here sign an X. Does not depend on the submission so we can get our information so we get to S equals sign annex. We know that submission, kepala zero, N, C K and C zero plus and C one and so on. Valencia. Let's give an ass due to the power. And so we get here times to the part and From here to get as equals to the power and negative one sign annex. And that is the final answer towards the park And -1 sign. MX. Thank you.

In this problem, the yellow solution yellow solution, which age I need to see R 04 on reaction will give us yellow PPT and the yellow PPT here. Age B b CR 04. Therefore, according to the option option C. H, correct answer for this problem, Option C. Each correct answer for this problem, I hope you understand the the action of this problem.

In this problem, first time writing the accent. So just look at it carefully. Six came for f e CN six plus or three plus city as to so it will react to give the product ID six get to the FECN six plus six. He who add as the product. Therefore, according to the given option, option B age, correct and set absent. Be correct. Answer for this problem. I hope you understand the solution of this problem.


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