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Determine e Dhbcof the following transitions are pamoiie forbidden for a particle 3 82-D box:"n 3 3 Fin W1z 3...

Question

Determine e Dhbcof the following transitions are pamoiie forbidden for a particle 3 82-D box:"n 3 3 Fin W1z 3

Determine e Dhbcof the following transitions are pamoiie forbidden for a particle 3 8 2-D box: "n 3 3 Fin W1z 3



Answers

(II) For each of the following atomic transitions, state whether the transition is allowed or forbidden, and if
forbidden, what rule is being violated: (a) 4$p \rightarrow 3 p$ ; (b) $2 p \rightarrow 1 s ;(c) 3 d \rightarrow 2 d ;(d) 4 d \rightarrow 3 s ;(e) 4 s \rightarrow 2 p$

For these questions have to remember two things. A transition is allowed only when the difference between the L values for both states is because to pleasure, miners one. So what position is only allow it between neighboring states with respect to the orbital frontal number. And you also have to remember how this letter symbols as P d e f G and age relates to the values off L No. After you remember that, you can do the question as follows. So in the first time, and we have a transition from four p 23 p. This foreign free are actually the end quantum number of the principal pronto numbers. And they're not relevant for this question at all. So we can just read it as a transition from the social P to the sexual P and the sexual peak Has Ellie goes to one, as we can see here. Therefore, the Delta Ll for this transition is equal to zero. Then this is a forbidden position. In the second item, we have a transition between, uh, Pete and asks of shells and note that B and es of shells are neighboring. Some shells he has. Ellie goes to one and as has value goes to zero. So the delta telling this transition is he goes to minus one and therefore it is ah allowing transition. On the third item, we have a transition from the deseg shell to the acid show. The the soup shell has l equals true while the acid shell has asked equals to zero. Has Ellen goes zero there for the delta? L Is he close to my news? True. Then this is not allow it. So to know only the second position is allowed on the only for fighting. We have a transition again from the toe s. So again we have delta l e goes to minus truth and Gwen and again they have a transition that is not allow it. And finally, we have another transition from Has to pee the transition from Peter asked his delta Alekos in my nose one. So the transition from ass to Pete we'll have Dotel equals to one in case you want to check it and can just remember that as has led close to zero MP has Ellie goes to one. So we're going from L'Echo to 0 12 because to one before the delta l is. It goes to one and this is their order allowed position. So only transitions be and e are allowed.

So we know that traditions are only possible. If and got him is equal. Go less minus one. So for the first part with the condition and dockers from four p, the creeping does that end is equal to zero because l is one in boat. So this transition it's forbidden for the second part where there is a tree be two one this transition that will be one minus Edo which is equal to one. Yeah, so this is equal to one. So this transition is allowed at the time fied forty Jody Delta Alice against zero. So this transition is forbidden. Forty five day two three s Delta is's to minus legal. This is for real. Then again, And similarly for the last part, we have the four less too topi transition. So don't I will be minus one. He'LL smile minus one zero, minus one. So that's minus one And this is allowed

In discussion, we want to determine which transition is allowed and british transition. We need to find a reflection of the emitted photons. Okay, So um he sold to firstly right down the rules for a lot of transitions. The other conditions for love transitions. Okay, so L must be equal to pass by this one. Okay then the time does he go to zero? All past minus one? So in a we have the transition from Gp 22 S. Okay. So we have only goes to 1 to 0 that our first one. Okay. And transition is enough. Mhm. So the changing energy. Yeah. So to find a change in energy you'll be using using. Uh huh. Yeah. He goes through negative 13.6 E. V. I. N. Square two. L. E. Just be uh 13.6 E. V. Hence 1/2 square minus 1/3 square. So this gives us uh positive value of 1.89 E. V. He then can calculate their uh we're playing he and so we have using he goes to H. F. Goes to hc over lambda. Okay so linda is H. C. Of the E. So we can update. We're playing. Then we convert the energy into jews. Like I'm not pain the menu of yeah trying to charge and then uh we're playing is fun to be 656. Okay so a transition is allowed. We plan is 656. He then in B. Hey the transition is treaty to us. Okay so this means that we have our goals to two to uh zero. So the L. Is equal to two. Okay transition is not alone. Okay so this is the answer for party then the policy we have for I have to treaty or have a treaty. He saw the transition is for americans to treat to help too. So the uh oh is it good to minus one. Okay so it's good um So the E. B. 13 mistakes E. V. Times one of the three square and is one of four square. And uh there is zero point 661 E. V. And so the linda is H C. E. O. E. Keep putting the numbers. Okay. And Brooklyn is 1880. They live with this king. So this is the answer of policy. Okay and the transition is allowed. He then in paddy. Okay the transition is between GDP through one S. Okay so we have was 1 to 0. So what happens is that L is negative one? Okay. And so the transition is allowed. Okay and then change in energy. Okay. Call the energy of the photon emitter is 13.6 E. V. Times one minus one victory square. And the answer is trump won T. V. And the plane is H C O L L. E. He could even numbers. Okay. And so is harry and three. They know that. Okay. So this is the answer party and just now have a Yeah. The data should be take a deep one, but still the transition. Is that okay? Right. So, um, so that's or party of this question And

So of these four transitions between principal quantum numbers energy is going to be absorbed when you go from a lower level to a higher level. So that applies uh to number two and number four because you're starting at a lower quantum number and going to a higher one energy is emitted when you do the opposite, when you start at a higher quantum number and you go back down so that is one and three. And then which involved the ground state. Anything that involves an equals one. So that would be just number one for a part D. They want to know um which will absorb the most energy. So of R two, number two and number four for number two year, going up one level and number four you're going up to levels. So the more levels you go up, the more energy absorb the answer is four and which one? Um It's the most energy. So we'll compare number one and number three you're going down to levels versus down one level. So the answer is number one.


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