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9 (5 pts each No partial credit) Draw the structures of each and predict the H NMR spectrum (approximate chemical shift, integration and splitting):a)anisoleb)4-nit...

Question

9 (5 pts each No partial credit) Draw the structures of each and predict the H NMR spectrum (approximate chemical shift, integration and splitting):a)anisoleb)4-nitrotoluene

9 (5 pts each No partial credit) Draw the structures of each and predict the H NMR spectrum (approximate chemical shift, integration and splitting): a) anisole b) 4-nitrotoluene



Answers

Describe the $^1H$ NMR spectrum of each compound. State how many NMR signals are present, the
splitting pattern for each signal, and the approximate chemical shift.

So nuclear magnetic resonance based on principle that hydrogen access a very small magnet and shows the different behavior for example shielding and the shielding facts when we apply an external magnetic force. So this determines the carbon hydrogen framework of all the organic compounds. So, for example, we have and to own. So what we have is the following. So we have signal about 2.1, 2.4, 1.6 and 9.9. So we have a scale. So about 9.9, you have a triplet thought about 1.6. Have another peak. Mhm. Just over about 2.1. Got a big singler. So this is two point mark. This is the protons here, so they don't see any other protons. That's why they're not split. And last one, we have one more triplet, about 2.4. So pent to own molecules consist of four types of hydrogen atoms for different chemical shift values. So we get splitting pattern of two triplets, one single and one multi. So the carbon and, um, our technique determines the carbon skeleton of an organic compound. So carbon sardine has a nuclear spin of a half, and so it acts as a magnet. Whilst carbon 12, the most abundant isotope, is an M R. Inactive because its nuclear spin is serum. So Carbon 13 NMR each has a chemically non equivalent carbon 13 will get its own signal and own chemical shift value, much like the Proton NMR. So again we can look at the robin. So what we see there's five peaks, so we've got a peek at about 13.6, 16.6, 45.4, 29.8 and two 7.7. So you can see that in the spectrum we will have 2 to 7.7 on its own appears. So where's carbon NMR? We typically uncoupled peaks just to make it easier for us. Then we have remaining four peaks, a lot farther upfield, and they are 29.8 45.4 13.6 and 16.6


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