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Estimate the average binding energy for ${ }^{102} \mathrm{Ru}$ from Fig. 23.11

Number twenty two starts out with a given the bit of info that we haven't e field in any given em wave has a peak of twenty two point five mila volts per meter. And we want to know the average rate at which this wave carries energy across unit area per unit time. So well, we're going to take the intensity. And we know that the average energy transferred across unit area is the average intensity, and it's given by question twin to death shade, which is why we're going to jump right into solving for it. But it one half purgative ity is free space times the speed of light times the he not squared. And we have this. So we'LL get there, get there, get there and this is simply a plug and choke type question. So that's a horrible six. Let's try again. Six point seven two times, ten to the minus seven. What per meter squared

In this problem, the average energy released in each nuclear Friesen is given by e. Average is equal to The Energy 17.6 M. Maybe multiplication. The value of one MDB which is equal to 1.6 multiplication than to the par -13. You'll Which is equal to 28.16. Multiplication. 10 to the power -13. You we all know formula of power which is given by power is equal to and multiplication E by the So the value of and biting can be written at bebe I E. Simply find it further. By putting the value here. I can write it as 500 multiplication. 10 to the past six. What by 28.16 multiplication and then to the power -13 June return simplification. I finally get the value of N by T is equal to 1.786. multiplication and 10 to depart. 20 atoms per second.

So we found the rate of change of H when um T is equal to three was equal to negative 83.1 and the last problem. And so we're going to figure out the average rate of change from two PM to four PM. So in T. Is equal to 42 TZ urged from T is equal to 22 T. Is equal to four. So we need to find a chav two and H of four. So each of two is equal to 5000 divided by two squared, which is four plus 10, Which is equal to 5000 divided by 14. And if you plug this into a calculator 5000 divided by 14 is equal to 357 point once 0.14 and H of four is equal to 5000 divided by four squared, which is 16 plus 10, which is equal to 5000 Right about 26. And if you plug this into a calculator 5000 divided by 26 is equal to 192.3 And .31 actually. And so now we can find the average rate of change from 2-4. Mhm. And that's equal to H. of four which was 1 92.31- Age of two. Just 3 57.14 And then this is all divided by four minus two. So 1 92.31 minus 3 57 point 1 4 is equal to negative 164.83. And then this is divided by two. So this would be equal to negative 82.415. And so we can see that this value here is pretty close to this value that we found for the instantaneous rate of change when t is equal to three. Um They're only off by a factor of a little bit above 30.5 B. Around 0.62 point seven. Um And so what that means is that the average rate of change from 2-4 was just very similar to the instantaneous rate of change when um T. U. is equal to three.

So what we have to find is change. Mhm blog. He then E 96 needle undergoes oxidation made. Okay, so let's see um delta E in this chick in this case is important to be -1.5 Bulls. This is again from age 6:38 in the book and Number of electrons is one. To use this in formula they touch you is equal to minus and s very gotten. Mhm. So -1. multiplied by 9645 homes for Mary, multiplied by €-1.5 is equal to 1 40 you know, juries by May. And this is not changing free and.