5

The compound CH;CH-CHCHO has absorption in the UV range at about 200 nm and strong weak absorption between _ 300 and 400 nm Identify these transitions based on the ...

Question

The compound CH;CH-CHCHO has absorption in the UV range at about 200 nm and strong weak absorption between _ 300 and 400 nm Identify these transitions based on the structure of the molecule. (Hint: You may find useful the results and visualization molecular orbitals from your Iast laboratory (computational) exercise ]

The compound CH;CH-CHCHO has absorption in the UV range at about 200 nm and strong weak absorption between _ 300 and 400 nm Identify these transitions based on the structure of the molecule. (Hint: You may find useful the results and visualization molecular orbitals from your Iast laboratory (computational) exercise ]



Answers

Compound E has the spectral features given below. What is its structure? MS $(m / z): \quad \mathrm{M}^{\pm}, 202$ IR $\left(\mathrm{cm}^{-1}\right): 3030-3080,2150$ (very weak), $1600,1490,760,$ and 690 $^{1} \mathrm{H} \mathrm{NMR}(\delta):$ narrow multiplet centered at 7.34 UV $(\mathrm{nm}): 287(\epsilon=25,000), 305(\epsilon=36,000),$ and $326(\epsilon=33,000)$

Inspector data. It's gonna tomorrow. Goblet Cooper wanted people and wonder Were you born? I wonder Doublet for two broke girls My Giblin 4.8 Delta Mikey Brett By going wonder don't get more different My phone You did, uh, And 7.1 data. See when going Wonder Dog that snow white vocals Ondo the I r debtor 30 30.30 20 during your time, Maybe plant decrypted. So you indeed 30 defense ignorance and 16 words you don't and plans, you know, And even worse, man one about. So in 46. 90 Uh, it's a very Arby's. No, the goal booed. How does it then? Genting This gonna spunk it? Well, most people did from him. I was so lubricant. Oh, troop locals, The ski It's too. I got to see it. But do you born one sweepings toe? You get a market glitter ho bondage This Eunice, they're never born. I never wanted to see that. I see it too. And this is planting. So be combine for the better we get. Yes, thank you. See, it's true. See? It's you Move on. See? It's stupid. Now the year values you gonna do well, too well. The year two stretching. See? Expect deliberations. He is once exposed. Tzeitel If Sisi CW want See Striking Liberation. 9 99 15 See, It's bending. She is winding immigration. Oh, but it's see in stool. See, It's your and 7 40 standing by. She has been the benj injury. Oh, so this is expected only, like

So here we're trying to elucidate the structure of a compound given its Max spectrum and its infrared spectrum as well. So to start off, we were given to peaks on the I R. So if you just draw makeshift spectrum over here with the Y axis percent transmits and wave numbers, Yes, access, we were told at around 1006 100 there is a broad, high intensity peak seen over there. And then, uh, 1360. There is a medium intensity peak. Yeah, it's just trying drugs. So something like that is how the young spectrum might look like. Okay, so, yeah, Now it's time to start assigning some functional groups. So, yes, you probably already know what's over here in this region. If we have a broad, high intensity absorption in around 3600 in this region, you just check your correlation chart. You will see that, Yeah, this is characteristic of a hydroxyl group. So very safe to say that there's an alcohol that we're dealing with an alcohol and even just to prove it further, this, um, medium intensity peak here, uh, 1260 wave numbers is also characteristics of the carbon oxygen single on vibrations. So we have already identified one functional group. Yes, we are dealing with alcohol. So for sure, dealing with alcohol. Nice. So now lets them see well, but all three can elucidate. So we were given the molecular weight from them. Aspect is being 102 Master church. Yes. Okay, so now we're just gonna use, um, math, Thio count number of carbons. So we know that I'm hydroxyl is 17. Master charged units. It's really hydroxyl. So if we just take that out of the way, get that way we get Let's just grab our calculators. Get 85 master charge left. Okay, so now to count carbons, What we're gonna do is we're gonna then divide that by 13, and yeah, this is called the rule of 13. It helps us, um, count carbons. So we know that the C h bond does have, um, a mask. The charge of 13. So then if we divide, um, the remainder muscular rate from the 13, you should be ableto count carpets, and that came out to be around 6.5. So then we can say that we even have six or seven carbons. Okay, so let's try and draw out our structure to see if we can get this molecular weight 102 Okay, let's start off with six apartments. Okay, so you draw it like that and start off with the primary alcohol alcohol just, um, to start off. Let's Yeah, let's count its molecular weight. So it's molecular weight will come out to being So it's it's Harbin's. So we have to do six times 12 and oxygen. I am just the oxygen hydrogen hydroxide. Those kind of 100 Jin's. There'd be 3579 11 and 13 13 hydrogen to the compound. And yet I believe we do get out to 102 France from all for the molecular rate, which is nice Lever sort of started to Yeah, our structure. But we would also have this exact same molecular weight. Um, if it was Game one hooks in all versus to Huck's in all versus three Hexen all so we still have to figure out which of the three it could possibly be. So then now we really need to look at the mass Spectra Thio figure out where we should place the hydra zone. Okay, so just to review some from the mass spec we need Thio review Base peak And what that ISS So, um, you remember the base peak is the highest intensity signal in a mass spectra, and it comes from the stable ist fragment. So that basically means that it will be the signal that has the highest relative abundance. That would be like 100. And it it's so abundant due to the fact that it's stable. So after we eat radiated our sample with whichever electrons organization denies electrons toe charge it, then whatever's on dinar sample fragment, whichever those would be the stable ists would be the base peak. So here, see, screen our base peak waas 45. He asked the charge So then Okay, yes. So we just now need to assign some, you know, functionality to this. So yeah, and we're doing that we would be able thio, figure out the placement of this hydraulic soul so you can't stop here and just call it hexagonal, right? Mhm. Yeah, because we do know textile. You just join the whether it's 12 or three and if you want to figure out whether it's 12 or three. Now, we just need to look at how hexagonal can fragment. Okay, So, um yeah, the most common ways for alcohol's to fragment is through something called offal Cleavage. And that's just basically where the alpha position on a flex in all, which is just the neighboring carbon carbon adjacent to it. Maybe he's another color. Yeah, it's just the neighboring. Um, Carbon. So this guy right here, This is awful for this one. It's the awful for that one. Okay, so then if we just cleave the Alfa Bond or the bond adjacent to the awful I mean then and form an opportunity in my on, we get off the cleavage. So let's just do this and the simplest way possible. Yeah, so here we have it. We have hexagonal one thanks and all. So the way this guy would, um, pregnant is to form a ox sodium ion were Get this one over here. Other a radical, this end radical, going that end. And basically what we form is we basically cleave this bond, um, the part with this long chain and we're left with, like, a radical of this chain. So from the carbons four carbons through radical. And then here he gets the oxen in my own, which is just basically a double Lee bonded, um, positive oxygen. So don't worry too much about that, but here this is the fragment that will most likely cause base peak. However, if you count on this guy's, um, molecular weights, this is 31 has to charge, which is still, um, all in short of what we need to get the correct based peak of 45 master charge. So it's close, so we can say that. Okay, maybe it's most likely than to axonal, which would leave off two carbons instead of just one. So let's just double check. So here we have Hexen all if we make it to hacks in all and form it over here and cleave this bond right there to form this structure. And don't worry too much about this mechanism. This is just extra if you want to know how we can elucidates which, um, the place my hydroxyl shit against life. Mm hmm. And here now we can see that this as a master charge of 45 which is then proving that Okay, we are most definitely working with here, too. External. Perfect. So now, um, the part B was just asking for us to explain the peak at 84 Master charge. Should have been block. Yeah. Okay, so right. So as he also would have seen the textbook. Another way for alcohol to fragment is through dehydration as a second sort of most likely fragmentation pathway. So as it sounds like, we get the loss of basically like a water, okay, which Yeah, she's pretty intuitive as to what? Just so basically, we use the Hydra Axle as well as one of the hydrogen. The farm, like the elimination product. Yeah, but we get then it's just this all cane. I believe it is a radical. A radical cat ion. Okay, they're So this is the peak there. So then, Okay. The way you can really recognize the dehydration, though, is that it would be the molecular ion pink minus 18, 18 small amounts for water. So then yes, just like that, it was 87 was pretty. It's a pretty nice give away the fact that we were going through dehydration pathway because our, um, like Either way, it is 100 to so then 102. My 18 is 84. So then we knew for sure that it was most likely gonna be in the hydrogen pathway. So yes, the mechanism is simply watch of the hydroxyl as well as neighboring proton toe form protocol Cat ion of all King Illumination product. Okay, so let's we learned a lot today, so let's just review. Everything s okay. First made a makeshift ir spectra demonstrating are displaying the two peaks that we've seen one of 13 60. And yes, these were clear giveaways of the presidents of hydroxyl alcohol in our molecule. Due to the spot intensity is very characteristic of alcohol. Okay, so we know we're working with alcohol. Then we did some math. Give them the 102 unregulated. Wait. We subtracted the molecular weight of alcohol to see what was left 85. All right then, using rule of 13, we were able thio count carbons. So for six or seven All right, so then either have axonal or happen all so then start off external to church And yes, we got it is a Texan all. But then Thio elucidate the placement of the hydroxy group. We looked at the base peak, which is the highest intensity signal caused by the stable ist fragment with 100 abundance. So, looking at the mass Spectra, we saw it to be 45 Massive charge. So, yes, if you look at the actually given there was this giant peak here, here, 45 that really gave us are based peak. Okay, so we know that the most common fragmentation thought for alcohol's is awful cleavage where the neighboring carbon bond is cleaved. Okay, so this kind of mechanism here, this position here is Alpha. It's neighbor to a hydroxyl. And we basically cleave this volunteer toe form this radical component here and then the charged oxen IAM group here and, you know, mass spec on Lee. Um, the text charge species. So you don't see this, Really? But this is the one that we see, and but it did not have the correct master charge ratio. So then if we placed it as a to hex, not we were able to use that same cleavage pattern to gain 45 masters ratio. So then we knew for sure. We were working with two checks and all That is the answer for parking, then for part B. Um, it was asking for what the structure is, what the mechanism was. Thio, get this kind of Ah, that's the charge ratio. So if you just compare this number to the molecular formula that was given, we can see that it was It seems to be an M minus 18. And if you have an alcohol M minus 18, it is a clear giveaway off a dehydration profit away where his name says, we lose water hydroxy with another proton and we get an elimination product and so radical Cat ion all keen, okay?

We're taking a look at Here is the integrated absorption coefficient for how the Gaussian Shape band is the following. So here we have the max that is the maximum mal absorption coefficient on Delta Bi Well, to the subscript 1/2 is the width of the band at half maximum. So in other words, we have the in school off E D. V. Bar equals one point, not six e max Doubts of the ball 1/2. So the fast thing we're looking at is the integrated absorption coefficient that is 2.98 times 10 to 8 liters for more per centimeter, about 1 80 nanometers. Another example where we have 5.3 times 10 to the power, seven liters per mall per centimeter at 200 nanometers where nano is 10 to the minus nine moving on 250 nanometers. We have 9.42 times 10 to the five leaders from all but centimeter on. We're taking a look at the oscillator strength now where oscillator strength is defined as F. But we have f equals 4.32 times 10 to the minus nine liters per more the centimeter multiplied by the X or the integration off E. D. BBA so we could determine f to be 1.287 at 189 m. It is not 0.229 up 200 nanometers and for 0.7 times 10 to the minus three at 2 50 nanometers.

Which of the following compounds would you expect to observe? Right in the range? 204 100 millimeters obstruction. Isolated Double one. It was a war. True from about day to isolate the absorption. Is your lord through in control of the education off? More how its absorption should be in the urge to 104. Trust me in the compound. See, there is no education, depending double walls. Booth absorbs higher than through. So the dancers are compounds. Be able to see okay.


Similar Solved Questions

5 answers
Problem 1.6 Let S be a vector subspace of R3 defined byS = {(T1,12,T3) eR:lz =~I2 and T1 2x3]Find a lincar map L R3 _ R2 which has S as its kerncl.b.) Find a lincar map L2 R' _ R: such that L2(R') = $_
Problem 1.6 Let S be a vector subspace of R3 defined by S = {(T1,12,T3) eR:lz =~I2 and T1 2x3] Find a lincar map L R3 _ R2 which has S as its kerncl. b.) Find a lincar map L2 R' _ R: such that L2(R') = $_...
5 answers
Part 4: Piecewise Functions Answer the following' questions aboul this piecewise function:180 *Dlstance (miles)A) What is lhe Speed Limit at the 20 mile marker?Over what Interval is the Speed Limit 40 mph?
Part 4: Piecewise Functions Answer the following' questions aboul this piecewise function: 1 80 * Dlstance (miles) A) What is lhe Speed Limit at the 20 mile marker? Over what Interval is the Speed Limit 40 mph?...
5 answers
If ais an element of & group G. then a = 6. 21. Shov that (51 . [Hence . U(14) is cyclic.] Is 22. Show that U(14) UK- = (1172 23. Show that U(2O) = for any k in U(20) [Hence. U(20) is nt cyclic ] 24. Suppose n is an even positive integer and H is & subgroup of 2, Kalff{+Ke
if ais an element of & group G. then a = 6. 21. Shov that (51 . [Hence . U(14) is cyclic.] Is 22. Show that U(14) UK- = (1172 23. Show that U(2O) = for any k in U(20) [Hence. U(20) is nt cyclic ] 24. Suppose n is an even positive integer and H is & subgroup of 2, Kalff{+Ke...
5 answers
Suppose an object of mass m = 4 kg is at rest at given location with potential energy of PE; = 50 J. Assuming there are no other outside forces acting on the object , how fast does the object move when it reaches potential energy of PEf = 0 J?Vf = 0 m/sVf = 5 m/s10 m/s25 m/s
Suppose an object of mass m = 4 kg is at rest at given location with potential energy of PE; = 50 J. Assuming there are no other outside forces acting on the object , how fast does the object move when it reaches potential energy of PEf = 0 J? Vf = 0 m/s Vf = 5 m/s 10 m/s 25 m/s...
5 answers
4 pts. Compute the characteristic polynomial for the matrix A = ~5 ): Determine all eigenvalues and corresponding eigenvectors for A Answer:(A2pts. the above calculations or otherwise solve the linear system Using211 T2,201 + 512.
4 pts. Compute the characteristic polynomial for the matrix A = ~5 ): Determine all eigenvalues and corresponding eigenvectors for A Answer: (A 2pts. the above calculations or otherwise solve the linear system Using 211 T2, 201 + 512....
5 answers
Item#Inkes 4 0 /4 %1 woik I0 Iove #C' chaly nantnIo #lEio: $ 5 /4 0 #olk 1 inicivu U1e charda Iron Pant AVrun pxeenaal dine/ence VcEIpMlMnstterAcQ125ErdPAYATMMunaanudtlatiarIncotrecl= Iy Ageln: aiemat ninlng
Item #Inkes 4 0 /4 %1 woik I0 Iove #C' chaly nantnIo #lEio: $ 5 /4 0 #olk 1 inicivu U1e charda Iron Pant A Vrun pxeenaal dine/ence Vc EIpMl Mnstter AcQ 125 Erd PAYATMMun aanudtlatiar Incotrecl= Iy Ageln: aiemat ninlng...
5 answers
1- At 100 8C, 100 g of copper piece is put into 50.0 g of water at 26.5. Find the final temperature of the copper-water mixture: (Specific heat of copper 0.385 ] / g oC , specific heat of water 4.18 J / g %C)
1- At 100 8C, 100 g of copper piece is put into 50.0 g of water at 26.5. Find the final temperature of the copper-water mixture: (Specific heat of copper 0.385 ] / g oC , specific heat of water 4.18 J / g %C)...
4 answers
Calculate volume of 5.0 M solution of HCIneeded to prepare 800 mL solution of0.3 M HClmL160.0mL48.0ImL 53.3mL 133
Calculate volume of 5.0 M solution of HCIneeded to prepare 800 mL solution of0.3 M HCl mL160.0 mL48.0 ImL 53.3 mL 133...
5 answers
Solve: X =~2Y, Y = 2X, x(o) =1, Y(o) = 0
Solve: X =~2Y, Y = 2X, x(o) =1, Y(o) = 0...
5 answers
Iftan X = -V3 &7/2 WHERE 2 < X < T. Find the other COSX,SECX COSEC X, SIN X, trigonometric functions using trigonometric identitiesSeleci one_cosX=1/2 secx=-2cosecx-1/v3 sinx=cosx=-1/2 secx=-2 cosecx--1/+3 sinx=-13cosx= 1/2 secx-2 cosecx-1/ 3 sinx= 3
Iftan X = -V3 &7/2 WHERE 2 < X < T. Find the other COSX,SECX COSEC X, SIN X, trigonometric functions using trigonometric identities Seleci one_ cosX=1/2 secx=-2 cosecx-1/v3 sinx= cosx=-1/2 secx=-2 cosecx--1/+3 sinx=-13 cosx= 1/2 secx-2 cosecx-1/ 3 sinx= 3...
1 answers
$13-14=$ Set up iterated integrals for both orders of integration. Then evaluate the double integral using the easier order and explain why it's easier. $$\iint_{D} y d A, \quad D$$ is bounded by $y=x-2, x=y^{2}$
$13-14=$ Set up iterated integrals for both orders of integration. Then evaluate the double integral using the easier order and explain why it's easier. $$\iint_{D} y d A, \quad D$$ is bounded by $y=x-2, x=y^{2}$...
5 answers
Finance 5: Other Loans 6.43CURRENT OpECTIVE Evaluate student Ioan oplionsQuestionCalculate the total cOS1 0l a [S-vear; S20,(HIO student laan Jran interest rate Ot 594 per Yedr compounded manthly Roundt0 tne hearest dallal ,ProvidfyouI ansier below:
Finance 5: Other Loans 6.43 CURRENT OpECTIVE Evaluate student Ioan oplions Question Calculate the total cOS1 0l a [S-vear; S20,(HIO student laan Jran interest rate Ot 594 per Yedr compounded manthly Roundt0 tne hearest dallal , ProvidfyouI ansier below:...
5 answers
Prevlous PateNext PagePage 11 of 15Question 11 (10 points) The sample mean , the sample standard deviation, the sample size, and the confidence level are given Assume the underlying population norally distributed. Find the associated confidence interval for the population mcan 138.9 22.3 28, 99%ParagraphPrevioua ParoNext PakePage 11 0f 15Submit Quh20f 15 questions saved
Prevlous Pate Next Page Page 11 of 15 Question 11 (10 points) The sample mean , the sample standard deviation, the sample size, and the confidence level are given Assume the underlying population norally distributed. Find the associated confidence interval for the population mcan 138.9 22.3 28, 99% ...
5 answers
V for sisayiuas refluxing the 1 mtroured 3 from [ the action 1 was 1 Give 3
V for sisayiuas refluxing the 1 mtroured 3 from [ the action 1 was 1 Give 3...

-- 0.021953--