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How many grams of Mn(CH; COO) there 206 eranis ofan aqueous solution- that is 3 (WW) Mn(CH; COO)...

Question

How many grams of Mn(CH; COO) there 206 eranis ofan aqueous solution- that is 3 (WW) Mn(CH; COO)

How many grams of Mn(CH; COO) there 206 eranis ofan aqueous solution- that is 3 (WW) Mn(CH; COO)



Answers

How many grams of $\mathrm{CuSO}_{4}$ are there in 219 grams of an aqueous solution that is $20.2 \%$ by weight $\mathrm{CuSO}_{4} ?$

So we're asked for how many grams of so we're looking for Two grams of the A. C l two should be dissolved in 500 point. Oh, no. Leaders of water. It's Joe to make girl 0.20 polarity or concentration solution of the A B L too. All right, so we're after the grounds of ch feel too. We know that, um, our value it see a deal too? The node amount of melody, liters of water. But we need to convert this to actually leader because we're working with polarity. That's 1000 milliliters per one leader that used me. Let's see. So 500 by one dozen used me 0.5 Leaders of vegetable now call that polarity is most of See a field too, huh? Leaders of our school shin. That's one leader. I'll be multiplied it by, um, the leaders of water. We would get our most of the A yell, too. So this would give a 0.10 mold of see a field, too now from zero point. No, no, no point. Is there a 0.0.10? Most of the A C 02 were asked to find the ground to see a CEO, too, so we can find the more mass of the A field, too. So let's look for that and then multiply it yet are Graham. So we know that one more of the two is equal to some Grandma CEO, too. So, looking at our periodic table, we see that calcium has a more mass of 40.8 and Theo Corinne has the more mass of 35.45 But we need to multiply it by two. Since there are two Corinne, so 40 point No, ain't too time. 35.45 give the 1 10.98 grand thermal. So let's put that in 110.98 grand, huh? The A C 02 So this gives us times that by 0.1 11 and point, they're all are actually 11 point panda grams of th field. Two for a solution. So this is our solution right here.

Hello and welcome to this video solution of enumerate. Here we are given the density of a 56.0%. By weight across solution of one propranolol is 10.8975 grandpa centimeter cube from this year. To calculate the more mole fraction of the compound. Right? So here we are having that let's say the mass of the salute is out of the solution. 100 g. Right out of that. We have got mass of the salute which is propranolol. He's 56%. That is 56 g. Right? Mm. And we know the molar mass of propranolol is 60 g. And here we will have the number of moles of propranolol let's say N. P equal to 56 by 60. Right? Similarly mass of water When the solution is equal to 44 g. A number of moles of water will be equal to 44 x 18 rate. Sorry not grams, 18 molds. So this is mold now mole fraction of this salute. He's N. P. That is the propranolol pie and play plus N. W. Total number of molds that is equal to. We calculate you will have 0.276. And that is given an option. D Right? I hope this is clear to you and have a very good rest of the day. Thank you

The mole fraction of C two h 50 H is equal to the malls of C two H five or H malls are C two, h five or H plus. The moles of H +20 present were asked to increase the mole fraction. More fraction is now going to be 0.0 5 to 5. We don't know how much ethanol must be added, so that's are variable and the moles of water present are 5.1 moles of water Solving this for acts we confined that X is equal to 0.278 Therefore, um, that's the moles of ethanol that would be present. So previously there, uh waas put 171 molds uh, ethanol present therefore the C two h 50 each required to increasing mole fraction will be 0.278 moles minus 0.171 moles, and this would be equal to what 107 moles. And so that's convert this two grams using the molar mass of ethanol when I find that this is equal to 4.92 grams. So this is the amounts of C two h five old age that must be added

Solution for the problem. More love kills um chloride is equal to 500 militar in 21 liter fun 1000 militar 1000 more later in 20 point 20 malaria, ITI is equal to 0.10 mall and muss off calcium Qala rate is equal to 0.10 more Kill some color right into 110 point 98 g upon one mole is equal to 11. Ground must have killed singularities 11 ground. Here we can sell the same unit Small can sell with more.


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