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The test statistic of z = 2.07 is obtained when testing the claim that p # 0.265_ Identify the hypothesis test as being two-tailed, left-tailed b. Find the P-value....

Question

The test statistic of z = 2.07 is obtained when testing the claim that p # 0.265_ Identify the hypothesis test as being two-tailed, left-tailed b. Find the P-value. or right-tailed Using a significance level of a =0.01, should we reject Ho or should we fail to reject Ho Click here_to view page ef the_standard normal distribution table Click here to view_page 2 ofthe standard normal distribution tableThis is atest:b: P-value(Round to three decimal places as needed )Choose the correct conclusion b

The test statistic of z = 2.07 is obtained when testing the claim that p # 0.265_ Identify the hypothesis test as being two-tailed, left-tailed b. Find the P-value. or right-tailed Using a significance level of a =0.01, should we reject Ho or should we fail to reject Ho Click here_to view page ef the_standard normal distribution table Click here to view_page 2 ofthe standard normal distribution table This is a test: b: P-value (Round to three decimal places as needed ) Choose the correct conclusion below: Reject Ho: There is not sufficient evidence t0 support the claim that +0.265. Reject Ho: There is sufficient evidence to support (he claim that p + 0.265. Fail to reject Ho - There is not sufficient evidence t0 support the claim that p # 0.265_ Fail to reject Ho. There is sufficient evidence t0 support the claim that p # 0.265.



Answers

Test the given claim. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, or critical value(s), then state the conclusion about the null hypothesis, as well as the final conclusion that addresses the original claim. Use the P-value method unless your instructor specifies otherwise. Use the normal distribution as an approximation to the binomial distribution, as described in Part 1 of this section. In a survey of 3005 adults aged 57 through 85 years, it was found that $81.7 \%$ of them used at least one prescription medication (based on data from "Use of Prescription and Over-the-Counter Medications and Dietary Supplements Among Older Adults in the United States," by Qato et al., Journal of the American Medical Association, Vol. 300, No. 24 ). Use a 0.01 significance level to test the claim that more than $3 / 4$ of adults use at least one prescription medication. Does the rate of prescription use among adults appear to be high?

27. Each note is that new is bigger than equal to 32. Which one is The new is small, attentive to determinative value, which is expired minus a note over standard deviation over square root. A van, which is 30.1667 minus 32 over four point or 37 over squared off 18, which is equal to negative 1.943 for the P value if the b value. But we consume it every value you think. Table five with degree or freedom, equal toe end minus one. So the P value according so these inputs is between open or 25 and open or five. Uh, if the value is smaller than significance level not, I possibly rejected. So me here is smaller than opened or five. So we reject they're not hypothesis. So for the if we can say that there is sufficient sufficient evidence to support the clean

Okay, So the given problem explains about touch therapy, and from the study is observed that among 280 trials, the touch therapists were correct. 123 times. Therefore, n is equal to 280 on the X is equal to 123. Okay, so here the researchers use a fair coin to test the sample. So the probability of getting heads on tails scene on bullets your 0.5. So the solitude guests now the next step be the best point estimate of the population proportion is the sample proportion be hot, which is equal to X over end, which is their frequent 2 to 80. Okay, saying 1 23/2 80 which is equal, Does you have put 439 now in part C of this problem is to construct the 99% conference level for the given data. Right, Andi, The 99% confidence interval for the population proportion P is given by portion P is equal to plus or minus e. So first it's compute the value of the margin of error e using the 99% conference level so the Formula 50 use is e CFO to times p cure. You are. So now we know that c ALF over to is zero. Quit. 23 Um, 2.583 maybe. And we have r p portion pee here. You know, que there's one man is p. So it's therefore equal to one minus 0.439 which is your point 561 So now, playing all these values back into this equation, we get e is equal to 0.76 Okay? And now, subsisting the values we can find the confidence interval P. Okay, He bless her, minus e which is equal to, as your point is, your 439 plus or minus Europe 0.76 over. So then we will get the range of 0.363 Did your 0.515

Were given that significance level. Alfa is equal to zero point. You're one. And people who have pulled in favor can be represented by X, which is equal to 481 on the people who opposed is 401. So we get the total number of people this 401 plus 481 physical to 100. You need to Okay, okay, on the given claim is equal to zero point five. Sure. Yeah. Okay, So the claim is that either the null hypothesis or alternative high boxes state the opposite each other on the null hypothesis needs to contain the value mentioned claim. Okay, so you know that the null hypothesis is P is equal to 05 Walter type boxes is just a P is not you. Does your there for the sample proportion, which is the number of successes divided by sample size is equal to X over and X number of successes on. And there's a number simple slips So to your 481 of 382 which is approximately equal to 0.54 54 now, if to determine value of the test statistics of Z is equal to p. There is pure not or the square root of P not times one minus over. And so therefore, if you're plugging all the values since Europe 5454 here minus peanut which is 050 divided by the square root off June 5 times one might in Super five, which is a stupid can over 882 which is equal to 2.7. It's you. So now the P value is the probability of obtaining the value of the test statistic or value more extreme. When the hypothesis is true, you have to to determine the value of P using the normal probability table. Okay, on the former P is equal to P or C was negative. 2.7. Yeah, where is he? Greater than 2.7, which is equal to two p. See Destiny 2.7, which will give us a final answer of two times your point shoes. You 35 which is Joe could choose your shit. Sure. Okay, so now, since this P value is less than our, um, significant level Alfa, we can reject the null hypothesis because PVA is less than significance lovely. Therefore there is sufficient evidence to reject the claim that the proportion of subjects responded in favor is equal to 0.5 and therefore the politicians claim is false.

For a right tailed hypothesis test and the test statistics described below, we want to determine whether or not we are able to reject it, not at alpha equals 0.5 So first, before getting started on either of these parts, we want to note that we can use the normal distribution symmetry and a Z score table to obtain P values for these critical values identified. So for a for instance, the probability Z equals 2.3 we have that the P value is given by the probability Z is less than or equal to negative 2.3 That is because what's to the right of positive 2.3 is equal to what's to the left of negative 2.3 Because the standard normal. So that trick. So this p value is simply equal 2.0212. Since this p value is less than or equal to our alpha value, were able to reject H. Not for this critical value. Next. In part BZ equals negative 0.31. We're going to determine the probability that One minus probabilities is less than or equal to negative 0.31. Again we rely on the symmetry the standard normal similar to how we solved A. So this becomes using the Z score table to look up the Z score or rather the area for negative 0.31 gives one minus 10.3783 Which gives us probably 6-1 7. Since this 0.6 to 17 is in fact greater than our alpha value, we cannot reject H not for part feet.


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