5

Identify the reactant and reagent used to synthesize the product shownReagentReactantDraw the starting material reactant:Identify the reagent:SelectDrawMoreEraseNaB...

Question

Identify the reactant and reagent used to synthesize the product shownReagentReactantDraw the starting material reactant:Identify the reagent:SelectDrawMoreEraseNaBHA BHz ~ THFRings

Identify the reactant and reagent used to synthesize the product shown Reagent Reactant Draw the starting material reactant: Identify the reagent: Select Draw More Erase NaBHA BHz ~ THF Rings



Answers

Draw the products, including their configurations, obtained from the reaction of 1-ethylcyclohexene with the following reagents: a. $\mathrm{HBr}$ b. $\mathrm{H}_{2}, \mathrm{Pd} / \mathrm{C}$ c. $\mathrm{R}_{2} \mathrm{BH} / \mathrm{THF},$ followed by $\mathrm{HO}^{-}, \mathrm{H}_{2} \mathrm{O}_{2}, \mathrm{H}_{2} \mathrm{O}$ d. $\mathrm{Br}_{2} / \mathrm{CH}_{2} \mathrm{Cl}_{2}$

This is the answer to Chapter 20. Problem number 47 fromthe Smith Organic chemistry Textbook. This problem asks us to draw the products of each of these reactions which involves a new organic metallic re agent. Okay, so we ate organic metallic reactions here. Okay, So So for the 1st 1 we have Grenier free agent, and we're reacting it with carbon dioxide, followed by, um, some acid for the work up. Ah, and so this is going to result in, um, the carb oxalic acid. So remember when we react Ah, grin. You agree, agent, With carbon dioxide, we end up with a carb oxalic acid instead of like, an alcohol like we typically get. Um, when we use just analogy. Hideaki Ito. So we have, um basically just replaced our MGB are with the c 00 h. So we have the car back sell gas in there. Okay, so that's a B is a more typical grin. Your reaction. So we have Ethel Griner agree, Agent um and we're reacting it with this This bring system this by cycle. Um, and there's a key tone on the right ring. And so, um, the reaction's going to occur at that key tone carbon. And so we will add our Ethel group from the Griner Free agent. Ah, and our key tone will end up as an alcohol. Okay, so there we go. That's B for see? Ah, we're reacting. Um, and ask chloride with excess green. You're free agent followed by water work up on. And so here, what we're gonna end up with, um, is a central carbon on. And so we started with one federal ring. Ah, and our green Your dory agent is ah, fennel Grenier on. And so we actually end up with three federal rings on this central carbon. Ah, and then also Anelka hole. Okay, um, for D. We're reacting in Esther with excess greener, every agent on water work up. Um, and so what we're gonna get here eyes double addition of the greenery agents. It's a metal grin yeard on. And so we end up with, um, our federal ring fromthe starting material. So there is that. Ah, and then here is our carbon. That was, um, the Esther Carbon. And so it's going to have an alcohol on it now. Ah, and we will have the two method groups that added So one method group and a second. Okay, so moving on to the next page eso for e were reacting just ah Green. You agree? Agent with formaldehyde. Ah. And so the result of that reaction is going to be, um, just the addition of one more carbon to this chain with an alcohol on it. And so we have five carbons to start. Your product will have 456 carbons on the alcohol. So one hexen all is our product. Okay, Um, so then for F, I were using ah, copper lithium re agent. So it's the metal organo. Cooperate. Um, and s o. The reaction here is going to take place at the double bond. Um, so not the key tone key tones gonna be infected. Um, and basically, we just end up adding, ah, metal unit to this change. So it's an eight carbon chain to start 2345678 nine. Now it is a nine carbon chain. The addition of that method group took place at the the AL Keen on. And so there is our key tones still intact. And so that's f for G. G. Is just another typical grin. You agree, Agent s. So it's gonna take place at the key tone in this molecule. Nothing else about the molecule, including that Al Keen eyes going to be affected by the reaction with discrim yeard. So there's the out keen still intact. As I said, um, and then here's the rest of our molecule, so our key tone has been reduced to an alcohol. Um, and we've added a method group here. Um, move that down a little bit, just so that it's easy to see. Here we go. Okay. Yeah. So we've added, Ah, I've added a meth. A group on our key tone is now an alcohol. Okay. And so that's g. And so lastly, um, we'll take a look at h S o h your organo cooper. It that we have here is gonna act is nuclear file and open this up oxide. Um, and following the rules for a pox side opening, it's going to attack at the less substituted carbon in the epoxy side. Um and so we will end up with this of hoops. So here's our C six h five unaffected by the reaction. Okay, um, and so again. The the cover lithium is gonna act as, ah, nuclear file an attack at this carbon. And so what we end up with is an alcohol here. Um, and there's our second carbon from the pox side on then. Since it was, ah, metal, copper, lithium or metal Cooperate, uh, that we were using. Um, there is our added metal group, okay? And so, um, that's the product for h. Ah. And that's the answer here. Uh, the only you know, there's no secret to these. You just need to know how these organic metallic re agents react under all of these conditions. Ah, and that's the answer to Chapter 20 problems of a 47.

This is the answer to Chapter 24. Problem number 43 fromthe Smith Organic chemistry textbook. This problem asks us to draw the product formed from a Michael reaction with the given starting materials using socks side and ethanol. Okay, um and so remember for these reactions, uh, the ah Alfa Beta unsaturated key tone is going to act a cz the Electra file, And we will form the eagle ate from the other carbon dio or night trial starting material. Um, and that's how the reaction will proceed on. So for a, uh, the product here is going to look like this. Okay, um, and then be will be the same way. The alphabet on saturated key tone is the electric file on the dyno trial compound is going to be the nuclear file. So will form the late there. Um, and so our product will look like this. Okay. Ah, yeah. And so that's the answer here. Both of these reactions proceed. As I said, by making the alphabet of unsaturated Carbonell the Electra file on then forming the final eight of the other carbon dio or nitro compound. Um, and making the product that would form by the new bond. And that is the answer to Chapter 24. Problem number 43

Name the following a meal and right Its product off Mutilation by I died forward by silver Excite this conditions for Hoffman elimination It's either determined configurations. If you look at the more nickel from this side that will produce this view or Reg and Dash formula the oldest prince fortune is three herbals well to free. So it's a derivative off propane there to figure groups it problems one and truth And the amino group. Is it carbon? What? No. Let's determine Stare chemistry for carbon one hydrogen is pointing away from us and priority off substance is decreasing in this direction which gives us s configuration. So we need toe it to the chemical name run If, for carbon tomb hydrogen is pointing toward us and well off substance are decreasing in this direction. When she gives us our however hard Dejan must be pointing away from us. It's pointed, troubled us. So we got the wrong answer. So research from our toe s So the compound will be one s two s Want to defend? You'll one I mean a propane often insulation we produce ball came leaving group which on the girls Yeah, to elimination the ways is hard Rocha group, which is introduced. So the more ritual from super oxide in the water. The reaction goes the best if hydrogen is in the employment staggered position with respect to the living group. However, you have metal in this position, so this conformation will not be reactive. A conformation change must occur to produce a reactive conformation. So this carbon rotates in those substance. They take each other places. So hydrogen goes there. It's place is taken by them for your group and myth. Um, the place is the final group. So now we have reacted information and eight to reaction. But I uses a double bond your finger groups that understand side of the bar and in the products they will also end up at the same side in the nipple group and hydrogen would under other side. So that one to the porter finals vit our highs impunity substance that each carbon they are understand. Start with a double barn. So the configuration off is out in Elkin will be easy

Okay, so problems eight. You're asked to identify the leading group and nuclear violent each of these reactions and predict the products. So in impart a this is your substrate. It's rib Ramo contains, and you're after attack it with Oh, th th three. I wish all these out of them still in reform just because I think it's easier to see then condensed form s So this is going to attack in us and to fashion because this here, shown in blue, is the nuclear file. Nuclear files typically are the electron rich cheese. In a reaction, they usually have a negative charge, but they don't have to, but they will always have either a long pair or a pie bond. The leading group is what leaves the substrate. And in this case, Sharon Green, it's the Fermi. So for the products of this reaction, you would have something that looks like this because this a nuclear file substrate has replaced the bro me in the broom in his left. Okay, In part B, the reaction substrate is claro cycle vaccines, and it's attacked with the nuclear file sodium hydroxide, inorganic chemistry. You can leave off the counter ion which in this case is sodium. So I'm just going to write the CIA files, which in this case is hydroxide. And once again, this is the nuclear file because it has the low fares, and in this case, it has a negative charge. So it's a good nuclear about, and the leaving group in this case is going to be scoring. So it attacks in s into factions and the corn grew, please. And in its place as a product, this is formed Psychlo six in all, plus foreign clients. Okay. And c, the substrate a beautiful idea. And it attacked with Eva had ion, which is in three minus. I'm gonna show you specific of the reaction, and it's gonna kick out the eye because once again, a size is famously a vile and eyes the leading group. So if on s into reaction, it will form. No, what I did, I am so in solution or D. The substrate is bro mo like waxing and the nuclear file once again leaving out the counter Ion is cyanide. So sign is going to be the nuclear file because it has the negative charge one to get it doesn't have to have a negative charge, but it has a lone pair that can react and the living group is going to be growing. So this reacts menace into fashion, looking out for me informs, but from my client, and that's the fore problem, mate.


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