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(20 pts) You place 150 mL of water at 400C in the refrigerator How mnuch refrigerator remove from the energy does the water t0 make ice at OOC? (Note 1: 1mL Hzo = c...

Question

(20 pts) You place 150 mL of water at 400C in the refrigerator How mnuch refrigerator remove from the energy does the water t0 make ice at OOC? (Note 1: 1mL Hzo = cn' Note 2: See Table 4.4 in your text 1g along with the subsequent example)

(20 pts) You place 150 mL of water at 400C in the refrigerator How mnuch refrigerator remove from the energy does the water t0 make ice at OOC? (Note 1: 1mL Hzo = cn' Note 2: See Table 4.4 in your text 1g along with the subsequent example)



Answers

You place a tray containing $410 \mathrm{~g}$ of water at $11^{\circ} \mathrm{C}$ in your freezer. How much energy must be removed to turn the water to ice at $-14^{\circ} \mathrm{C} ?$

By agreement. This is the problem based on the amount of the heat observed by the ice. At my understanding researches, you start to minus 10 to 0 little cheat 0 to 10 mhm M C Ice date 30 and the 28 of fusion and seawater Delta T masses 0.15 kg. The specific heat is 2090 and to change in temperature, keep 10 while qualified. Specification 3.33 Take the power five plus 0.15 into oh for one Nigeria in 2 10. So it is to be equal to 65,006. 55. Jordan, their son. Thanks for watching it.

In this particulary case. Here is zero daily centigrade from pastilles 15 C. The water goes to negative 15 C, so this party's water gets cold here it gets into eyes on deny school junk again. On this is basically the heat extracted from the Gold Reserve Ire which is in this particular case for the water to cool down. It would be a M C. Liquid dead that he one thus for the ice for the water to freeze. It is an Elwell, Elysa that and hit for the ice to get colder. It is M c ice does the D to now. In this particular case, we have okay that we can take the mass common. We are taking 100 milliliters of water. So 100 milliliters off water corresponds to 0.21 liter times. Juan, you know, Grandpa Leader, It was little 0.1 kilograms, so we can take the mass comin over here. That is the reported one kilogram specific hit. Off the liquid is 4200 Jules bar, kilogram degree centigrade and specifications off Isis. Half of that 2100 June barred kilogram Did we sent it dead? It just happened to be that does 31 density to both our 15 Galvin. Thus the l so we can buy them a sketchy Calvin, you know, to make it cancel. Ah, the l let it hit off. Freezing is 3.3 times 10 to the five June by the kilogram. So calculating this we get QC equals 42 seven 15 June. Now, in this particular case, we're trying to find heat exhausted into the room, which is Q age which is you see, plus double in No w in can be Didn't as you see over gay So it becomes QC. I want us one over k. So you see, we found to be 42 7 15 June Want us one over. The coefficient of performance for this engine is four. So that gives qh equals is 5.3 times 10 to therefore Julen

Solution for the able problem. You amount of feet que into heat of solid is equal to 1 27 grand. Multiply 2.6 Joel, divided by Graham into degree Celsius into zero minus minus 11. Decree. Celsius Multiply one killer Jewell, divided by those in Joel, is equal to 2.9 Killer Joel and amount of weight into melt. Man solid is equal to 1 27 grand. Multiply 333 jewels. Pro Karam multiply. One. Killer tool divided by 1000 jewels is equal to 42.3 Killer Joel and next is kun into amount of feet. Heat for liquid hello is equal to 1 27 Graham Multiply 4.1 Ad Joel, divided by Karam into degrees Celsius into change in temperature. 21 minus zero Big resources multiply one Killer Jewell, divided by thousands jewels is equal to 11 Killer Joel and near total amount of feet is equal to 2.9 Killer tall plus 42.3 Killer Joel plus 11 killed. A jeweled is equal to 56. Killer Jewell. His total amount of energy

For us to answer this question, let's call T. F. A flat T. F. B. The final temperature of the mixture. So what happens is ice absorbs hit during the true processes that his eyes. It absorbs heat from negative to one degree socials. To theoretically socials. And then it melts at this constant temperature of This is melting at zero, decrease socials. And then we hit it up to T. F. So this is heating again disease hitting. So here's what we're going to do here is we're going to assume that there is no heat loss to the surround. So looking at this we're saying remember Q. It is equal to N. C. He downtown team. So for affairs change. For example for this melting process, the Q. Is equal to and multiplied by the end of the change of fusion. So what we have here is and cp of the ice multiplied by delta T. Plus and delta H. Of fusion plus NCP of liquid water, delta T. We're now at this point this should be equal to N. C. P. Of the ice Delta team. So looking at this information, remember number of moles and is equal to mass divided by mama's. So looking at this information, we already have this is 40g. So what we're going to have at the end of the day is 40 multiplied by 3 7.7. Multiplied by zero miners minus 11. And we add 6.01 by 10 to the Power three. Also ahead seven 5.3. And what we're going to have here is TF -0°. So this should give us 250 mils, multiplied by one crime humility. Later, one grand family. This is the mass of the ice. This should be equal to or rather we multiply this by 75.3 Multiplied by 2 5 miners, T. F. So if we make TF subject of the formula party F here is going to be equal to 9.78° soldiers. So the final temperature of the mixture will be 9.78°.


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