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4.F4 #hy'"phtd #trutntum Y+*{-t24 60 Poir k)...

Question

4.F4 #hy'"phtd #trutntum Y+*{-t24 60 Poir k)

4.F4 #hy'"phtd #trutntum Y+*{-t24 60 Poir k)



Answers

Divide. $$\left(45 a^{8 k}+30 a^{6 k}-60 a^{4 k}\right) \div\left(3 a^{2 k}\right)$$

Let's solve for K. Using basic algebraic knowledge, we have three x times x minus five K is equal to three X squared minus 60 X. We want to solve for K. So let's start by trying to get K by itself on one side of this expression right here, on one side of the equal sign, we want to try to get K there so that we can solve for it. So let's start first by dividing both sides by this three X. That way we can start to limit what we have on the side with the case we're going to divide both sides by three X. This is going to cancel out and if we wanted to simplify the right side here, it's easiest. Sometimes if we split it up a little bit so we can split this into two fractions. Instead, we can have three X squared over three x -60 x over three x. And that gets set equal to our X -5K. Now, let's further simplify now. On this right hand side, what we see is that our threes are gonna cancel off here. So are one of these X terms we're gonna be left with just one X. Instead. So we have one X left over. And then in the second fraction we see that our exes are gonna cancel again. And then we're left with 60 divided by three and 60 divided by three is equal to 20. So we have X -20 is equal to X -5K. Now. Now let's start with this piece by subtracting X from both sides. Right That way we can get rid of these X terms we're left with negative five K. Is equal to x minus 20 minus X. Can see on the right hand side now a positive x minus x cancels those out. We have negative 5K. is equal to negative 20 now and now all we have to do is divide both sides by this negative five so we can get K all by itself. And if we take negative 20 divided by negative five, we can see that K is equal to a positive for because the negative divided by a negative will give us that positive.

So I have 1 80 equals k over 20. And so to solve this, you would multiply both sides by 20 en que would equal 3600.

So we're acts to solve this equation. But first we want to do is make sure that the variables are on one side and the numerical constants are on another side so we can go ahead and solve for K the first thing we want to do. It's a track 30 from both sides, right, because we want to make sure that two K is on one side. So whatever we do on the left side, we have to do that same thing on the right side to make sure that the equations are still matched. So this will pretty much give us two K is equal to 1 80 minus 30 which is killing toe 1 50 Now we want to get K by itself. To do that, we have to divide by two. Whatever we do in the less shy we have to do on the right side. So we're gonna also divide 1 50 by two. So that gets us K by itself. So okay is equivalent to 1 50 divided by two, which is equivalent to 75

Okay, so I've been given to algebraic fractions. They won't be last to divide one by the other on the way we're gonna do that is we're going Teoh first, change this divide to a times. I'm gonna flip the second fraction upside out, and that will be the exact same question. So what I mean by that is we can keep this destruction the same. So 42 K 6 k to power 6/25 on the second fracture, we're gonna flip you upside down, so it could be 35 of 12 k squared, and then we could just answer the question like a regular fractional modification. Okay, so on the top here, I'm actually going to, um you like, calculator for this if you give me more moment. Okay. So I've got my calculator now 42 times by 35 on the top here. So that's going to be 1470 k to car six. So it times are too numerous together to get a new numerator. Same with the denominators. So 25 times by 12 going to 300 k squad. All right, and then we're looking to simplify with going to start with these K case of these two cases, both the top and the bottom. So I'm just going to divide by K squared on the top of the bottom here to get one for 70 cape about four over 300. Divide by 10 here to get one for seven cater power for over 30. And then I believe both the top in the bomb could divide by three here because this is 150 minus three. So it's gonna be and 49 k to the power for off a 10. Uh, I don't think that divides any further. No. Okay, that's the answer. If you have any questions about any of that, make sure to email. May Daniel Dr. P. Hate, don't Nola out. Gmail Don't come. Thank you very much for listening. And I wish you the best for your studies.


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