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16.96. If only 0.160 g of Ca(OH)2 dissolves in 0.100 L of water; what is the Ksp value for calcium hydroxide at that temperature?...

Question

16.96. If only 0.160 g of Ca(OH)2 dissolves in 0.100 L of water; what is the Ksp value for calcium hydroxide at that temperature?

16.96. If only 0.160 g of Ca(OH)2 dissolves in 0.100 L of water; what is the Ksp value for calcium hydroxide at that temperature?



Answers

If only $0.160 \mathrm{g}$ of $\mathrm{Ca}(\mathrm{OH})_{2}$ dissolves in $0.100 \mathrm{L}$ of water, what is the $K_{\mathrm{sp}}$ value for calcium hydroxide at that temperature?

Hi. Given the information we are going to solve for K S P for a solution of calcium hydroxide. So the first thing that we need is an equation. So starting with an equation, we have calcium hydroxide beginning as a salad. When that is placed into water, it's going to disassociate. And we're going to get calcium ions that are a quiz as well as to hydroxide ions. But you're also Aquarius. Now that we have our equation, we can write our equilibrium. Expression are equilibrium expression. Who's going to tell us that K. S P is going to be equal to the concentration of the calcium ions? And that's gonna be concentration in terms of polarity multiplied by the concentration of the hydroxide ions. Since our balanced equation has a two in front of the hydroxide in our expression, we're going to need to square the concentration of hydroxide, right? The next thing we need to do is calculate Armel Arat e from the information that was given. We were given 0.16 programs of the initial calcium hydroxide and we were told that it was dissolved in 100. I'm sorry. 0.1. Leaders of water So remember mole Arat E is moles per leader. Right now we have grams per leader. So to convert this two moles per leader, we're gonna have to divide by the molar mass of calcium hydroxide. The molar mass of calcium hydroxide is 74 0.1 g per mole. Our grams will cancel and were given the units moles per liter. In our answer, calculating this we get 2.16 times 10 to the negative too. As our modularity of the calcium hydroxide. I can't move. Let's go ahead and make ourselves for our next step. Our fourth step Here is our first step. We wrote our equation Our second step. We wrote our equilibrium expression Our third step. We calculated the mole Arat E Now we're going to do our ice table or I stands for initial change and equilibrium. So let's look at this for each of our substances calcium hydroxide or calcium and our hydroxide. Remember in that both of these air Aquila's because they're now dissolved. Okay, So initially we started out with our calcium hydroxide is a solid since it was a solid and it wasn't dissolved yet. Initially we had zero as the concentration for the calcium and the hydroxide. Then we went ahead and we dissolved all of this. It said that that was the maximum amount. So we knew that exactly that amount did go ahead and dissolve. And we calculated that number to be 2.16 times 10 to the negative. To Moller, the calcium ions then would be 2.16 times 10 to the negative, too. Yeah, and the hydroxide is gonna be two times that amount. Because for each calcium ion that is produced, there are two hydroxide ions produced in solution. So that's gonna be 4.32 times 10 to the negative second again, I just multiplied the polarity by two. So I equilibrium. We will have zero are solid remaining. We will have 2.16 times 10 to the negative too. S similarity for the calcium and 4.32 times 10 to the negative too as the polarity for the hydroxide. Now we can plug this into our expression for K sp. So our k sp told us that. Roll it back down just a little so you can see it. All right, so it told us to take the concentration of the calcium 2.16 times 10 to the negative, too. Similarity. And And multiply that by 4.32 times 10 to the negative second. And remember, the O. H is squared. So we need to square this value. All right. Pulling out our calculator taking 2.16 times 10 minute give second and multiplying it by the square of 4.32 times 10 to the negative. Second, we will arrive at R. K s P and R K s P is going to be 403 Tom's 10 to the negative fifth. All right, thanks so much for watching. I hope you found this useful and have a great day.

This calculation is pretty straightforward if we write Caspian terms of Moeller Celje bility, but let's first calculate Mueller scalability. If we know that 1.78 grams dissolved for leader, we can convert the grams into leaders by dividing by the molar Mass and we'll get 2.40 times 10 to the negative To Moller for that Mueller Celje bility Caspi is going to be equal to the calcium concentration multiplied by the hydroxide Concentration squared calcium concentrations gonna be equal to the Moeller Celje bility hydroxide. Concentration because we get to hydroxide is for everyone. Calcium hydroxide that dissolves is going to be equal to two times the Moeller Celje bility and then we'll square that whole thing. So K SP is going to be equal to 5.55 times 10 to the negative five.

To calculate case really simply first need to calculate more scalability. Mostly ability is the moles of the compound that dissolved in a leader. We weren't given moles, but we were given grands weaken Comfort the grandes into molar mass by dividing by the molar mass of the compound calcium hydroxide which is 74.93 We get a Muller Celje bility of 1.75 times 10 to the negative too. Because chaos P is equal to the hydroxide Concentration squared, multiplied by the calcium concentration and the calcium concentration is the Moeller Saudi ability. Because we get one calcium ion solution every time one calcium hydroxide dissolves but we get to hydroxide Zand solutions hydroxide concentration is twice the Moeller Celje bility. Then of course we need to square it. So we get four s Cube s being 1.75 times 10 the negative two or kspn. Whatever this temperature is is 2.16 times 10 to the negative five

To calculate the molar scalability of calcium hydroxide in a solution that's buffered to a pH of 10.60 who recognize this is the case. P expression and hydroxide concentration is going to be equal to K W, divided by the hydro knee um, concentration, which is 10 to the negative. PH where we get a hydroxide concentration of 93.98 10 of the negative, too. So we'll look up our case. P value for calcium hydroxide set that equal to the calcium concentration, which corresponds to muller scalability. Because every time a calcium hydroxide dissolves, we get one calcium multiplied by the fix hydroxide concentration at 3.98 times tend to negative two, and we square that and we get a Miller Sally ability of 3.47 times. Tend the negative to Moller.


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