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8 My Notesanoic; antbu-IuuUU 453 1 uoju belween thc tolla ing 1 1 Serpgito Lonpluu Prewous Answers Jele ) 1 points 11 1 124 I...

Question

8 My Notesanoic; antbu-IuuUU 453 1 uoju belween thc tolla ing 1 1 Serpgito Lonpluu Prewous Answers Jele ) 1 points 11 1 124 I

8 My Notes anoic; antbu-IuuUU 453 1 uoju belween thc tolla ing 1 1 Serpgito Lonpluu Prewous Answers Jele ) 1 points 1 1 1 124 I



Answers

Line $1 :$ Passes through $(-8,-55)$ and $(10,89)$
Line $2 :$ Passes through $(9,-44)$ and $(4,-14)$

Now in this part we are asked to find out the yellow respect. You'll notice right the sequence of the reactions of the year being N no three or two. This upon hating will produce. Yeah, mm. No, this is a fun reaction were diluted. Well you the the L two. No, we have video on reaction with alimony, um ammonium carbonate, ammonia carbonate. This will produce, he is C. 03 This is uh now this upon reaction will dilute at cl will produce S E L two B S C L two. Upon reaction with potassium promenade this will produce E A R Bs er of or no B S C R. O. For upon reaction with dilute sulfuric acid, it is a source of work. It will produce B. A. S. Awful. So this is Yeah, this is the better answer. E. S. 04 Yeah. So far is there direct And and this is this is the final product. But we're asked to find out the yellow pre speed. So this is the yellow principle. Hello, is it the B A c R 04? P a c R O Forest to Yellow Pre spirits. So let's check out the options. We see. Obscenity is going to Son. He is going to B S c R 04 is uh, yellow precipitate.

We have this flow chart and we have to find the output of this flow chart. So let's start executing this flow chart before we execute each operations. When we want let's try to understand what exactly this flow chart does. It starts with the start command, then we have some operation box. We're in the values of A. And the ceo initialized and then some genius to diseases squired and then added with A. And is in fact doubled over here. And then it checks whether the value of a is still less than eight and when it does it will go ahead and or do these operations once again. So basically we have a loop over here It gets repeated as long as the value of a. is less than eight. once the value of is not less than eight. That is If a is either eight or anything more than eight like 9 then the local stop and it will start printing the value of C. So let's start executing this one x 1. So initially the value of the equal to one & C Equal to two. And when it comes over here the sea is getting updated by squiring the value of C. And then added with eight. So when we square the value of C we get to square is four. And when you add with a that is one we get sequel to fight. So therefore the current value is equal to five. And the next statement we have A is doubled. So equal to a start to, this is basically is getting double Which means this is the initial value of eight and double it will get to. So therefore these are the two values which we have done now. That is equal to five and equal to two. Well then how this decision box which checks whether it is still less than eight, Which is in fact true, that is two is less than eight. Yes. So that means the control will be shifted back to this point which means we are into the next to loop. So in the next two loop, let's write down the current values of AIDS and sees. So is already updated too two and she is now updated to fight. So these are the values that we are going to it place when we place this look. So then once again she's getting updated by squiring the sea and adding with a which means the sea will be square. That is five x squared. So therefore if you do that it will be 25 Plus getting added with a. That is too. So this gives value. See the new value of sequel to 27 And once again is getting doubled. So this is the value of a. That is too when a double two will get a call to four and once again we check whether still If a is to less than eight so is less than eight. Yes this is is therefore the control will be shifted back to the this point which means we are into the next loop. So let's write on the existing values of A. Or the updated values of A. And C. You know that this is the an updated value of we put here And c. is 27 so we put the C over kid And then once again the sea is getting squired and added with a. Which means c equal to 27 Times 27-plus 4. So when it's choir 27 This is equal to 729 plus food Which is equal to 7:33. Therefore the updated value of c equal to 733 and still and then the next statement we held this getting doubled as usual which means this four is getting doubled so therefore equal to eight now. And we have this decision is eight less than eight. No it is not. So therefore the loop will stop over here. It will come out of the loop and it will execute the next statement which means it prints the value of sleep. You know that the greater values equal to 77 33. So therefore at this point the computer will print the value 733 which means this option is correct

So in this problem we're given this rational expression Um and were asked to graph it, analyzing graphic using the steps given in the eight steps given in the book. The 1st 1 says to factor and determine the domain. All right. So the numerator, X cubed minus one. This is the difference of two cubes. Which factors into x minus one times X squared plus. Thanks. Plus one. Okay then the denominator, X squared minus nine factors into X plus three And X -3 because it's the difference of two squares. Right? All right. So, our domain means I can put any value for X. M1 in here. But remember I cannot divide by zero. So, X can't be three or negative three, can it? Because the denominator would be zero in that case. And so the domain end is from minus infinity to minus three For -3-3 And 3 to Infinity in it. Let's begin drawing a graph over here. Then here's X. Here's why And here's three and here's -3. Okay. Step two says to write this in factored form. So that means I have X -1 times X squared plus x plus one over X plus three Times X -3. Okay, Step three says to determine the intercepts. Okay. And the x intercepts happen where The numerator is zero. Well, where does that happen? Well, that happens at X equals one. Right. So at x equals one 21. Right here, I have that point. Okay. And X squared plus x plus one. There's no other real number that I can put in there. That will get that to be zero. Um mm hmm. So I can't ever make that polynomial B0. So I only have one x intercept. Yeah, one or something. Mm. What about when X is 0? What happens? Well Then I get -1 times zero plus zero plus one. That's one over. And then I have zero plus three. So that's three and zero times minus three X minus three. So I get negative over negative so it becomes positive. So I get 1/9, don't i? Okay. So If one is here, right? That's one one. Then when X was zero, I got one night. Which means I went through like right here, didn't I? Okay. So there's my two intercepts and assist, analyze the behavior around them. And so what do I notice? Well, when X is between one and 3, what happens? The numerator is on positive, isn't it? And the denominator. Well, what do I get here? I get a positive and then I get something that's negative, don't I? Because it's less than three. So when I subtract three, that's negative. So this is something negative. Which means this is falling off this way, isn't it? Okay. Well, what happens when X is between zero and -3. Okay. Well, let's see. So then the numerator is negative times what? Well, let's see if I had like negative two in there. I'd have four -2. That's two plus one. So I'd have some positive number one over. Okay, so remember I'm negative but I'm something less than Something between 0 -3. So that means this first component is positive And the next one is negative. And so this is all positive in it because the positive the negative or negative would be positive. Okay, So that tells me that this is going like this. Right? Well, something like that. Okay, Number four says to do the vertical ascent totes All right, well, I know I have one here because I can't be that van I have one here so I can't be that body. Right? All right. Now then Next one says to do the horizontal assume totes Okay, well let's see this is got a higher degree in the numerator than it does in the denominator. And so this is going to do what? Well, as X gets bigger and bigger and bigger. Right? His ex goes to affinity than our function H of X. There's also going to go off to infinity. And Okay, let's see. And when x goes off to negative infinity then our function we'll go off to negative infinity as well, won't it? Because the numerator run off faster than the and the denominator. Okay, so let's figure out now what happens when we get closer to these assume totes to the vertical ascent bodes well, let's see the numerator. See if if I come toward X goes towards three from the right, What happens up here? I end up with some positive number here. Some other bigger positive number there and then down here I have A number close to six. But here I have a little itty bitty positive number. So this is going to run off to infinity in it. So I'm going to go off that direction, aren't I? Okay. And what happens when I go? Well X goes to three from the left. Okay, so what have I figured out so far? Well, I figured out that I'll get close to assassin. Tote of three from the right and I'm going to infinity and his ex gets bigger and bigger. I'm going off to infinity that way as well, aren't I? Okay, We're not three from the from the See this is -3 and -3 from the left. Well, so the numerator is a negative number times a positive numbers. That's negative. And the dominator down here, I have again a negative number. Okay, so that's thank you for negative, that's positive. And then what happens? Well, well, this is a negative number as well. But what what happens when this expose 3? Okay, so I'll be negative but then I'll have a little itty bitty negative number at that. I'm dividing by which means I'm running off towards negative infinity, aren't I? Okay. And we already said that when I go towards negative infinity, I go off that direction as well? So kind of get the sense right that this does this, doesn't it like that already, don't we? six was to divide Step six was to divide in the intervals and determine above and below where we did that and seven was to do near assume totes, which we just did as well. And then eight was to finish, Okay, so there we go. There's the graph. Right, interestingly enough, I went to Desmond's dot com, then pull down the graphing calculator and graft and look at that. Sure enough, you see what happens right? The centerpieces, what we talked about what we showed and then the right hand side over there and left hand side over there are what we showed as well. So there's just like our graph is

So here we just want to write all of our numbers in scientific notation. So for part A, we have 1.156 and this will be equal to 1.156 times 10 to the next tent times 10 to the zero power tend to the zero. Power would be equal to one, which would be one times 1.156 equal and, of course, 1.15 sex for a part B. We have 21 point eight and we need to move the decimal place over to the left. One's the one place, so this will be 2.18 times 10 to the first power. For part C, we have 0.68 We have to move the decimal place 12123 places over to the right. So this will be 6.8 times 10 to the negative Third tower. Ah, for Part D, we have 328.65 This is giving us 3.2865 times 10 to the second power. Ah, for E. We have 100.219 Yes, and move that. That's my place over to the right one place. This will give us 2.19 times 10 to the negative first and then fear part F. We have 444. We have to move the decimal place over 12 spaces. So this will be 4.44 times 10 to the second power. That is the end of the solution. Thank you for watching.


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