Here were asked for the major products obtained from the reaction of each of these compounds with one of Corbyn of HCL, and they were also asked to indicate the kinetic and thermodynamic products. The first one is to three dimethyl 13 pence a dying which I've drawn on screen here. And so we're gonna number this or we're gonna number are dying one through four. Just those four carbons that participate in the dying and we're gonna number. It's what we get the most stable carbon cat I in, uh, couple Catalans overall. So if I go from this side, my car broke a tie. Ins are always on carbons two and four. So if I go from this side over here, I would have tertiary on two and a secondary on four. If I went from the other direction, I'd have a tertiary onto in a primary on four. So I'm gonna go from this direction, so I get tertiary and secondary instead of tertiary in primary. This will be one too 34 on, and then the first step is to have that 12 double bond. Grab our hydrogen off of the chlorine and give us A car broke out. I am so that carbon cut. I would look like this, um, be hydrogen here. Went on to carbon one is that we can have the call carbon to be the carbon cat I And since that will be a Lilic, um, so that is our first intermediate. And then there's this also has a resonance contributor. If we move that double bond right there and that residents contributor looks like this, it's no never bonds here, and our car broke out I and is up here and then we'll get a product from each of these just by attacking the car. Broke a tie ins with the C L minus the Korean nuclear file that was left over from the HCL. So from this top one right here will have the chlorine on this carbon up here and are double bond stays over here. This is our 12 product, and then from the bottom, we will have double bond right here and a chlorine over here. And this is our 14 So a zipper, kinetic and thermodynamic, the one to product is always the kinetic product. Who's, um now, keep in mind that the Connecticut promoting them. It could be the same products. But the kinetic product is always 12 because of the proximity effects soapy for proximity effect. And that just means that because when this hydrogen is pulled off the chlorine, the Korean then is right next to this carbon cat are in a position to. So it's really easy for just going attack just because of the proximity. So that will be the Connecticut product. And then the thermodynamic product is going to be the most stable product on. And we're talking about thes reactions that usually means the most stable out keen. And so here the most Abel Kane is usually going to be the AL Keen. That is some of substituted, Um, and so here, that is going to be the 14 So this will be our thermodynamic product because the Al Keen is more stable. Um, and then let's part want our part A and then for part B, we're going to the same thing. We're gonna number our, um, carbons to get the most stable carbon cattle. And so if I go from the left here, I would have tertiary on number two in Turkey. Area number four. I went from the right. I would have secondary unto in primary and four, so I definitely want both of those tertiary res. So we're gonna go this direction and then do the same process so my one to bond will grow up the hydrogen and kick off that chlorine and we'll get a carbo cat ion that looks like this for that one and then not will have a residence contributor. That looks like this for that over here. Um, and if you'll notice these, they're actually the same thing. Just flipped over. So if you were to have your hand on a table with your palm facing up and you flipped it over so your problem is facing down, you would get, uh, the other version of this actually, the same the same structure. So, um, here we're actually on only going to get one product. It's what that is the 12 and the 14 product. It will be exactly the same. Um, and so that products. Oops. Well, look like this. I'm just gonna draw it on this side of the glory will be here, and the double bond will be over here, so that is our products. That is obviously going to be both the kinetic and thermodynamic products, since it is the 12 and the one for product. So this is Medic and thermo, since it's 12 and 14 at the same time.