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Plasmid that is 4000 base pairs contains BamHI restriction site 350 bps and two Pstl sites at 2100 bps and 3200 bps_ After complete digest of the plasmid by both re...

Question

Plasmid that is 4000 base pairs contains BamHI restriction site 350 bps and two Pstl sites at 2100 bps and 3200 bps_ After complete digest of the plasmid by both restriction enzymes, what size fragments would you expect? Select one:350, 800, 1100, 17501100, 1150, 1750olud1750, 2250d. 1150, 2850Iw34000,2100, 3200Clonchoice

plasmid that is 4000 base pairs contains BamHI restriction site 350 bps and two Pstl sites at 2100 bps and 3200 bps_ After complete digest of the plasmid by both restriction enzymes, what size fragments would you expect? Select one: 350, 800, 1100, 1750 1100, 1150, 1750 olud 1750, 2250 d. 1150, 2850 Iw3 4000,2100, 3200 Clon choice



Answers

You are studying a circular plasmid DNA molecule of size 10.5 kilobase pairs (kb). When you digest this plasmid with restriction endonucleases $B a m \mathrm{HI}, E_{\text {ro }} \mathrm{RI}$, and HindIII , singly and in all possible combinations, you obtain linear restriction fragments of the following sizes: $$\begin{array}{ll} \text { Enzymes } & \text { Fragment Sizes (in kb) } \\ \hline \text {BrmHI} & 7.3,3.2 \\ \text {EroRI} & 10.5 \\ \text {HindIII} & 5.1,3.4,2.0 \\ \text {BamHI }+\text {EcoRI} & 6.7,3.2,0.6 \\ \text {BamHI + HindIII} & 4.6,2.7,2.0,0.7,0.5 \\ \text {EcoRI + HindIII} & 4.0,3.4,2.0,1.1 \\ \text {BamHI }+\text {EcoRI }+\text {HindIII} & 4.0,2.7,2.0,0.7,0.6,0.5 \end{array}$$ Draw a restriction map for the plasmid that fits your data.

Yeah. Mhm. The given problem is we have to make a recommendation with the human DNA and a plasma. It so both have a restriction site of. Yeah. Cool. What one and and three. So how this recognition is made. So both the human DNA and the plasma. It must have a have the sticky and how this thickened is obtained. So when the same restriction enzyme is used for both the human DNA and the plasma and then we get a sticky end so they are complemented each other and they stick together to make a recommendation. A when we see about the C. E. Carbon, it has a restriction site. G. E. T. T. See C. T. T. A. And she now the Saudi carbon cleaves between Gmd gone in and At the nine so it clears and it forms overhang with a three prime. And for this hindered three, the recognition site is yeah. G C pt pt see T. Yeah. Here the henrik lives between a and forms a fire prime overhang on DNA and produces a sticky end. If the same restriction enzyme is used for the plasmid and the human DNA, then it forms a sticky end and they complement each other and they can former recombinant DNA. So I'm discussing the options. The first option cut the plasma. So here uh echo array for the plasma and hinder three for the human. So this is the wrong answer. Why? Because uh these are different restriction and sam used. So this is the wrong answer. Now, when we talk about the option B. You see Karen to cut both the plasmid. So this is a Right answer because both are restricted with the same restriction enzyme here, the same thing Hinder three plasma and human DNA are both cut with the same enzyme. So this is also the right answer. So option D. A. Or B is a cut plasma T car one and B. This is all. This is a wrong answer and option E B or C. Okay, so be or sick and with the right answer. So this is a right as a BRC. So, uh, the right answer for this option is on the whole, let's eat B or C is the right answer for the given question.

Already. So here we're looking at, um, genetic analysis and in particular, the electrophoresis. So we have a, uh, piece of DNA, which pants sell sort of put off to the side and vertically. And three ability to sort of split it. We're using the restriction sites at with a two que be peace A for KB size piece killed this piece and a five. All right, CBI size piece. And so part A says this piece of DNA is cut just in this normal expected distribution that we are given in the problem. So what will the gel look like? So, for part A, we're gonna get lines at the length of these pieces. We would expect to see one at 21 at four. And one at five. Okay, So then part B says so. It's a mutation alters at site one. Okay. And site one was his first one. Now all of the banding look like Well, so there's a mutation there. Then it's not going to get cut there. Okay, so this first piece ends up being six k b in length, and then we start the second piece, which is five. So then we head onto part. See similar question. Let's say there's a mutation in both the first and the second one. So now we're not getting this DNA cut at all. The total length then is going to just be 11 and that that's it for that piece. Okay, so then we go into D. And this one says, if 1000 base pairs of DNA were inserted between the two restriction sites, So now we're adding 1000 to this one. What would the banding look like now? We're assuming that both of these cuts are going to occur still, So we still have our to K V and R five K be paid pieces that we need to add 1000 to the four key piece, but that's gonna make it five as well. So we're gonna put two bands at the five mark, And so what it would look like to the technician is just the two band showing up and then last but not least, we're adding 500 base pairs. We're not adding or subtracting. So 500 base pairs between the two restriction sites were deleted. Then what happens? So instead of adding 1000 were subtracting 500 s in this case, we're still gonna get R two and R five pieces, so we'll just go ahead and write those than the four were, you know, subtracting 500 from. So instead of being at four, it's gonna be at, like, 3.5, so be a little bit lower than the one in a

Okay, so this problem is asking. Or restriction enzymes should be used to cut both the DNA sequence and its plasma in order to make a common in DNA or common in sequences. So an important role that we need to remember is that the same restriction enzyme must be used to cut the plasma, it and the D. N. A. Because it will produce fragments with complimentary stickiness. With this being known answers B and C are both correct making answer E the correct option. It doesn't matter what restrictions when you use, as long as you use the same for both the human DNA and the plasma. Okay.

Hey everybody. So today we're talking about um basically the transference of bacterial plasmid DNA. And human DNA. So our question is helps. So okay so now we have some options and we're supposed to go through them. But I did write to beg so let's zoom out, move it up and get back to drugs. So option A. Is DNA proliferate. I'm should be R. N. A. Glamorous. See who wait, what would be I was incorrect. Our guys DNA lie gaze see is RNA polymerase, G. Is restriction enzyme. Okay, so let's figure it out by thinking about what this would be. So and what subject they're getting into here? Um This is what's called genetic engineering, meaning we are using genetic materials to make something. Okay. Um It's important for a lot of reasons but one of the main reasons is research. PcR is a common technique used for genetic engineering. So let's get into it. Um What is DNA polymerase? This is used specifically in PcR for amplification of DNA? Uh So that's gonna be wrong because we're talking about amplifying. It's not the thing that's gonna be facilitated. So DNA ligas I'm DNA like gays is the thing. Think I'm trying to think of how I remember it to be honest with you. I think I think of like pace which makes me think of lipids which makes me think of fat which makes me think of stickiness but that probably isn't that so maybe licking like like gays lick or something. Just just know that Lie gazes. Something for joining DNA segments which makes it most likely your answer. But we'll get into that the second aren't a plum race. Um It's the enzyme that is used for synthesis of RNA. So. No it's not gonna be right. I think polly makes me think more or multiple. So making amplification. Yeah restriction enzymes obviously going to be wrong. Um This is for cleavage so it's kind of the opposite. So the answer is going to be B which is DNA legs. I hope you learned something. Have a great day.


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