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Vnihreepnde70lkin titeuntOunchiotulDrodi'ciloYndLocctum?dVeHtVR, anJ € NMR spocira idenldyccmocudHaURCNAR -CHCH OH(CiuACHOHCHSCHsCICiojh...

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Vnihreepnde70lkin titeuntOunchiotulDrodi'ciloYndLocctum?dVeHtVR, anJ € NMR spocira idenldyccmocudHaURCNAR -CHCH OH(CiuACHOHCHSCHsCICiojh

Vnih reepnde 70lkin titeunt Ounchiotul Drodi 'ciloYnd Locctum? dVe HtVR, anJ € NMR spocira idenldy ccmocud HaUR CNAR - CHCH OH (CiuACHOH CHSCHs CICiojh



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licre the ycllow and orangc precipirares arc, rcspectively (a) $\mathrm{Na}_{2} \mathrm{Cr}_{2} \mathrm{O}_{2}, \mathrm{~K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{-}$ (b) $\mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}, \mathrm{Na}_{2} \mathrm{Cr}_{2} \mathrm{O}_{2}$ (c) $\mathrm{Na}_{2} \mathrm{CrO}_{4}, \mathrm{~K}_{2} \mathrm{CrO}_{4}$ (d) $\mathrm{Na}_{2} \mathrm{Cr}_{2} \mathrm{O}_{2}, \mathrm{~K}_{2} \mathrm{CrO}_{4}$

This question asks us to predict the in the most picture off given chemical structures. So we're going to predict the Proton NMR spectra. He's done the chemical structure. So the first molecule that they have to work with is, Ah, I'll cry, bro. Might That has to Rome in substituted in set up to hide regions. So it's, uh um Bill Dan, which means that it has full carbons in the carbon chin and there are two Romans on the terminal ends. So as we look at this molecule, closely be contend that there are two types of protons in this molecule, the eight i protons, which are adjacent, uh, to the bro. Me and the beat I protons, which are further of an inch diameter terminal grow, means so they are going to get two signals for the two types of programs. We can tell that the men next, let's try to figure out, um, the number of peaks each signal is splitting toe. So the radar prudence we're splitting toe a number of peaks based on the number off neighboring protons it has, and we can see that vote anytime. Photons have two hydrogen neighbors coming from the beat I protons. So to class, fun is going to be three. So the eight i protons ability Bryce to a triplet. Considering the beat I broke Aunt, we can consider them as one big group and only look at the eight I Proton neighbor, because this vase equivalent of the speed we don't have to consider the splitting between will be type protons. So we can just look at the eight i protons and again that are due off, um, them in each ISS. And so beta protons Well against letting to a triplet from two glass fun from the top brass mango. And, uh, the difference between the two triplets is going to be that the chemical shift off the anti protons, maybe further down feel compared to the beat up protons. Because the anti protons are really close to the Electra negative moments that will be sheeted them so he can tell her that we're going to have new signals. Each of them are going to be speaking to triplets. So that's how that can. But I know so this would be for a and this obey for B, and the integrations will leave on to one because we have four anti protons and four peter protons. Next, we have to, uh, figure out approximate frequency off the chemical shift. So the anti protons, we we know for sure that that it will be downfield. But if we look at a table that gives us a number for the chemical shift off brood on, that is, uh I just sent to a broom in our proton that is bound to a carbon that is also bound to a broke. We can see that it could be between for and 2.5 BBM so the chemical shift will be became for and don't find RPP. And for that, and, uh uh, the diaper dons are further up feared we'll have a chemical shift close to one going to be PM So let's move on to the next molecule. And this is, uh and either that also has ah grooming for attached to it and the stock. So looks like this as ah Terminal do group. That is bone do on oxygen, which has ah methylene group next to it on the other side. And then those to mercy edge to metal in groups before this and the trouble mean I don't the number of different types of carbons here. Ah, so the metal pro dance are their own kind. We can deliver them it. And, uh, methylene protons here will be different. But the two protons we consider equivalent to each other, so there they can be labeled as B union. This is the two protons here will be a couple into each other, but they will be different from and be. And, uh, methylene I just sent of the booming will have a different kind off. Well done. I actually do, Ah, protons that I quibble into each other, but different from everything else. So if we just started to think of the chemical shift for each of these, um, the most balancing a signal is going to come from, um the B dy protons, which are I just sent to the oxygen. Next, it's going to be the d type protons with charges into the blooming. After that, it will be the middle group protons. And finally, it's going to be this singer Madeleine Group, which is our surrounded by other carbonates and that former give rise to an upfield signals show. Next we can consider the splitting from each type off throw don. So this is the kind cargo shift. If I consider the splitting, the anti protons will be a single it because they don't have any adjustment. Hydrogen beat I prudence have to see that I protons I just sent of them so it would be too blessed. One, but you play it. The leader protons again have the C type protons at just endure it and that are two of them. So that would also be a triplet. But this sea diver Dunn's have, um two dives of non equivalent neighbors. So it will be actually two plus van, which is three times if there are the two plus front three. So if we see are clear splitting for the sea dive, bro, don't. We must see nine picks, but usually because, uh, coupling constants can be similar to each other. There's going to be a lot of overlaps and BBC less than nine Biggs nine. Split big. So we can this consider that to be a my deep let So let's try to draw the spectrum corresponding to this mark. You, as we established the B dy protons, will be the most down food downfield and their former chip let in man the D type Rodin's to. And that will also again for Major Black. And then the single it coming from the method brought dons. And then we'll have a modular that has something close to nine weeks but can be much less than that. You drew severe overlap off the peaks, so let's go ahead and liberties every day and see Next we can do is record the number of firm record integral ratio from this. So the integration usually tells us the number off protons under each category, so that are to be die protons. So just you guys toe Yes, you off to And then that, uh, to be type dancer again to And then did he make the protons? There's every three and then there'll be again. You want McGillin for dance corresponding to the might deflect. And if they had the O, I guess the chemical ships off each of these the be that prudence. They will have a chemical shift near three point lead bps and ah di type protons and have a chemical shit close to. So even if you have a chemical ships between the 0.3 and to find fright because the 0.5 this kind of the lower managing for her pro down that this bound or carbon that is also bound of Roman at the and then the motive. Ah, from dance that I just sent into the, um, oxygen. It never be here then, Mia, did he find three? So he can just disregard this spot and say that all of these are close to 3.3. And so obviously the BD and A peaks very close to each other, but they'll be in the order that we've drawn them in and finance see die protons coming from the strengthening group over here. I didn't have ah, uh, chemical shift Nia run point for I do 112 creepier. So don't sada to NMR Spectra hired. Expect for these two molecules, along with their approximate chemical shifts and their integration of the integrated issues and the split patterns

Okay, This problem is asking us which of these molecules between all four of these is my m ing going to naturally to tomorrow's into. So let's go ahead and define a couple terms here. First off to Tom Rice or to Tamar Ization is essentially I saw memorization, right? Because whatever we have right here in this case, we have an I mean, the Tomur, the Tanamor is going to be in equilibrium. It exists in equilibrium with my I mean so in order to exist in equilibrium, that means that we're going to have basically the same atoms as we do in this. I mean, but just in a different order, right, we're gonna have different connections. Basically another item, er which is going to be called the totem. Or in this case, so we're looking among all these molecules, Which one has the same atoms just in different connections. So over here we have an oxide. Does this have the same number of atoms in the same type of atoms? The answer is no, because we have an oxygen here that is simply not a cook cook component of Miami. So this is not going to be an option. Next step. We have a hydro zone. Is this considered to be the same atoms as we do in my me? The answer is no. Because we have another nitrogen, right? We have the extra nitrogen. That is not a option. Next up we have this semi carpet zone. This is obviously not the right answer because this one has way too many nitrogen, right? We have one too many. This is not gonna be an option. The last option is my enemy. So does this have the same number of atoms? Same type of atoms and just in different connections? The answer is yes. So it's going to be my enemy. And what is that? Because if we're to simply use a base, for example let's go. You had a user base. My bass is able to Deep protein ate the aesthetic proton associative right here. So this is analogous to my alfa hydrogen usually associated with carbon nails. So I'm gonna take off the hydrogen. Moving the electrons onto this carbon or another way I can show is to move these electrons onto the single bond to create a double bond. As I do that, I'll have to move these electrons up to this nitrogen to produce this intermediate in which I have a nitrogen with a single bond because it has a negative charge. My method group right there and then my double bond right there. Right. So this is very, very similar to my enemy, which I have drawn right here. The only other thing missing is the presence of the hydrogen, which can simply be used over here. We have HB used from the protein nation of be in the previous step that can simply get pregnant by HB to eventually form my enemy shown right here. So this is a Tanamor because this exists in equilibrium, right? It just depends on the reaction conditions. But normally we're going to have my maybe the most stable form that is going to be the one that is present in the greatest excess, right? So enemy and I mean those are taught Immers, and they're going to exist naturally.

In this problem, I'm writing the reaction. So just look at it carefully. After that, I will explain it Here to see our two oh seven plus six as to plus four. Any cl will react to give two k h s 04 plus food any Edge S 04 plus two c r +02 Cl two plus three H +20 So he has read of her personal due to see our or two CL two when this paper at barged through any O h a yellow solution of any at any to c r o. Forage produced. So according to the option of some A C B are correct. I hope you understand the solution of this problem.

In this problem we have to find resent that can be used to convert one. I saw pro pile cyclo painting. Yeah, this is cyclo painting and this is I saw profiled psychlo painting to convert this elkin into Yeah. Mhm. One I saw profile Saif low paint a normal And we have to find this reason. We know that Elkins react with water in the presence of is seed. Yeah. As catalyst. Okay. Mhm. To form alcohols. Yeah. Mm The addition it's cereals. This is the police. Okay, takes place. Okay. Mhm In accordance with mhm True. Mhm marconi cloves rule according to my clinic offers rule during the edition two un symmetrical Calkins negative part of addendum gets attached to that carbon adam which has a lesser number of hydrogen. Therefore, you're looking in case of a stool or its minuses negative part of a random which goes to this carbon which has listened number of high rosen. Yes, suitable day isn't is it's too when you get in with dilute H two So 4. Mhm. Therefore answer for this problem is option deal. It's too with diluted H two so 4 Can be used to convert one I suppose pile cycle of painting two. When I saw profiled psychlo painting not. Mm This is our answer for this


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