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0z2 (part Of 3) Iu.u pOints3.3 V2.3 V 8.7 V 3.8 0.3 $ WFind the current I1 in the 0.3 02 resistor at the bottomn of the circuit between the two power supplies. AnSw...

Question

0z2 (part Of 3) Iu.u pOints3.3 V2.3 V 8.7 V 3.8 0.3 $ WFind the current I1 in the 0.3 02 resistor at the bottomn of the circuit between the two power supplies. AnSwer in units of A023 (part 2 of 3) 10.0 points Deterrine 12 Answer in units of A024 (part 3 of 3) 10.0 points Deterrine I3. Answer in units of A.

0z2 (part Of 3) Iu.u pOints 3.3 V 2.3 V 8.7 V 3.8 0.3 $ W Find the current I1 in the 0.3 02 resistor at the bottomn of the circuit between the two power supplies. AnSwer in units of A 023 (part 2 of 3) 10.0 points Deterrine 12 Answer in units of A 024 (part 3 of 3) 10.0 points Deterrine I3. Answer in units of A.



Answers

In Figure $\mathrm{P} 18.64, R_{1}=0.100 \Omega$ $R_{2}=1.00 \Omega,$ and $R_{3}=10.0 \Omega.$ Find the equivalent resistance of the circuit and the current in each resistor when a $5.00 \mathrm{V}$ power supply is connected between (a) points $A$ and $B,$ (b) points $A$ and $C,$ and $(\mathrm{c})$ points $A$ and $D.$

There to nuke equation for the circuits are even minus. I won Obon minus I three R three physical studio and e minus. I don't ar minus. I three are three's equals zero. The junction rule equation is then Ivan is equals toe I took place. I treat This is the Junction Rule Equation Junction decoration to find the current through each branch with substitute by the junction rule equation into the Tokyo to new pick creation as following even it took was to Ivan are one place I minus I do are three physicals to video you do is close to I are to place. I want minus I to are three physical So zero you think given values off the distance and the e m f we can sold for Ivan and I do I went is equal to 0.144 and I do is equals to 0.139 And beer I had three is equals to Ivan minus I if it falls to therefore I trees equals to Ivan minus I to close to zero point Double 05 appeared No the potential difference across our three The potential difference across are three is we are three, which is close to 0.139 multiplied 20 is because 2.78 world

For this question about the question you want to find the unknown currents. The first that I can do is to look at loops that you've office small number off unknowns as possible. It's one of loops is over here. So in this looked as the only unknown there'll be involved. It's I fall. Okay, writing Now the jobs look rule. You start off with the battery moving from minus two. Positive. So we get that V two. So this is fight falls. Then we bypass are four in the same direction s to current, so we some tree away Deportation drop. So this tool times I fall every create this 20 so you can find I fought to be quite five MPs. All right. Next unit for other equations. To find the father unknowns, I went to high five. So, Defense Secretary, I'm gonna use T Junction Junction rules made ready. Incoming current must be close to the outgoing current. So, for your first junction, all the rights we have eye for the incoming current and your going will be I five and I treat for a second junction. I tree and I one incoming and I two is the only elk away current. The 30 question We're gonna use the different look, Rose. So if we can do you can look at is over here and for this loop, we start off with the best for you again. And so we are moving from positive to negative. So we got a minus away, V two. So that's minus five. Debbie. Bypass artery. Same direction. Nasty current. So minus Sometimes I tree very bypass are one in the opposite direction. So we plus quit is 20 The last equation Internet Yes, over here. This particular group the start off Tibet tree from minus to plus. So we at the fee one this shelf by plus ah, one witness full time. So for my one Demi bypass, I to which is also subject because it's in the same direction is the current maybe three times side too. Question zero now Too soft for this ik regent's from equation too. We're going to from equation to find ways I won, I want Yes, he goes to my two minus all right tree. We substitute that into both equation tree and four so in equation tree off the substituting in you get minus five minus to a tree, us four times off to my nose, for I treat close to zero. Simplifying debts gets minus five minus six tree plus for two because it was substituting debt into equation for my substituting the equation for I one into equation for get shelf minus for two plus for a tree. My next shii to west with zero get shelf plus four tree minus seven I to close to zero. We have two equations and toe unknowns. It's like yourself. So after substituting, uh, we adjusting the equation I left. We get our i to in terms off a tree and the from the equation on the right. All right. We can substitute the I two into question over here, so we get chop. Thus for a tree minus seven, four times six. Tree bus five, close toe zero. So this is the video expression full I tree and then we bring all the constants to the right hand side. So that's trough doing it. I tree to be close to 0.5 MPs From here, we can find any other values quite easy. I to using the above expression we can't two MPs. Then we can start you to into the equation for I one right over here, which is a goes to I to my nose. I tree should be a 1.5. Finally, we can't get five from the first equation. Jessica's toe I four minus. All right, treat. So this by fine minus my fire, which is two MPs s well, no to find a Pulis applied by the different what age is. We just have to multiply the current 50 voltage. So the current passing Trudy respective for teach We use that current to get power and poets goes to feed times I So the public or city Rotich one get few one times I to write nasty current housing. Truitt. So it'll be journey for what's for P two. The power for the second footage that is V two, which is five votes went Bye bye. I five i five is skipper nous to MPs so this will be 10 watts to find the power dissipated by the resistance. We already have t various currents. So we just have to use the current I square. Uh, my current square time. See resistance to get it power. So power for our first. The sister. Uh, one. We take high one square times the resistance off one first night. What's let me do the same thing for the other resistance, right? So I'm gonna do them directly for you. For our tree. The carbon this point finds a boy five square, perhaps two homes. What fight? What's for the current ISS? I for just 2.5 resistances too. You should get show my fight. What's

High in the given problem there is a combination, a multi loop circuit. The first group is having a resistance or one Is equal to 10 own. There is a battery providing a potential of we too Is equal to 9.00 world in this law. And one more resistor Having a resistance of our two Is equal to 20. Then there is another loop having a resistor Providing a resistance of our three is equal to 310 on and a battery providing the potential of We even Is equal to 15.0 vote. And this is the complete circuit representing multiple blows. Now we can name the injunctions, abc D E and F. No, the given currents in the circuit are here, this is Ivan moving towards right through Arman Then there is a current I two, moving again towards right through our two. And finally here this is I treat and interestingly that is also moving towards Right through our three All these three currents our meeting here at the junction E. I won I do And I three. So first of all using kill jobs. Yeah, junction rule at the junction E. We get Ivan last side two plus Atria has all the parents are Entering into the junction but none of the current is leading, so it's equal to zero or we can say equation for I treat is equal to -11 plus I two. We can market a situation number one. No, we will apply to your chops will teach law or loop through. So first of all using here it jobs loop rule in closed loop E B E F A. This upper loop let him be blue first. So in this loop, if we apply for jobs you cool. First of all it says the algebraic sum of potential drops. So the potential will be dropping in this loop at two places, Most of all this is Ivan are one And that is clockwise, so it will be taken as positive. But for I tuned to R2, that will be taking place counterclockwise. So it will be taken as a negative and battery. We too is sending its quarantine counter clockwise direction again. So it will also be taken as negative. And this job's lupul says just break. Some of potential drops means Ivan are one with positive is equal to, sorry, Ivan, carbon positive minus I too are too negative Is equal to -72. Now plugging in the non values it becomes 10, I've won the R one value of R one is 10, then I even minus 20 I took Is equal to -9. So we can market as equation number two. No, the same rule, absolute rule in loop, closed loop B c D E B. And in this closed loop The potential rob I think two or 3. Counterclockwise the potential drop I to into our two here it will be clockwise Battery providing Voltage V two clockwise. Berkeley providing voltage V. Even clockwise. So now using the same chops loophole here we get I two. R 2 minus side three. R three is equal to B two plus we won Or we can say plugging in all the known values. This is 22 minus 30 for our three and I three from equation number one this is minus I one plus I too is equal to 15 for we too. We even is nine. So rearranging the terms we get here 22 Plus 30 I one plus 30. I do physical to 24 or we get it to be 30 Ivan plus 50 I do is equal to 24. It is a question on Bird three. Now, equation number two, sales 10 I 1 -22 is equal to -9. So in order to solve these situations we multiply the situation number two By three. So if I multiply it by three I will get Mhm Here it will come out to be Turkey uh one -60 I two Is equal to -27. So finally, if I subtract these quick missions now, designers, here it is plus and here it is again plus. So canceling this, we get 110 I two is equal to 51. So in this way we get the value of its current I two which is 51 by 110 mp here and it comes out to be I two is equal to 0.46 ampere now using equation two again, which says then Ivan -22 and four. I do. This is 0.46 Is equal to -9. So solving this, we get the value of Ivan To be equal to 0.027 MP here. So these are the two currents. And finally Using the question # one, it's I three here will come out to me -1 means 0.027 plus item in 0.46 mps. Which comes out to be minus 0.49 mps. Now in the problem we have to find the power dissipated in various resistors. So first of all, barbara dissipated in our one is even is equal to Ivan square into our van. Yes, this is For I've and zero zero 2 7 square into urban. It is Then on. So finally this P one comes out to be 7.29 millie. What one of the answer then? Four resistance are too. The speed will be given by I two square into our two. Now, for I do this 0.46 ampere having a square in 2 20. So finally, the speed who comes out to be 4.23. What 2nd answer at last for R three P three will be equal to square over our square of I three into our three. Yes, this is 0.49 square in 2 30. And finally this power P three comes out to be seven point to vote the last answer with a given problem. Thank you.


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