High in the given problem there is a combination, a multi loop circuit. The first group is having a resistance or one Is equal to 10 own. There is a battery providing a potential of we too Is equal to 9.00 world in this law. And one more resistor Having a resistance of our two Is equal to 20. Then there is another loop having a resistor Providing a resistance of our three is equal to 310 on and a battery providing the potential of We even Is equal to 15.0 vote. And this is the complete circuit representing multiple blows. Now we can name the injunctions, abc D E and F. No, the given currents in the circuit are here, this is Ivan moving towards right through Arman Then there is a current I two, moving again towards right through our two. And finally here this is I treat and interestingly that is also moving towards Right through our three All these three currents our meeting here at the junction E. I won I do And I three. So first of all using kill jobs. Yeah, junction rule at the junction E. We get Ivan last side two plus Atria has all the parents are Entering into the junction but none of the current is leading, so it's equal to zero or we can say equation for I treat is equal to -11 plus I two. We can market a situation number one. No, we will apply to your chops will teach law or loop through. So first of all using here it jobs loop rule in closed loop E B E F A. This upper loop let him be blue first. So in this loop, if we apply for jobs you cool. First of all it says the algebraic sum of potential drops. So the potential will be dropping in this loop at two places, Most of all this is Ivan are one And that is clockwise, so it will be taken as positive. But for I tuned to R2, that will be taking place counterclockwise. So it will be taken as a negative and battery. We too is sending its quarantine counter clockwise direction again. So it will also be taken as negative. And this job's lupul says just break. Some of potential drops means Ivan are one with positive is equal to, sorry, Ivan, carbon positive minus I too are too negative Is equal to -72. Now plugging in the non values it becomes 10, I've won the R one value of R one is 10, then I even minus 20 I took Is equal to -9. So we can market as equation number two. No, the same rule, absolute rule in loop, closed loop B c D E B. And in this closed loop The potential rob I think two or 3. Counterclockwise the potential drop I to into our two here it will be clockwise Battery providing Voltage V two clockwise. Berkeley providing voltage V. Even clockwise. So now using the same chops loophole here we get I two. R 2 minus side three. R three is equal to B two plus we won Or we can say plugging in all the known values. This is 22 minus 30 for our three and I three from equation number one this is minus I one plus I too is equal to 15 for we too. We even is nine. So rearranging the terms we get here 22 Plus 30 I one plus 30. I do physical to 24 or we get it to be 30 Ivan plus 50 I do is equal to 24. It is a question on Bird three. Now, equation number two, sales 10 I 1 -22 is equal to -9. So in order to solve these situations we multiply the situation number two By three. So if I multiply it by three I will get Mhm Here it will come out to be Turkey uh one -60 I two Is equal to -27. So finally, if I subtract these quick missions now, designers, here it is plus and here it is again plus. So canceling this, we get 110 I two is equal to 51. So in this way we get the value of its current I two which is 51 by 110 mp here and it comes out to be I two is equal to 0.46 ampere now using equation two again, which says then Ivan -22 and four. I do. This is 0.46 Is equal to -9. So solving this, we get the value of Ivan To be equal to 0.027 MP here. So these are the two currents. And finally Using the question # one, it's I three here will come out to me -1 means 0.027 plus item in 0.46 mps. Which comes out to be minus 0.49 mps. Now in the problem we have to find the power dissipated in various resistors. So first of all, barbara dissipated in our one is even is equal to Ivan square into our van. Yes, this is For I've and zero zero 2 7 square into urban. It is Then on. So finally this P one comes out to be 7.29 millie. What one of the answer then? Four resistance are too. The speed will be given by I two square into our two. Now, for I do this 0.46 ampere having a square in 2 20. So finally, the speed who comes out to be 4.23. What 2nd answer at last for R three P three will be equal to square over our square of I three into our three. Yes, this is 0.49 square in 2 30. And finally this power P three comes out to be seven point to vote the last answer with a given problem. Thank you.