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What mass of HCl is required to produce 38 g ZnClz Zn + 2 HCIZnClz ` + HzYour answer should have two significant figuresProvide your answer below:FEEDBACKMORE INSTR...

Question

What mass of HCl is required to produce 38 g ZnClz Zn + 2 HCIZnClz ` + HzYour answer should have two significant figuresProvide your answer below:FEEDBACKMORE INSTRUC

What mass of HCl is required to produce 38 g ZnClz Zn + 2 HCI ZnClz ` + Hz Your answer should have two significant figures Provide your answer below: FEEDBACK MORE INSTRUC



Answers

What mass of HCl, in grams, is required to react with $0.750 \mathrm{g}$ of $\mathrm{Al}(\mathrm{OH})_{3} ?$ What mass of water, in grams, is produced? $\mathrm{Al}(\mathrm{OH})_{3}(\mathrm{s})+3 \mathrm{HCl}(\mathrm{aq}) \longrightarrow \mathrm{AlCl}_{3}(\mathrm{aq})+3 \mathrm{H}_{2} \mathrm{O}(\ell)$

Hi everyone. So in this question they asked that is what mass of it said it's containing 45 ml of a quest solution that has a density of 1.19 grand per cm cube contains 37.21% of its sell by mass. So we're renting given later given massa pits seal mass of its seal. Question mark. Then what do you mean? What do you find your mallet? The next Man City one Point 19 Gramp Rcm Q. The next one. New. Mhm percentage of its cl Martines. 37.2% means 37.2 Grand present in the program. Now, therefore, mass offered seal. That is a call to volume of itself 45 Into Rinse it up. It's 1.19 dream of solution solution divided by a male up solution solution into 37.2 g outfits. CNN Divided by 100 g of Solution. Listen, And that is equal to 19 points 9206 grand. And therefore, Mhm Massage bed seal containing 45 ml, Bad four my sockets. Moss of Let's see it contained. Yeah, in 45 Year mel. Yeah, I agree. Yes, it's here. Marty is equal 19.9206 Grands.

We can use the mass percentage formula to figure out the mass of a particular compound in a certain solution, given its density. And so if our solution is 45 mL and we're looking at hydrogen hydrochloric acid, which has a density of 1.19 grams per centimeters cubed or grams per milliliter and we know that there is 37.21% of that HCL, we can convert 37.21 percent to 37.21 g per 100 g. We keep that ratio the same, multiply these two numbers and then divide by 100 to get 19.9 3 g of H. C. L.

In this problem were asked to find how many grams of hydrochloric acid are consumed in the reaction of 425 grams of a mixture containing 35.2% magnesium carbonate and 64.8% magnesium hydroxide by mass. This problem involves two chemical reactions. We can start this problem by finding the amount of hydrochloric acid that will react with both of the species. We were told in the problem statement the percent by mass of the 425 grams of each of these substances so we can multiply our total sample, wait by the percentage by mass of each of our individual species. So we find that we have 275.4 grams of our magnesium hydroxide, and we have 149.6 grams of our magnesium carbonate so we can go ahead and solve for the amount of moles of hydro Clark asset that need to react with this amount off. Both are magnesium hydroxide and magnesium carbonate, and then we'll go ahead and add those moles together to find the total moles of hydrochloric acid required. We can start with her magnesium hydroxide here and divide by the molar mass to get it in terms of moles of our magnesium hydroxide. And we have strike yama tree from our first chemical reaction shown above. So we know that for one mole of our magnesium hydroxide, we require two moles of our hydrochloric acid. So we find from our first reaction that we need 9.44 moles of hydrochloric acid. We can repeat the same steps with her magnesium carbonate. So we divide by the molar mass to get it in two moles of our magnesium carbonate. And we can use the Stoke Yama tree provided in the second chemical reaction. And we see that for one mole of our magnesium carbonate, we require two moles of hydrochloric acid. So for our second reaction, we require 3.55 moles Hardcore kassid. When we add these numbers up, we find that 12.99 moles of hydrochloric acid are required total. In these two reactions, we confined our total grams of hcl required by multiplying by the molar mass. So the total grams of hydrochloric acid required is equal to 473

Here were asked to consider the reaction of solid zinc with excess HCL reacting to form zinc chloride and H two gas. These in chloride and the HDL er a quiz. And so we're told that we result with 0.1 to 5 leaders of age to gas at STP. And so that's another way saying we have it at temperature to 73 Kelvin and a pressure of equal to equal to one atmosphere. And so we're basically asked how many moles of zinc did we start with for this to be the result? And so we need to figure out the moles of hydrogen gas that we have and because we have a 1 to 1 more ratio Haijun to sink, we're going to get the number of moles is sick when we should figure out from there the masses think that was reacting. So we're gonna use the ideal gas law solving for the number of moles. So an equals P V over our tea. I'm just gonna plug in the values that we have here. So the pressure we have one atmosphere would ignore the units for now 0.1 to 5 leaders over 0.8 to 1 as our gas constant and to 73 kelvin as our temperature. And so then the number of moves that we're going to get he's going to be equal to 5.57 times tense, a negative third malls of age to which is also able to the Moores of sick because we have a one so one ratio. And so since we have now the most of zinc, or ask to find the mask, we just need to multiply this number right here by the molecular weight of sink, which is 65.38 grams per mole. The moles will cancel out, and we're gonna get a final Masses Inc as 0.36 or grabs.


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