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EvaluateF dr where F (42, Y, 2x) , and C is given by 7(t) (t,sin(t) , cos(t)) , 0 < t < TQuestion Help:VideoSubmit Question...

Question

EvaluateF dr where F (42, Y, 2x) , and C is given by 7(t) (t,sin(t) , cos(t)) , 0 < t < TQuestion Help:VideoSubmit Question

Evaluate F dr where F (42, Y, 2x) , and C is given by 7(t) (t,sin(t) , cos(t)) , 0 < t < T Question Help: Video Submit Question



Answers

Evaluate the given fimctions. $$f(T)=7.2-2.5|T| ; \text { find } f(2.6) \text { and } f(-4)$$

So for number 12 were asked to find the greatest imager, Um, as our plug in from the 4.2. So our focus is the 4.2, and then we just look and see what is the next? The next imager that is right below 4.2. And that would be 44 is the greatest, uh, or largest imager that is less than or equal to the 4.2 that comes up.

Problem were given a function f of tea. It's just secret. A T squared plus one about about T minus two. Okay, there wants us to evaluate that function when t is equal to three. Once he is equal to negative one and when t is equal to zero. Okay, to do that, we just played visit Is our input. Yes, everyone. C a t. We're just gonna replace it with a three for the first ones. Three squared, plus one to bed. About three minus two three squared. Plus one is 10 three minus two is one 10. Everyone is just 10. You get a negative one. We're gonna have negative one squared plus one divided by a negative. Going minus two. The negative one squared is positive. 11 plus one is two negative. One minus two is negative. Serene, uh, says doesn't really simplify, but we can rewrite. It is negative to over three. Looking at zero, we're gonna have zero square last one. All right, the better buzz. Europe minus two. And that's simply gonna be negative whenever, too. Okay. Thank you very much.

Okay, so this problem gives us the function effort. T equals the square root of to t plus five him. And it wants us to evaluate the function at three points when t is equal to three. Once he is equal to negative one. And when t is equal to zero. Okay, to do that, we just plug it plugged those values in for tea, and two comes three. That's fine. Which is 11. Since this gives a spirit of 11 I'm playing a negative one. We're gonna have two times negative one plus fire, which is just equal to three. Final answer is just the square of the three and plug it in zero. We're gonna have to time zero. That's fine, which is just by. And that's the spirit of five. Okay, that's all. Thank you very much.

No. In this problem, they give us a function of t is a function team ever. T is the square root of three t plus four. It wants us to evaluate f of three. That's a negative one and f of zero. Okay. No, did that. We're just gonna plug in those values. So the input for the 1st 1 is three. There's compete in three for team during the three times three, uh, three times three is nine plus forwards. 13. So this is just the square of 13 for the 2nd 1 Republican and negative one three times negative. One must borders. Negative. Three plus four is positive. One in the square root of one is just one and plug it in zero. We're gonna have the square root of three tons zero plus four, which is just the square it for, uh, which is to Okay, Thank you very much.


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