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Roll a weighted (unfair) six sided die The probabilities of getting a 1.2,3, or 4 are all the same. Getting 5 is twice as likely as getting 3 4. Getting 3 6 is tw...

Question

Roll a weighted (unfair) six sided die The probabilities of getting a 1.2,3, or 4 are all the same. Getting 5 is twice as likely as getting 3 4. Getting 3 6 is twice as likely as getting a 5. What is the probability of getting 3201/8None of these~1/2~1716~1/101/32~1/2023/8

roll a weighted (unfair) six sided die The probabilities of getting a 1.2,3, or 4 are all the same. Getting 5 is twice as likely as getting 3 4. Getting 3 6 is twice as likely as getting a 5. What is the probability of getting 32 01/8 None of these ~1/2 ~1716 ~1/10 1/32 ~1/20 23/8



Answers

What is the probability of rolling a 6 on two consecutive rolls of a fair six-sided die?

All right. So in this question I have to find the probability of rolling a die five times and obtaining six on the first two rolls five on the third role and 123 or four in the last two rules. Okay, so I'm rolling a die five times. So what is the total number of outcomes It is going to be success to five right five times. 1, 2, 3, 4, 5. There are six possible outcomes for all five times 665 with the total. So this is my denominator. Now what is going to be my numerator? I want six on the first rules. Right? So there is only one possible outcome that can fill these two. Then I want five on the third road, five on the third role and I want 123 or four of the last two rules which means I have four possible outcomes over here. So I'm going to apply all of these. These are my favourable cases. So this is going to be 54 20 to 4 80. So this is 80 by 88.63-5 80, divided by six. This is going to give me 0.102 So my probability comes out to be 0.10288 Or I can write this s 0.0103. This is my answer.

Here in this problem, the sample space for random experiment. Under the study, let it be s is given by 123456 This is the value of s now P one can be calculated by this formula number of favorable cases which is given age one by total number of exhaustive cases which is given us six. No, I'm just writing the value of p four so the value of the food can be given edge be four ones can be given. Add one by six Multiplication one by six I am just writing it here B four ones Multiplication one by six Multiplication one by six Now going forward and solving it further. So I get the value. Age one by 1296 So probability of obtaining 41 seen a rou when ruling a fair six side die each one by 1 to 96 This is our answer

Okay, We have a fair six sided die. Then the possible outcomes are the numbers. 12345 and six. And the numbers that are even are 24 and six. So there are three possible outcomes that are even out of six possible outcomes. And so the probability of rolling an even number is 3/6 which reduces to 1/2.

We went to find the probability of each outcome when it buys two diets world. So let's that p of one equal text where p of one is a probability that we will roll and get one. We know that one is equally likely to appear as 35 and six. So X is equal to p of one, which is equal. Scipio three, which is You go to Pier far and which does he go to p of six. We also know Tour three is three times more likely to occur than each of the other outcomes. So Pee two or four is equal to you two plus beauty for since get rolling a tour ruling force independent from each other. And that's equal to three times p of one. Let's p 03 less Pierre fired last p 06 Since this is three times more likely to happen that either of these outcomes and that is equal to three times four X since each of these is equal to X and therefore it's able to 12 weeks and we know that p of two is equally likely is PIA for therefore p of two plus p 04 equals 12 x is the same SP of two plus p of two equals 12 x soapy of two musical to PIA, for which is equal six x. Therefore, the total probability must be equal to one so p m form and that's equal to P upon plus Pierre too, it must be. All three was Pew for Plus View five does p of six, and that's equal to four X plus 12 eggs equals one because you have P ps two plus before which is able to 12 eggs and then we have p of 13 or four people. Five of you have sex with your ex each. Therefore, we have 16 accidents along so X is equal to one over 16. Therefore, the probability that will grow 135 or six is equal to one over 16 and the probability that will roll a tour a tour for is equal to six times six time for number 16 which is three over eight


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