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###### Using Ea + Sx) dx lim (1 + Sx;) Ax, we have lim (1 + 5(-2 a))r = lim 42 Eg]I2o]20|Step 4Now,lim42(-9 204) lim Ax -9 22]But20i20 ~9 +andtep

Using Ea + Sx) dx lim (1 + Sx;) Ax, we have lim (1 + 5(-2 a))r = lim 42 Eg] I2o] 20| Step 4 Now, lim 42(-9 204) lim Ax -9 22] But 20i 20 ~9 + and tep

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