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2#ytlytett Aicdthe general Soltlaa pa [ddant equatloo3444++3444244 Fiod He Igenc Sol HBc AHe?X HPfet 2h YA4 equeHon...

Question

2#ytlytett Aicdthe general Soltlaa pa [ddant equatloo3444++3444244 Fiod He Igenc Sol HBc AHe?X HPfet 2h YA4 equeHon

2#ytlytett Aicdthe general Soltlaa pa [ddant equatloo 3444++3444244 Fiod He Igenc Sol HBc AHe?X HPfet 2h YA4 equeHon



Answers

$\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CONH}_{2} \longrightarrow \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{NH}_{2}$ Here $(\mathrm{X})$ is (a) $\mathrm{Ni} / \mathrm{H}_{2}$ (b) LiAlH $_{4}$ (c) Zn (d) $\mathrm{Pt} / \mathrm{H}_{2}$

Dark Hussein is white phosphorus and reaction with see A. We're told to ems we have wide fast for us. Yes. Yeah. Which will too So this upon reaction will give This will give p three less. Yeah, that's too you're too All too. So this is the product of this reaction. So let us set the options so we see option B and option here, correct and speaking rate of sin the and option the uh that answer.

In this problem, I can write the reaction age see http CH two CH two in by agents of in or C two at five poultry C two H 50 N A will give the compound ad see http CH two C o siete. See http C o C two H 5. Therefore, according to the option, option a option age correct and said of some aid, correct. Answer for this problem, I hope you understand the solution.

In this problem, I can write the reaction edge. Just look at it carefully. H n 02 when react with H two, S. 03 as well as as to it will give the product ID as to and so forth. Plus and H 20 H and H 20 pad. So he had in this problem the compound A. Is equal to n H 20 H. Therefore, according to the option obstinacy. It correct and said for this problem, I hope you understand the solution of this problem.

In this problem I can write the reaction and CST CH two managed to in perchance of action or two 0-5° integrate will give this compound CS three CH 20 H. And this component to denso. PBL three will give CST CH two beyond and this compound in pageants of GCN we'll give CST CH two M. C. And this component presence of AL I am at full well finally give CST CH two NHCS three. This is compounded by this is component so according to the option, option C it correct here, option siege, correct answer.


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