Once again. Welcome to new problem. This time we have one arm, Uh, that's holding on to a short boot. So these are these are, like fingers right here. Um, you know, just having an unlike that. And it's it's holding onto a short boot. Um, the arm itself, the short put itself is right here. So the mass, uh, of the moss off the short route happens to be given us, um, 77.3 kilograms. So that's that's the, um, the mask off the short for 7.3 kilograms. And then there are the piece of information that we're given is that he's a specific distance, This one right here. The distance between the elbow on the extensive in that distance are gonna call it, um d equals two small, the equals to two point five centimeters. Also, we're supposed to find, So this is the information was given. Uh, we're also given that the entire distance from this point up until the center off the short poot is early centimeters, the distances in centimeters Onda. We do see that the law um, this law I'm right. D'oh! I'm gonna call it M l Mass Law uh, has, um, us off 2.3 kilograms with the center of gravity. So this distance right here, that's the center of gravity. And up until there, that's 12 centimeters. This 12 is 12 centimeters, because that's the information that's given. Um, that's from the elbow. So was saying from the elbow, right here it's 12 centimeters. That's the distance. Our purpose is to find this force f m that holds on to the ball itself. Such that the ball doesn't get doesn't fall off. It's it's holding not the ball, but the short route. That's that's what's going on with this problem eso was supposed to find we want to find but force Mmm f m. You know, that's that's what we want to find. So that's the information we were given. Well, gonna use equilibrium and according to our equilibrium will get to see that this sum of all the forces on it's gonna be equals to zero. And also the some off all the talk about the elbow eyes also gonna be equivalent to zero. So gonna use talk and we'll interested in the talk around the elbow festival. Ah, we take the the mass the mass off the law firm. Uh, times 12 centimeters, actually. The weight, the weight off the law arm, remember, talk talk is defined us the perpendicular distance, times the force. This is the force. So we have to change all of these two weights a male G. So this would be m l G times 12 centimeters plus the must off the short poop, which is, um M s G ah, this time it's not 12 centimeters, but it's gonna be 30 centimeters, 30 centimeters, because you can see from the short boot up until the elbow right there. That whole distance is his 30 centimeters. And then, ah, all of that is you know, all this one is pushing down, and the lower arm is also pushing down. Uh, so this is clockwise is positive, But this force the one we're looking for, uh, counterclockwise is gonna be negative. And so in this problem, we have to subtract the talk you to that. So f m times the small distance D that sam is gonna be equivalent to zero. Okay, It's gonna be equivalent to zero. So in the next page next page, we simplify the problem. We have if enemy close to go back M l g 12 centimeters m l g tall centimeters, then, uh, plus em, um, m s plus m s g 30 centimeters. But remember, ml is the muss off the law, Um, and M iss is the must Oh, the short put. And in this case we're using, we're using talk to solve this problem, and then we want to divide by, you know, the small Dee Dee Dee's this distance right here, the distance between the elbow under under force itself. You know, this is the gap. So we wanna have this distance right here and fucked. Uh, assuming was fuming this elbow, it's gonna be right here. This is this is no assumption, right? Here is our elbow. But then there's a gap right there in that distance. Gap is 2.5 centimeters, and so the next step would be to plug in the numbers responsible for this problem. So 2.3 kilograms times nine points, eight me. This second squared times 12 centimeters plus. Remember? You know, you can change the centimeters two majors by doing that one meter, 100 centimeters. Uh, which gives you zero point 12 meters. Or you can leave it like that because of centimeters they're gonna cancel out. So mass off, uh, s is a mass of the shot 47.3 kilograms and multiply that by nine point h meet his second squared. And then you multiply that but 30 centimeters and divide everything by, uh, 2.5, but centimeters, So this sentimental will cancel that one and that one. So we just left with, uh, the product of a kilogram and meet it the second squared. And remember, one newton is equivalent to one kilogram up. Made a meet up one kilogram. He does, uh, one kilogram. Um, meat is per second squared. That's one mutant. So the problem is being transformed right away into Newton's, and that becomes approximately 900 70 mutants. So I hope you enjoy the problem again. It was, uh, on, um, at a law firm and an upper arm holding a short boat. And we used to talk because of some of the talk around the elbow right here is gonna be zero. So we define the talk as a result off the the law, um, and then sum it up with the talk off the shot put. Both of these are positive. And the reason why the positive is because it's choice clockwise would be positive. And then the force that we're looking for would have Ah, uh uh counterclockwise. And so it's negative. And then we end up simplifying the problem. Using our bro, we end up having 970 mutants, so I hope you enjoy the problem and have a wonderful day. Okay, thanks. Bye. You can send any questions or comments walking by.