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Delctnning HalosDalvanc €uioson19 1 11AnOacaeunaler Caten Fol_ulionCURRENT OENSITY (LAct1 FICURE 6.17 Polenlostric Folanzation CuIvc; ior vatous Meja 3 an alo...

Question

Delctnning HalosDalvanc €uioson19 1 11AnOacaeunaler Caten Fol_ulionCURRENT OENSITY (LAct1 FICURE 6.17 Polenlostric Folanzation CuIvc; ior vatous Meja 3 an aloys lcr Drocicnoc gakvanic Corrosict1 Jeraled 3*9 NaCL (From Bonnot and Greere_)

Delctnning Halos Dalvanc €uioson 1 9 1 1 1 AnOacaeunaler Caten Fol_ulion CURRENT OENSITY (LAct1 FICURE 6.17 Polenlostric Folanzation CuIvc; ior vatous Meja 3 an aloys lcr Drocicnoc gakvanic Corrosict1 Jeraled 3*9 NaCL (From Bonnot and Greere_)



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Calomel is made by treatitrg (a) $1 \mathrm{lg} \mathrm{SO}_{4}$ with $\mathrm{NaCl}$ (b) $\mathrm{l} \mathrm{lg}_{2}\left(\mathrm{NO}_{3}\right)_{2}$ and $\mathrm{l} \mathrm{g}$ wirh aqua rcgia (c) $\mathrm{l} \mathrm{Ig}_{2}\left(\mathrm{NO}_{3}\right)_{2}$ wirh $\mathrm{l} \mathrm{ICl}$ (d) $\mathrm{Hg}\left(\mathrm{NO}_{3}\right)_{2}$ with $\mathrm{NaCl}$

In this problem, I'm writing the reaction. Just look at it carefully. Any energy for at be your ford four H two will react to form any and at four at people for plus four as to and and ME energy for add bill for will react to form and the beauty plus an STD plus as to So according to the option. In this problem option. See each correct. Was there not that we have any Beauty which reacts with metallic oxide to give colored or to post fails.

Hello students welcome back and this question we are given the connectivity of NSL to be equal to 1 26.4 Okay and similarly we are given linda nod for a tear To be equal to 425 .9 And we are given Linda not for any at sea to be equal to sorry it's at sea and they accede to be equal to To be equal to 4 25.9 4.25.9. Okay so these are the given. Sorry I'm sorry this is any easy. Okay see the compound this is N A A C And it is given to be 91 91. Okay so I'm giving these values and I have to find out Linda not four HAC. Okay so if I just break London or for any H H A C. So what do I get is I will be needing the London or for each place and the London or for a C minus. Right so if I get these two values I'll read the London or poor H A C. Okay so for that I am given some conditions so I'll find out this way these two values from here. So if I just break it okay if I just break these values what do I get is and they can not offer any plus and linda northward C l minus. Okay and this will be equal to lend an out of edge place let's land another sale minus and this will be quick to learn a lot of Annapolis in London order? Yes you like this. Okay so you can clearly see that if I if I just add these two equations, if I just add this situation and the situation I'll get lambda edge place and linda easy. And then I have to subject this situation. I have to subtract the situation. So if I'll subtract this equation this will cancel the sale minus and this will cancel this a necklace. Right so I can write that Lebanon not for H. A. C. Will be equal to linda North for N. A. C. Plus lambda North for at C. L minus the London or food Anisha. Okay because this any will cancel this any and the cl will cancel the sale and we will be left with a C. N. H. Okay so putting these values, what do I get is 4 25 point night plus 91 -126 1 26.4. So if I was calculated it comes out to be 3 90 white fight centimeter square Farmall. Okay so this is the value of London order H. S. Okay so that's it. Thank you

In this problem, I can write the reaction edge. Just look at it carefully. Any to Jad plus MG two minus will react to form to any plus plus M D J. Also the second reaction age, Any to Jihad plus C A two plus Here it is. Plus will react to form to any Plus plus. See A JED. So according to the options Option eight character here, Option Age got again. Said for this problem, I hope you understand the direction of this problem.

Hello and welcome to this video solution of enumerate. So here we are given the interoceanic distance of K. & C. Alliance in the Crystalline Case. Ellis 3.14 Armstrong. The screening constant is given us 10.87 both Dan's. Now you to calculate the radius of the potassium. So let me show you how this can be done. So first of all the screening constant is given. Right. So first we will write down the expression of the radius for the potassium iron and our key will be equal to. So this is inversely proportional to the effective nuclear charge. Right? So let's say we have some constancy and we take it Uh atomic number of protection. That is 19- the screening constant, which is 10.87 given. Right? So you have here see over 8.13 X. Similarly for clothing, let's consider C effectively charge which is actually same As that of potassium. So here we have 17 that will make a number of chlorine and minus screening constant, which is 18.87 in both cases. Right, so see over 6.13 We're having Now here we have to take the uh the ratio of RK over RC seal that is actually inversely proportional to the ah yes, this is impossible shots were taken. So we just right here we will have if you take the ready ratio of it, You will have here 6.13 over 8.13 rate. Yeah. Great. And now we can right Hark A plus R. C. Hell which is equal to 3.1 Food. That is given right? It is given this is equal to see over 8.13 Plus c. over 6.13. Now we can to calculate the radios of the potassium my own, we can apply this RK over RK plus R. C. And Alright this is equal to R. K. Is See over a 21 3. And here we'll have so let me write it directly. So here we will have one x 8.1 13 over one x 8.13. Just a moment. Yeah three Plus one x 6.13. Great. And now we have our key Equal to you calculated and our Cumulus Arsenal has already given us 3.148. So if you take it and you will get arc equalled approximately called 1.35 Armstrong. Right, so the option correct option is C. In this case. Right. I hope this is clear to you and have a very good rest of the day.


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