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Aucmg-s Ieizcheck my wortDamCalculate Ibe hydroxide Won conceutrations 0f (he following colulluns 259€ . given the pOH: pOH[OH(Entci odt AMTeI#CCnc nolation )...

Question

Aucmg-s Ieizcheck my wortDamCalculate Ibe hydroxide Won conceutrations 0f (he following colulluns 259€ . given the pOH: pOH[OH(Entci odt AMTeI#CCnc nolation )(b) pOHLonPrev18 cf 27NextBAL

aucmg-s Ieiz check my wort Dam Calculate Ibe hydroxide Won conceutrations 0f (he following colulluns 259€ . given the pOH: pOH [OH (Entci odt AMTeI #CCnc nolation ) (b) pOH Lon Prev 18 cf 27 Next BAL



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Calculate the pOH and pH of the following aqueous solutions at $25^{\circ} \mathrm{C}:\left(\text { a) } 1.24 M \mathrm{LiOH}, \text { (b) } 0.22 \mathrm{M} \mathrm{Ba}(\mathrm{OH})_{2},(\mathrm{c}) 0.085 \mathrm{M} \mathrm{NaOH}\right.$

In this question that consisting off story Barthes offers bar that separation off high drop sign is similar to the concentration off the strong, based off only one way. So it will be over Boeing 66 Mohler So now we can calculate the value off B O. H, which equal negative logs a concentration off the A wage so it will be one going Togami and so the value off pH will be 40 negative the value off P o edge. So it will be 12 going the A to similarly in the B. The concentration off H negative is equals a concentration off a strong bees off Mona or H negative. So it will be 5.43 muller. And so the value off the people edge will be negative logs a concentration. So it will be all Boeing 73 And so the value off BH, which equal 14 negative the value off people which so it will be 13 points to seven that last one. See, here's a concentration off. All H negative will be equal the concentration off the strong bees. Oh, Boeing 74 times by two. Because each strong days containing toe moon off hydroxide. So the concentration off upside total will be one point for a muehler. So now the value off the O. H will be negative logs of concentration. So it will be lowballing 17 and finally is a value off. Be. Age will be equal certain going a three. Thank you.

Yeah in this question were given the ph values and we need to find concentration of H minus to find the B wage from the concentration of a wage. Used to find the long of the concentration and now to do the reverse of this, we're going to find the inverse log. So first we are going to see what the negative of B O H is, It's going to be negative seven and then we are going to find the in worst log And when we put it into calculator, then this long is going to be 10 to native seven which can also be written as 1.0 I am stand to the negative seven and M which is small spur leader which is the unit of the concentration. Here we are again going to first convert it into a negative sign, -12.91. And then by taking the inwards log Which is 10 to the negative 12.91, I'm going to get 1.2 Times 10 to the -13. Yeah. For the third part, I'm again going to find negative of this number and then I'm going to find that in words log which is 10 to the -1.82. This is coming out to be 1.5 Times 10 to the negative to him. For the final part we're going to find it in words log off negative nine .41. Would you stand to the negative 9.41 And this is going to be 3.9 Time stand to the -10 M.

We're to calculate the pH and PCO Which of the following solutions For a We have a similarity of any Ohh equal to zero point 0450 Moeller o H minus would be 0.450 Moeller chocolate a p o. H. This is equal at 1.3 for seven before ph would be 14 minus 1.347 which will be equal to 12.653 For be similarity of calcium hydroxide equal 2.160 Moeller 1 to 2 more ratio so hydroxide would be equal the 20.3 to 0 Mueller p which negative log when 3 to 0, which is equal the 0.49 0.495 ph people of 14 minus 140.495 which is equal to 13 0.505 apart. See, we have a 1 to 1 mixture of similarity. Vizio Windsor 1 to 5 Mueller and any which also you got the 0.125 Mueller learn the well is the 1 to 1 mixture. Similarity of each through a plus is he called a 0.125 similarity of O H minus is equal to 0.125 When we mix these two together, there's complete neutralization on Oh, sorry. This is calcium hydroxide. Let's make a change here. This is going to be calcium hydroxide. Therefore, the similarity here would be 0.0 to 50 Moeller two moles of hydroxide per one mole of calcium hydroxide. We have O H minus present in excess by points or 125 Moeller comes over the P U H in the same equal to 1.903 and therefore my Ph would be equal to 14 minus 1.903 Which of equal the 12.97 for Deke. We've got a 2 to 3 mixture. Uh, we've got a channel three, which is equal to you. Put 25 miller 250.0, uh, $25. And we've got a witch, which is equal to also 0.125 And we've got a 2 to 3 ratio, uh, in the mixture, um, clarity of each 30 plus is equal the 0.0 to 50 Mueller Larry O H minus is 0.375 Mueller Uh, minus is larger than if we have always minus in excess when this neutralizes 0.375 Mueller minus 10 to 50 Mueller vehicle that 500.125 Mueller P a witch Negative log 0.125 which is a with a 1.903 therefore a pH. It's 14 minus 1.903 to yield UH Ph of 12.97

This is Chapter 18 Question 28. So it's looking for the pH and the P O. H. For there is different concentrations of proton and hydroxide. So for part A, it tells us that our hydroxide concentration is equal to, um oh 3.3 times tending to your fifth, which then allows us to find the p. O. H. Because we can say that the P. O. H. Is equal to the negative log of the O. H minus concentration, which is just the native log of 3.3 times tender. Then I get 1/5 which is equal to 4.48 too significant to decimal places in the p. O. H. Because you have two significant figures in your concentration, which then means that the pH is equal to, um, there was all of this equation, which is 14 is equal the pH plus the p O. H. So you kind of P H is equal to 14 minus the P O. H. So 14 minus four point for eight is equal to 9.52 So there's your P O. H. Andrew Ph again two decimal places because there's two significant figures in the initial ah question. So for Part B would do the same procedure except in reverse. So for Part B, it tells you that the proton concentration is equal in nine point five times, 10 to the negative third. So at this point, we just say that the pH is equal to the negative log of 9.5 times 10 to the negative third cause it's just equal that make a log of the proton concentration, which would give you 2.0, too, and two decimal places. Because there's two significant figures, then we know that it's 14 is equal to the pH Plus the p ohh, which will give you the P O. H. Is equal to 14 minus two ph or 14 minus 2.0, too, which is equal to 11.98 two decimal places because you two significant figures to start


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