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Lo @cu clstan ( Versus time for 4 particle is shoun in Fig. Find the average velocity the time intervals of: a) The position [0.1Js ; b) [13]s c) (2,6]s. Also find ...

Question

Lo @cu clstan ( Versus time for 4 particle is shoun in Fig. Find the average velocity the time intervals of: a) The position [0.1Js ; b) [13]s c) (2,6]s. Also find instantancous Yelocity at FSs.x(m)Fig:

Lo @cu clstan ( Versus time for 4 particle is shoun in Fig. Find the average velocity the time intervals of: a) The position [0.1Js ; b) [13]s c) (2,6]s. Also find instantancous Yelocity at FSs. x(m) Fig:



Answers

The position versus time for a certain particle moving along the $x$ axis is shown in Figure P2.3. Find the average velocity in the time intervals (a) 0 to $2 \mathrm{s},$ (b) 0 to $4 \mathrm{s}$ (c) 2 s to 4 s, (d) 4 s to 7 s, (e) 0 to 8 s. (FIGURE CANT COPY)

All right. Where were we has to compute the average velocity for a particle given, given certain positions and the part of certain initial position. Certain frontal, bosom and time interval. So the particle For the first question, Christian A. The initial position in the position of the particle is equals zero and Article two seconds. So tickles here. The particle initial position is zero meters from the origin. The final position. It's a 10 meters and the time interval is two seconds before according to the definition of the average velocity in one dimension, which is the change in position, many brother. With the change in time, we have 10 meters overs over to sickens or five meters per second. For the next question, we were asked to to answer to compute the average velocity for from seconds to four seconds. And for this case, the display Zeman his is the 40 meters and the change in time is four seconds. Therefore, the average velocity is for four meters per second or 1.25 meters per second. For the next question, we want to compute the average velocity between two seconds and t equals four seconds. So the initial position articles two seconds is 10 meters. The final position is five meters for the average velocity is for I understand meters over for minus two seconds and this is equal to negative 2.5 meters per second. The next question is to compute the average velocity between equals four seconds. Antique rose three seconds before writing a lot. About the change in time is three seconds in the change in position is and is six meters minus five meters, which is negative 11 meters afforded the average velocity and wonder Benjamin you seek will do minus 11/3 meters per second which is equal to miners three. 23 3 meters in the next. The next question is this is e think the previous one was was from member stick it Yeah, the Reza When you resist De and then the next one is he for this one? We want to compute the average velocity between tickle zero Zerg on anti equals eight seconds. You cannot as a a T equals zero The position the initial position Physical zero an A T eagles a second The final position secret zero zero meters zero meters for average velocity is zero because the change in the displacement is there. The average there is velocity is your

For this problem over need to do is use the definition of the average velocity as it is the ratio of the change of the display. It's been over the change in time and redivided from the graph. The first question was there was velocity from zero certainty two seconds from 0 to 2 seconds. The displacement is 10 minus zero meters, so the average velocity is five meters per second for being we're supposed to compute the average velocity between the times off equals zero and equals four seconds. This place money's fine money zero meters or were for China zero circles. And this comes out to me more important to five meters per second for C. The average velocity is supposed to be computer within four within two and four seconds. So there is never We'll also is this bluesman over the Delta T And this comes some theories. About 2.5 There's Persik, um, and for the you want to know between the times are four and seven seconds and the displacement is five minutes five meters. But as I said, when it's four seconds or minus 10/3 years per second, which is a good. 23.3 years per second. Okay, Bonus. 3.3 meters per second. And then the last question E once is to compute the average velocity between t equals zero and equals eight seconds. This, please. 10 and the changing times a second. So there was a teaser.

Yeah, discussion covers the concept of the average velocity and the average velocity is the total displacement upon the total time. For a It is from T equals 02 two seconds. The average velocity equals that displacement is two seconds. That is 10 m. Okay, Upon the time, that is two seconds. So the average velocity equals five m for a second. Okay, now, for part B, the Average velocity during takeoff, 02, four seconds equals the displacement. That is five m upon the time. That is four seconds Are the average velocity equals 1.25 m for a second. For C. That is the regular city, but 20 equals two seconds. 2 4 seconds. Okay, the average velocity equals the displacement. And that is uh define the specimen is five. Okay. And the initial displacement poisonous 10 m upon the time, that is two seconds. So the average velocity equals -2.5 m for a second. Now, in deep part, the rest velocity uh in two equals 4 to 7 seconds equals the displacement. That is the minus uh There is a final position, Minister initial position that is minus four minus five m Upon the time. That is three seconds Are the average velocity during this inter world is -3 m/s. For part B. The average velocity during the whole trip is The total displacement. That is the final position. Minister initial position and that is zero m upon the time. That is eight seconds Are the average velocity equals 0m for a second.


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